Test for existence of nested JavaScript object key

JavascriptObjectPropertiesNested

Javascript Problem Overview


If I have a reference to an object:

var test = {};

that will potentially (but not immediately) have nested objects, something like:

{level1: {level2: {level3: "level3"}}};

What is the best way to check for the existence of property in deeply nested objects?

alert(test.level1); yields undefined, but alert(test.level1.level2.level3); fails.

I’m currently doing something like this:

if(test.level1 && test.level1.level2 && test.level1.level2.level3) {
    alert(test.level1.level2.level3);
}

but I was wondering if there’s a better way.

Javascript Solutions


Solution 1 - Javascript

You have to do it step by step if you don't want a TypeError because if one of the members is null or undefined, and you try to access a member, an exception will be thrown.

You can either simply catch the exception, or make a function to test the existence of multiple levels, something like this:

function checkNested(obj /*, level1, level2, ... levelN*/) {
  var args = Array.prototype.slice.call(arguments, 1);

  for (var i = 0; i < args.length; i++) {
    if (!obj || !obj.hasOwnProperty(args[i])) {
      return false;
    }
    obj = obj[args[i]];
  }
  return true;
}

var test = {level1:{level2:{level3:'level3'}} };

checkNested(test, 'level1', 'level2', 'level3'); // true
checkNested(test, 'level1', 'level2', 'foo'); // false

ES6 UPDATE:

Here is a shorter version of the original function, using ES6 features and recursion (it's also in proper tail call form):

function checkNested(obj, level,  ...rest) {
  if (obj === undefined) return false
  if (rest.length == 0 && obj.hasOwnProperty(level)) return true
  return checkNested(obj[level], ...rest)
}

However, if you want to get the value of a nested property and not only check its existence, here is a simple one-line function:

function getNested(obj, ...args) {
  return args.reduce((obj, level) => obj && obj[level], obj)
}

const test = { level1:{ level2:{ level3:'level3'} } };
console.log(getNested(test, 'level1', 'level2', 'level3')); // 'level3'
console.log(getNested(test, 'level1', 'level2', 'level3', 'length')); // 6
console.log(getNested(test, 'level1', 'level2', 'foo')); // undefined
console.log(getNested(test, 'a', 'b')); // undefined

The above function allows you to get the value of nested properties, otherwise will return undefined.

UPDATE 2019-10-17:

The optional chaining proposal reached Stage 3 on the ECMAScript committee process, this will allow you to safely access deeply nested properties, by using the token ?., the new optional chaining operator:

const value = obj?.level1?.level2?.level3 

If any of the levels accessed is null or undefined the expression will resolve to undefined by itself.

The proposal also allows you to handle method calls safely:

obj?.level1?.method();

The above expression will produce undefined if obj, obj.level1, or obj.level1.method are null or undefined, otherwise it will call the function.

You can start playing with this feature with Babel using the optional chaining plugin.

Since Babel 7.8.0, ES2020 is supported by default

Check this example on the Babel REPL.

UPDATE: December 2019 

The optional chaining proposal finally reached Stage 4 in the December 2019 meeting of the TC39 committee. This means this feature will be part of the ECMAScript 2020 Standard.

Solution 2 - Javascript

Here is a pattern I picked up from Oliver Steele:

var level3 = (((test || {}).level1 || {}).level2 || {}).level3;
alert( level3 );

In fact that whole article is a discussion of how you can do this in javascript. He settles on using the above syntax (which isn't that hard to read once you get used to it) as an idiom.

Solution 3 - Javascript

Update

Looks like lodash has added _.get for all your nested property getting needs.

_.get(countries, 'greece.sparta.playwright')

https://lodash.com/docs#get


Previous answer

lodash users may enjoy lodash.contrib which has a couple methods that mitigate this problem.

getPath

Signature: _.getPath(obj:Object, ks:String|Array)

Gets the value at any depth in a nested object based on the path described by the keys given. Keys may be given as an array or as a dot-separated string. Returns undefined if the path cannot be reached.

var countries = {
        greece: {
            athens: {
                playwright:  "Sophocles"
            }
        }
    }
};

_.getPath(countries, "greece.athens.playwright");
// => "Sophocles"

_.getPath(countries, "greece.sparta.playwright");
// => undefined

_.getPath(countries, ["greece", "athens", "playwright"]);
// => "Sophocles"

_.getPath(countries, ["greece", "sparta", "playwright"]);
// => undefined

Solution 4 - Javascript

I have done performance tests (thank you cdMinix for adding lodash) on some of the suggestions proposed to this question with the results listed below.

