Throw an error preventing a table update in a MySQL trigger

MysqlDatabaseTriggers

Mysql Problem Overview


If I have a trigger before the update on a table, how can I throw an error that prevents the update on that table?

Mysql Solutions


Solution 1 - Mysql

As of MySQL 5.5, you can use the SIGNAL syntax to throw an exception:

signal sqlstate '45000' set message_text = 'My Error Message';

State 45000 is a generic state representing "unhandled user-defined exception".


Here is a more complete example of the approach:

delimiter //
use test//
create table trigger_test
(
    id int not null
)//
drop trigger if exists trg_trigger_test_ins //
create trigger trg_trigger_test_ins before insert on trigger_test
for each row
begin
    declare msg varchar(128);
    if new.id < 0 then
        set msg = concat('MyTriggerError: Trying to insert a negative value in trigger_test: ', cast(new.id as char));
        signal sqlstate '45000' set message_text = msg;
    end if;
end
//

delimiter ;
-- run the following as seperate statements:
insert into trigger_test values (1), (-1), (2); -- everything fails as one row is bad
select * from trigger_test;
insert into trigger_test values (1); -- succeeds as expected
insert into trigger_test values (-1); -- fails as expected
select * from trigger_test;

Solution 2 - Mysql

Here is one hack that may work. It isn't clean, but it looks like it might work:

Essentially, you just try to update a column that doesn't exist.

Solution 3 - Mysql

Unfortunately, the answer provided by @RuiDC does not work in MySQL versions prior to 5.5 because there is no implementation of SIGNAL for stored procedures.

The solution I've found is to simulate a signal throwing a table_name doesn't exist error, pushing a customized error message into the table_name.

The hack could be implemented using triggers or using a stored procedure. I describe both options below following the example used by @RuiDC.

Using triggers

DELIMITER $$
-- before inserting new id
DROP TRIGGER IF EXISTS before_insert_id$$
CREATE TRIGGER before_insert_id
    BEFORE INSERT ON test FOR EACH ROW
    BEGIN
        -- condition to check
        IF NEW.id < 0 THEN
            -- hack to solve absence of SIGNAL/prepared statements in triggers
            UPDATE `Error: invalid_id_test` SET x=1;
        END IF;
    END$$

DELIMITER ;

Using a stored procedure

Stored procedures allows you to use dynamic sql, which makes possible the encapsulation of the error generation functionality in one procedure. The counterpoint is that we should control the applications insert/update methods, so they use only our stored procedure (not granting direct privileges to INSERT/UPDATE).

DELIMITER $$
-- my_signal procedure
CREATE PROCEDURE `my_signal`(in_errortext VARCHAR(255))
BEGIN
    SET @sql=CONCAT('UPDATE `', in_errortext, '` SET x=1');
    PREPARE my_signal_stmt FROM @sql;
    EXECUTE my_signal_stmt;
    DEALLOCATE PREPARE my_signal_stmt;
END$$

CREATE PROCEDURE insert_test(p_id INT)
BEGIN
    IF NEW.id < 0 THEN
         CALL my_signal('Error: invalid_id_test; Id must be a positive integer');
    ELSE
        INSERT INTO test (id) VALUES (p_id);
    END IF;
END$$
DELIMITER ;

Solution 4 - Mysql

The following procedure is (on mysql5) a way to throw custom errors , and log them at the same time:

create table mysql_error_generator(error_field varchar(64) unique) engine INNODB;
DELIMITER $$
CREATE PROCEDURE throwCustomError(IN errorText VARCHAR(44))
BEGIN
    DECLARE errorWithDate varchar(64);
    select concat("[",DATE_FORMAT(now(),"%Y%m%d %T"),"] ", errorText) into errorWithDate;
    INSERT IGNORE INTO mysql_error_generator(error_field) VALUES (errorWithDate);
    INSERT INTO mysql_error_generator(error_field) VALUES (errorWithDate);
END;
$$
DELIMITER ;


call throwCustomError("Custom error message with log support.");

Solution 5 - Mysql

CREATE TRIGGER sample_trigger_msg 
    BEFORE INSERT
FOR EACH ROW
    BEGIN
IF(NEW.important_value) < (1*2) THEN
    DECLARE dummy INT;
    SELECT 
           Enter your Message Here!!!
 INTO dummy 
        FROM mytable
      WHERE mytable.id=new.id
END IF;
END;

Solution 6 - Mysql

Another (hack) method (if you are not on 5.5+ for some reason) that you can use:

If you have a required field, then within a trigger set the required field to an invalid value such as NULL. This will work for both INSERT and UPDATE. Do note that if NULL is a valid value for the required field (for some crazy reason) then this approach will not work.

BEGIN
    -- Force one of the following to be assigned otherwise set required field to null which will throw an error
    IF (NEW.`nullable_field_1` IS NULL AND NEW.`nullable_field_2` IS NULL) THEN
	    SET NEW.`required_id_field`=NULL;
    END IF;
END

If you are on 5.5+ then you can use the signal state as described in other answers:

BEGIN
    -- Force one of the following to be assigned otherwise use signal sqlstate to throw a unique error
    IF (NEW.`nullable_field_1` IS NULL AND NEW.`nullable_field_2` IS NULL) THEN
	    SIGNAL SQLSTATE '45000' set message_text='A unique identifier for nullable_field_1 OR nullable_field_2 is required!';
    END IF;
END

Solution 7 - Mysql

DELIMITER @@
DROP TRIGGER IF EXISTS trigger_name @@
CREATE TRIGGER trigger_name 
BEFORE UPDATE ON table_name
FOR EACH ROW
BEGIN

  --the condition of error is: 
  --if NEW update value of the attribute age = 1 and OLD value was 0
  --key word OLD and NEW let you distinguish between the old and new value of an attribute

   IF (NEW.state = 1 AND OLD.state = 0) THEN
       signal sqlstate '-20000' set message_text = 'hey it's an error!';     
   END IF;

END @@ 
DELIMITER ;

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionMatt MacLeanView Question on Stackoverflow
Solution 1 - MysqlRuiDCView Answer on Stackoverflow
Solution 2 - MysqlJustinView Answer on Stackoverflow
Solution 3 - Mysqlel.atomoView Answer on Stackoverflow
Solution 4 - MysqlMarinos AnView Answer on Stackoverflow
Solution 5 - MysqlBHUVANESH MOHANKUMARView Answer on Stackoverflow
Solution 6 - MysqlPhotonFalconView Answer on Stackoverflow
Solution 7 - MysqlBashirView Answer on Stackoverflow