The calling thread must be STA, because many UI components require this

WpfXamlMultithreadingFacebook

Wpf Problem Overview


I am using http://www.codeproject.com/KB/IP/Facebook_API.aspx

I am trying to call the XAML which is created using WPF. But it gives me an error:

> The calling thread must be STA, because many UI components require this.

I don't know what to do. I am trying to do this:

FacebookApplication.FacebookFriendsList ffl = new FacebookFriendsList();

But it is giving me that error.

I added a background worker:

static BackgroundWorker bw = new BackgroundWorker();

static void Main(string[] args)
{
    bw.DoWork += bw_DoWork;
    bw.RunWorkerAsync("Message to worker");
    Console.ReadLine();
}

static void bw_DoWork(object sender, DoWorkEventArgs e)
{
    // This is called on the worker thread
    FacebookApplication.FacebookFriendsList ffl = new FacebookFriendsList();

    Console.WriteLine(e.Argument);        // Writes "Message to worker"

    // Perform time-consuming task...
}

Wpf Solutions


Solution 1 - Wpf

Try to invoke your code from the dispatcher:

Application.Current.Dispatcher.Invoke((Action)delegate{
      // your code
});

Solution 2 - Wpf

If you make the call from the main thread, you must add the STAThread attribute to the Main method, as stated in the previous answer.

If you use a separate thread, it needs to be in a STA (single-threaded apartment), which is not the case for background worker threads. You have to create the thread yourself, like this:

Thread t = new Thread(ThreadProc);
t.SetApartmentState(ApartmentState.STA);

t.Start();

with ThreadProc being a delegate of type ThreadStart.

Solution 3 - Wpf

You can also try this

// create a thread  
Thread newWindowThread = new Thread(new ThreadStart(() =>  
{  
    // create and show the window
    FaxImageLoad obj = new FaxImageLoad(destination);  
    obj.Show();  
    
    // start the Dispatcher processing  
    System.Windows.Threading.Dispatcher.Run();  
}));  

// set the apartment state  
newWindowThread.SetApartmentState(ApartmentState.STA);  

// make the thread a background thread  
newWindowThread.IsBackground = true;  

// start the thread  
newWindowThread.Start();  

Solution 4 - Wpf

I suspect that you are getting a callback to a UI component from a background thread. I recommend that you make that call using a BackgroundWorker as this is UI thread aware.

For the BackgroundWorker, the main program should be marked as [STAThread].

Solution 5 - Wpf

Just mark your program Main method with the [STAThread] attribute and the error goes away! it's magic :)

Example:

class Program {
    [STAThread]
    static void Main(string[] args) {
    // My code here
    }
}

Solution 6 - Wpf

For me, this error occurred because of a null parameter being passed. Checking the variable values fixed my issue without having to change the code. I used BackgroundWorker.

Solution 7 - Wpf

If the Application.Current is null for example by unit test, you can try this:

 System.Windows.Threading.Dispatcher.CurrentDispatcher.Invoke( YOUR action )

Solution 8 - Wpf

In my case, I wanted to launch a WPF window from a console app. Simply setting the Main method with [STAThread] didn't work.

A combination of Timores' and Mohammad's answer worked for me:

private static void StaThreadWrapper(Action action)
{
	var t = new Thread(o =>
	{
		action();
		System.Windows.Threading.Dispatcher.Run();
	});
	t.SetApartmentState(ApartmentState.STA);
	t.Start();
}

Example usage:

StaThreadWrapper(() =>
{
	var mainWindow = new MainWindow();
	mainWindow.Show();
});

Solution 9 - Wpf

Another situation if you may meet, choosing which Window to new and show.
Don't make the choice in App.xaml.cs' App() or OnStartup(), instead, make the choice in Startup event.

// App.xaml.cs
        private App()
        {
            Window window = CheckSession() ? new InstallWindow() : (Window)new LoginWindow();
            window.Show(); // bad 1
        }

        protected override void OnStartup(StartupEventArgs e)
        {
            Window window = CheckSession() ? new InstallWindow() : (Window)new LoginWindow();
            window.Show(); // bad 2

            base.OnStartup(e);
        }

Below should be good

// App.xaml.cs
        private App()
        {
            Startup += Application_Startup;
        }

        private void Application_Startup(object sender, StartupEventArgs e)
        {
            Window window = CheckSession() ? new InstallWindow() : (Window)new LoginWindow();
            window.Show();  // good
        }

Also remember to remove the StartupUri from App.xaml

<!--App.xaml-->
<Application StartupUri="MainWindow">
<!--remove StartupUri-->
</Application>

OR add the event here is OK too.

<!--App.xaml-->
<Application Startup="Application_Startup">

</Application>
// App.xaml.cs
        private App()
        {
            
        }

        private void Application_Startup(object sender, StartupEventArgs e)
        {
            Window window = CheckSession() ? new InstallWindow() : (Window)new LoginWindow();
            window.Show();  // good
        }

Solution 10 - Wpf

If you call a new window UI statement in an existing thread, it throws an error. Instead of that create a new thread inside the main thread and write the window UI statement in the new child thread.

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionC..View Question on Stackoverflow
Solution 1 - WpfAmjad AbdelrahmanView Answer on Stackoverflow
Solution 2 - WpfTimoresView Answer on Stackoverflow
Solution 3 - WpfMohammad Atiour IslamView Answer on Stackoverflow
Solution 4 - WpfPreet SanghaView Answer on Stackoverflow
Solution 5 - WpfLiRoNView Answer on Stackoverflow
Solution 6 - WpfRyan LoggerythmView Answer on Stackoverflow
Solution 7 - WpfGhislain ZabatioView Answer on Stackoverflow
Solution 8 - WpfdatchungView Answer on Stackoverflow
Solution 9 - WpfjqknonoView Answer on Stackoverflow
Solution 10 - WpfBalvant RamaniView Answer on Stackoverflow