> Disclaimer #1 Turning strings into references is unnecessary meta-programming and probably best avoided. Don't lose track of your references to begin with. Read more from this answer to a similar question. > > Disclaimer #2 We are talking about millions of operations per millisecond here. It is very unlikely any of these would make much difference in most use cases. Choose whichever makes the most sense knowing the limitations of each. For me I would go with something like reduce out of convenience.

Object Wrap (by Oliver Steele) – 34 % – fastest

var r1 = (((test || {}).level1 || {}).level2 || {}).level3;
var r2 = (((test || {}).level1 || {}).level2 || {}).foo;

Original solution (suggested in question) – 45%

var r1 = test.level1 && test.level1.level2 && test.level1.level2.level3;
var r2 = test.level1 && test.level1.level2 && test.level1.level2.foo;

checkNested – 50%

function checkNested(obj) {
  for (var i = 1; i < arguments.length; i++) {
    if (!obj.hasOwnProperty(arguments[i])) {
      return false;
    }
    obj = obj[arguments[i]];
  }
  return true;
}

get_if_exist – 52%

function get_if_exist(str) {
    try { return eval(str) }
    catch(e) { return undefined }
}

validChain – 54%

function validChain( object, ...keys ) {
    return keys.reduce( ( a, b ) => ( a || { } )[ b ], object ) !== undefined;
}

objHasKeys – 63%

function objHasKeys(obj, keys) {
  var next = keys.shift();
  return obj[next] && (! keys.length || objHasKeys(obj[next], keys));
}

nestedPropertyExists – 69%

function nestedPropertyExists(obj, props) {
    var prop = props.shift();
    return prop === undefined ? true : obj.hasOwnProperty(prop) ? nestedPropertyExists(obj[prop], props) : false;
}

_.get – 72%

deeptest – 86%

function deeptest(target, s){
    s= s.split('.')
    var obj= target[s.shift()];
    while(obj && s.length) obj= obj[s.shift()];
    return obj;
}

sad clowns – 100% – slowest

var o = function(obj) { return obj || {} };

var r1 = o(o(o(o(test).level1).level2).level3);
var r2 = o(o(o(o(test).level1).level2).foo);

Solution 5 - Javascript

You can read an object property at any depth, if you handle the name like a string: 't.level1.level2.level3'.

window.t={level1:{level2:{level3: 'level3'}}};

function deeptest(s){
	s= s.split('.')
	var obj= window[s.shift()];
	while(obj && s.length) obj= obj[s.shift()];
	return obj;
}

alert(deeptest('t.level1.level2.level3') || 'Undefined');

It returns undefined if any of the segments is undefined.

Solution 6 - Javascript

var a;

a = {
    b: {
        c: 'd'
    }
};

function isset (fn) {
    var value;
    try {
        value = fn();
    } catch (e) {
        value = undefined;
    } finally {
        return value !== undefined;
    }
};

// ES5
console.log(
    isset(function () { return a.b.c; }),
    isset(function () { return a.b.c.d.e.f; })
);

If you are coding in ES6 environment (or using 6to5) then you can take advantage of the arrow function syntax:

// ES6 using the arrow function
console.log(
    isset(() => a.b.c),
    isset(() => a.b.c.d.e.f)
);

Regarding the performance, there is no performance penalty for using try..catch block if the property is set. There is a performance impact if the property is unset.

Consider simply using _.has:

var object = { 'a': { 'b': { 'c': 3 } } };

_.has(object, 'a');
// → true

_.has(object, 'a.b.c');
// → true

_.has(object, ['a', 'b', 'c']);
// → true

Solution 7 - Javascript

how about

try {
   alert(test.level1.level2.level3)
} catch(e) {
 ...whatever

}

Solution 8 - Javascript

You can also use tc39 optional chaining proposal together with babel 7 - tc39-proposal-optional-chaining

Code would look like this:

  const test = test?.level1?.level2?.level3;
  if (test) alert(test);

Solution 9 - Javascript

ES6 answer, thoroughly tested :)

const propExists = (obj, path) => {
    return !!path.split('.').reduce((obj, prop) => {
        return obj && obj[prop] ? obj[prop] : undefined;
    }, obj)
}
→see Codepen with full test coverage

Solution 10 - Javascript

I tried a recursive approach:

function objHasKeys(obj, keys) {
  var next = keys.shift();
  return obj[next] && (! keys.length || objHasKeys(obj[next], keys));
}

The ! keys.length || kicks out of the recursion so it doesn't run the function with no keys left to test. Tests:

obj = {
  path: {
    to: {
      the: {
        goodKey: "hello"
      }
    }
  }
}

console.log(objHasKeys(obj, ['path', 'to', 'the', 'goodKey'])); // true
console.log(objHasKeys(obj, ['path', 'to', 'the', 'badKey']));  // undefined

I am using it to print a friendly html view of a bunch of objects with unknown key/values, e.g.:

var biosName = objHasKeys(myObj, 'MachineInfo:BiosInfo:Name'.split(':'))
             ? myObj.MachineInfo.BiosInfo.Name
             : 'unknown';

Solution 11 - Javascript

This question is old. Today you can use Optional chaining (?.)

let value = test?.level1?.level2?.level3;

Source:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Optional_chaining

Solution 12 - Javascript

I think the following script gives more readable representation.

declare a function:

var o = function(obj) { return obj || {};};

then use it like this:

if (o(o(o(o(test).level1).level2).level3)
{

}

I call it "sad clown technique" because it is using sign o(


EDIT:

here is a version for TypeScript

it gives type checks at compile time (as well as the intellisense if you use a tool like Visual Studio)

export function o<T>(someObject: T, defaultValue: T = {} as T) : T {
    if (typeof someObject === 'undefined' || someObject === null)
        return defaultValue;
    else
        return someObject;
}

the usage is the same:

o(o(o(o(test).level1).level2).level3

but this time intellisense works!

plus, you can set a default value:

o(o(o(o(o(test).level1).level2).level3, "none")

Solution 13 - Javascript

I didn't see any example of someone using Proxies

So I came up with my own. The great thing about it is that you don't have to interpolate strings. You can actually return a chain-able object function and do some magical things with it. You can even call functions and get array indexes to check for deep objects

function resolve(target) {
  var noop = () => {} // We us a noop function so we can call methods also
  return new Proxy(noop, {
    get(noop, key) {
      // return end result if key is _result
      return key === '_result' 
        ? target 
        : resolve( // resolve with target value or undefined
            target === undefined ? undefined : target[key]
          )
    },

    // if we want to test a function then we can do so alos thanks to using noop
    // instead of using target in our proxy
    apply(noop, that, args) {
      return resolve(typeof target === 'function' ? target.apply(that, args) : undefined)
    },
  })
}

// some modified examples from the accepted answer
var test = {level1: {level2:() => ({level3:'level3'})}}
var test1 = {key1: {key2: ['item0']}}

// You need to get _result in the end to get the final result

console.log(resolve(test).level1.level2().level3._result)
console.log(resolve(test).level1.level2().level3.level4.level5._result)
console.log(resolve(test1).key1.key2[0]._result)
console.log(resolve(test1)[0].key._result) // don't exist

The above code works fine for synchronous stuff. But how would you test something that is asynchronous like this ajax call? How do you test that?

fetch('https://httpbin.org/get')
.then(function(response) {
  return response.json()
})
.then(function(json) {
  console.log(json.headers['User-Agent'])
})

sure you could use async/await to get rid of some callbacks. But what if you could do it even more magically? something that looks like this:

fetch('https://httpbin.org/get').json().headers['User-Agent']

You probably wonder where all the promise & .then chains are... this could be blocking for all that you know... but using the same Proxy technique with promise you can actually test deeply nested complex path for it existence without ever writing a single function

function resolve(target) { 
  return new Proxy(() => {}, {
    get(noop, key) {
      return key === 'then' ? target.then.bind(target) : resolve(
        Promise.resolve(target).then(target => {
          if (typeof target[key] === 'function') return target[key].bind(target)
          return target[key]
        })
      )
    },

    apply(noop, that, args) {
      return resolve(target.then(result => {
        return result.apply(that, args)
      }))
    },
  })
}

// this feels very much synchronous but are still non blocking :)
resolve(window) // this will chain a noop function until you call then()
  .fetch('https://httpbin.org/get')
  .json()
  .headers['User-Agent']
  .then(console.log, console.warn) // you get a warning if it doesn't exist
  
// You could use this method also for the first test object
// also, but it would have to call .then() in the end



// Another example
resolve(window)
  .fetch('https://httpbin.org/get?items=4&items=2')
  .json()
  .args
  .items
  // nice that you can map an array item without even having it ready
  .map(n => ~~n * 4) 
  .then(console.log, console.warn) // you get a warning if it doesn't exist

Solution 14 - Javascript

create a global function and use in whole project

try this

function isExist(arg){
   try{
      return arg();
   }catch(e){
      return false;
   }
}

let obj={a:5,b:{c:5}};

console.log(isExist(()=>obj.b.c))
console.log(isExist(()=>obj.b.foo))
console.log(isExist(()=>obj.test.foo))

if condition

if(isExist(()=>obj.test.foo)){
   ....
}

Solution 15 - Javascript

One simple way is this:

try {
    alert(test.level1.level2.level3);
} catch(e) {
    alert("undefined");    // this is optional to put any output here
}

The try/catch catches the cases for when any of the higher level objects such as test, test.level1, test.level1.level2 are not defined.

Solution 16 - Javascript

Based on this answer, I came up with this generic function using ES2015 which would solve the problem

function validChain( object, ...keys ) {
	return keys.reduce( ( a, b ) => ( a || { } )[ b ], object ) !== undefined;
}

var test = {
  first: {
  	second: {
    	third: "This is not the key your are looking for"
    }
  }
}

if ( validChain( test, "first", "second", "third" ) ) {
	console.log( test.first.second.third );
}

Solution 17 - Javascript

I have created a little function to get nested object properties safely.

function getValue(object, path, fallback, fallbackOnFalsy) {
    if (!object || !path) {
        return fallback;
    }

    // Reduces object properties to the deepest property in the path argument.
    return path.split('.').reduce((object, property) => {
       if (object && typeof object !== 'string' && object.hasOwnProperty(property)) {
            // The property is found but it may be falsy.
            // If fallback is active for falsy values, the fallback is returned, otherwise the property value.
            return !object[property] && fallbackOnFalsy ? fallback : object[property];
        } else {
            // Returns the fallback if current chain link does not exist or it does not contain the property.
            return fallback;
        }
    }, object);
}

Or a simpler but slightly unreadable version:

function getValue(o, path, fb, fbFalsy) {
   if(!o || !path) return fb;
   return path.split('.').reduce((o, p) => o && typeof o !== 'string' && o.hasOwnProperty(p) ? !o[p] && fbFalsy ? fb : o[p] : fb, o);
}

Or even shorter but without fallback on falsy flag:

function getValue(o, path, fb) {
   if(!o || !path) return fb;
   return path.split('.').reduce((o, p) => o && typeof o !== 'string' && o.hasOwnProperty(p) ? o[p] : fb, o);
}

I have test with:

const obj = {
    c: {
        a: 2,
        b: {
            c: [1, 2, 3, {a: 15, b: 10}, 15]
        },
        c: undefined,
        d: null
    },
    d: ''
}

And here are some tests:

// null
console.log(getValue(obj, 'c.d', 'fallback'));

// array
console.log(getValue(obj, 'c.b.c', 'fallback'));

// array index 2
console.log(getValue(obj, 'c.b.c.2', 'fallback'));

// no index => fallback
console.log(getValue(obj, 'c.b.c.10', 'fallback'));

To see all the code with documentation and the tests I've tried you can check my github gist: https://gist.github.com/vsambor/3df9ad75ff3de489bbcb7b8c60beebf4#file-javascriptgetnestedvalues-js

Solution 18 - Javascript

A shorter, ES5 version of @CMS's excellent answer:

// Check the obj has the keys in the order mentioned. Used for checking JSON results.  
var checkObjHasKeys = function(obj, keys) {
  var success = true;
  keys.forEach( function(key) {
    if ( ! obj.hasOwnProperty(key)) {
      success = false;
    }
    obj = obj[key];
  })
  return success;
}

With a similar test:

var test = { level1:{level2:{level3:'result'}}};
utils.checkObjHasKeys(test, ['level1', 'level2', 'level3']); // true
utils.checkObjHasKeys(test, ['level1', 'level2', 'foo']); // false

Solution 19 - Javascript

I was looking for the value to be returned if the property exists, so I modified the answer by CMS above. Here's what I came up with:

function getNestedProperty(obj, key) {
  // Get property array from key string
  var properties = key.split(".");

  // Iterate through properties, returning undefined if object is null or property doesn't exist
  for (var i = 0; i < properties.length; i++) {
    if (!obj || !obj.hasOwnProperty(properties[i])) {
      return;
    }
    obj = obj[properties[i]];
  }

  // Nested property found, so return the value
  return obj;
}


Usage:

getNestedProperty(test, "level1.level2.level3") // "level3"
getNestedProperty(test, "level1.level2.foo") // undefined

Solution 20 - Javascript

The answer given by CMS works fine with the following modification for null checks as well

function checkNested(obj /*, level1, level2, ... levelN*/) 
	  {
			 var args = Array.prototype.slice.call(arguments),
			 obj = args.shift();

			for (var i = 0; i < args.length; i++) 
			{
				if (obj == null || !obj.hasOwnProperty(args[i]) ) 
				{
					return false;
				}
				obj = obj[args[i]];
			}
			return true;
	}

Solution 21 - Javascript

Following options were elaborated starting from this answer. Same tree for both :

var o = { a: { b: { c: 1 } } };

Stop searching when undefined

var u = undefined;
o.a ? o.a.b ? o.a.b.c : u : u // 1
o.x ? o.x.y ? o.x.y.z : u : u // undefined
(o = o.a) ? (o = o.b) ? o.c : u : u // 1

Ensure each level one by one

var $ = function (empty) {
	return function (node) {
		return node || empty;
	};
}({});

$($(o.a).b).c // 1
$($(o.x).y).z // undefined

Solution 22 - Javascript

I know this question is old, but I wanted to offer an extension by adding this to all objects. I know people tend to frown on using the Object prototype for extended object functionality, but I don't find anything easier than doing this. Plus, it's now allowed for with the Object.defineProperty method.

Object.defineProperty( Object.prototype, "has", { value: function( needle ) {
    var obj = this;
    var needles = needle.split( "." );
    for( var i = 0; i<needles.length; i++ ) {
        if( !obj.hasOwnProperty(needles[i])) {
            return false;
        }
        obj = obj[needles[i]];
    }
    return true;
}});

Now, in order to test for any property in any object you can simply do:

if( obj.has("some.deep.nested.object.somewhere") )

Here's a jsfiddle to test it out, and in particular it includes some jQuery that breaks if you modify the Object.prototype directly because of the property becoming enumerable. This should work fine with 3rd party libraries.

Solution 23 - Javascript

I think this is a slight improvement (becomes a 1-liner):

   alert( test.level1 && test.level1.level2 && test.level1.level2.level3 )

This works because the && operator returns the final operand it evaluated (and it short-circuits).

Solution 24 - Javascript

Here's my take on it - most of these solutions ignore the case of a nested array as in:

    obj = {
        "l1":"something",
        "l2":[{k:0},{k:1}],
        "l3":{
            "subL":"hello"
        }
    }

I may want to check for obj.l2[0].k

With the function below, you can do deeptest('l2[0].k',obj)

The function will return true if the object exists, false otherwise

function deeptest(keyPath, testObj) {
    var obj;

    keyPath = keyPath.split('.')
    var cKey = keyPath.shift();

    function get(pObj, pKey) {
        var bracketStart, bracketEnd, o;

        bracketStart = pKey.indexOf("[");
        if (bracketStart > -1) { //check for nested arrays
            bracketEnd = pKey.indexOf("]");
            var arrIndex = pKey.substr(bracketStart + 1, bracketEnd - bracketStart - 1);
            pKey = pKey.substr(0, bracketStart);
			var n = pObj[pKey];
            o = n? n[arrIndex] : undefined;

        } else {
            o = pObj[pKey];
        }
        return o;
    }

    obj = get(testObj, cKey);
    while (obj && keyPath.length) {
        obj = get(obj, keyPath.shift());
    }
    return typeof(obj) !== 'undefined';
}

var obj = {
    "l1":"level1",
    "arr1":[
        {"k":0},
        {"k":1},
        {"k":2}
    ],
    "sub": {
       	"a":"letter A",
        "b":"letter B"
    }
};
console.log("l1: " + deeptest("l1",obj));
console.log("arr1[0]: " + deeptest("arr1[0]",obj));
console.log("arr1[1].k: " + deeptest("arr1[1].k",obj));
console.log("arr1[1].j: " + deeptest("arr1[1].j",obj));
console.log("arr1[3]: " + deeptest("arr1[3]",obj));
console.log("arr2: " + deeptest("arr2",obj));

Solution 25 - Javascript

This works with all objects and arrays :)

ex:

if( obj._has( "something.['deep']['under'][1][0].item" ) ) {
    //do something
}

this is my improved version of Brian's answer

I used _has as the property name because it can conflict with existing has property (ex: maps)

Object.defineProperty( Object.prototype, "_has", { value: function( needle ) {
var obj = this;
var needles = needle.split( "." );
var needles_full=[];
var needles_square;
for( var i = 0; i<needles.length; i++ ) {
    needles_square = needles[i].split( "[" );
    if(needles_square.length>1){
        for( var j = 0; j<needles_square.length; j++ ) {
            if(needles_square[j].length){
                needles_full.push(needles_square[j]);
            }
        }
    }else{
        needles_full.push(needles[i]);
    }
}
for( var i = 0; i<needles_full.length; i++ ) {
    var res = needles_full[i].match(/^((\d+)|"(.+)"|'(.+)')\]$/);
    if (res != null) {
        for (var j = 0; j < res.length; j++) {
            if (res[j] != undefined) {
                needles_full[i] = res[j];
            }
        }
    }

    if( typeof obj[needles_full[i]]=='undefined') {
        return false;
    }
    obj = obj[needles_full[i]];
}
return true;
}});

Here's the fiddle

Solution 26 - Javascript

Now we can also use reduce to loop through nested keys:

// @params o<object>
// @params path<string> expects 'obj.prop1.prop2.prop3'
// returns: obj[path] value or 'false' if prop doesn't exist

const objPropIfExists = o => path => {
  const levels = path.split('.');
  const res = (levels.length > 0) 
    ? levels.reduce((a, c) => a[c] || 0, o)
    : o[path];
  return (!!res) ? res : false
}

const obj = {
  name: 'Name',
  sys: { country: 'AU' },
  main: { temp: '34', temp_min: '13' },
  visibility: '35%'
}

const exists = objPropIfExists(obj)('main.temp')
const doesntExist = objPropIfExists(obj)('main.temp.foo.bar.baz')

console.log(exists, doesntExist)

Solution 27 - Javascript

You can do this by using the recursive function. This will work even if you don't know all nested Object keys name.

function FetchKeys(obj) {
    let objKeys = [];
    let keyValues = Object.entries(obj);
    for (let i in keyValues) {
        objKeys.push(keyValues[i][0]);
        if (typeof keyValues[i][1] == "object") {
            var keys = FetchKeys(keyValues[i][1])
            objKeys = objKeys.concat(keys);
        }
    }
    return objKeys;
}

let test = { level1: { level2: { level3: "level3" } } };
let keyToCheck = "level2";
let keys = FetchKeys(test); //Will return an array of Keys

if (keys.indexOf(keyToCheck) != -1) {
    //Key Exists logic;
}
else {
    //Key Not Found logic;
}

Solution 28 - Javascript

And yet another one which is very compact:

function ifSet(object, path) {
  return path.split('.').reduce((obj, part) => obj && obj[part], object)
}

called:

let a = {b:{c:{d:{e:'found!'}}}}
ifSet(a, 'b.c.d.e') == 'found!'
ifSet(a, 'a.a.a.a.a.a') == undefined

It won't perform great since it's splitting a string (but increases readability of the call) and iterates over everything even if it's already obvious that nothing will be found (but increases readability of the function itself).

at least is faster than _.get http://jsben.ch/aAtmc

Solution 29 - Javascript

I have used this function for access properties of the deeply nested object and it working for me...

this is the function

/**
 * get property of object
 * @param obj object
 * @param path e.g user.name
 */
getProperty(obj, path, defaultValue = '-') {
  const value = path.split('.').reduce((o, p) => o && o[p], obj);

  return value ? value : defaultValue;
}

this is how I access the deeply nested object property

{{ getProperty(object, 'passengerDetails.data.driverInfo.currentVehicle.vehicleType') }}

Solution 30 - Javascript

theres a function here on thecodeabode (safeRead) which will do this in a safe manner... i.e.

safeRead(test, 'level1', 'level2', 'level3');

if any property is null or undefined, an empty string is returned

Solution 31 - Javascript

I wrote my own function that takes the desired path, and has a good and bad callback function.

function checkForPathInObject(object, path, callbackGood, callbackBad){
    var pathParts = path.split(".");
    var currentObjectPath = object;

    // Test every step to see if it exists in object
    for(var i=0; i<(pathParts.length); i++){
        var currentPathPart = pathParts[i];
        if(!currentObjectPath.hasOwnProperty(pathParts[i])){
            if(callbackBad){
                callbackBad();
            }
            return false;
        } else {
            currentObjectPath = currentObjectPath[pathParts[i]];
        }
    }

    // call full path in callback
    callbackGood();
}

Usage:

var testObject = {
    level1:{
        level2:{
            level3:{
            }
        }
    }
};


checkForPathInObject(testObject, "level1.level2.level3", function(){alert("good!")}, function(){alert("bad!")}); // good

checkForPathInObject(testObject, "level1.level2.level3.levelNotThere", function(){alert("good!")}, function(){alert("bad!")}); //bad

Solution 32 - Javascript

//Just in case is not supported or not included by your framework
//***************************************************
Array.prototype.some = function(fn, thisObj) {
  var scope = thisObj || window;
  for ( var i=0, j=this.length; i < j; ++i ) {
    if ( fn.call(scope, this[i], i, this) ) {
      return true;
    }
  }
  return false;
};
//****************************************************
 
function isSet (object, string) {
  if (!object) return false;
  var childs = string.split('.');
  if (childs.length > 0 ) {
    return !childs.some(function (item) {
      if (item in object) {
        object = object[item]; 
        return false;
      } else return true;
    });
  } else if (string in object) { 
    return true;
  } else return false;
}
 
var object = {
  data: {
    item: {
      sub_item: {
        bla: {
          here : {
            iam: true
          }
        }
      }
    }
  }
};
 
console.log(isSet(object,'data.item')); // true
console.log(isSet(object,'x')); // false
console.log(isSet(object,'data.sub_item')); // false
console.log(isSet(object,'data.item')); // true
console.log(isSet(object,'data.item.sub_item.bla.here.iam')); // true

Solution 33 - Javascript

I was having the same issue and and wanted to see if I could come up with a my own solution. This accepts the path you want to check as a string.

function checkPathForTruthy(obj, path) {
  if (/\[[a-zA-Z_]/.test(path)) {
    console.log("Cannot resolve variables in property accessors");
    return false;
  }

  path = path.replace(/\[/g, ".");
  path = path.replace(/]|'|"/g, "");
  path = path.split(".");

  var steps = 0;
  var lastRef = obj;
  var exists = path.every(key => {
    var currentItem = lastRef[path[steps]];
    if (currentItem) {
      lastRef = currentItem;
      steps++;
      return true;
    } else {
      return false;
    }
  });

  return exists;
}

Here is a snippet with some logging and test cases:

console.clear();
var testCases = [
  ["data.Messages[0].Code", true],
  ["data.Messages[1].Code", true],
  ["data.Messages[0]['Code']", true],
  ['data.Messages[0]["Code"]', true],
  ["data[Messages][0]['Code']", false],
  ["data['Messages'][0]['Code']", true]
];
var path = "data.Messages[0].Code";
var obj = {
  data: {
    Messages: [{
      Code: "0"
    }, {
      Code: "1"
    }]
  }
}

function checkPathForTruthy(obj, path) {
  if (/\[[a-zA-Z_]/.test(path)) {
    console.log("Cannot resolve variables in property accessors");
    return false;
  }

  path = path.replace(/\[/g, ".");
  path = path.replace(/]|'|"/g, "");
  path = path.split(".");

  var steps = 0;
  var lastRef = obj;
  var logOutput = [];
  var exists = path.every(key => {
    var currentItem = lastRef[path[steps]];
    if (currentItem) {
      logOutput.push(currentItem);
      lastRef = currentItem;
      steps++;
      return true;
    } else {
      return false;
    }
  });
  console.log(exists, logOutput);
  return exists;
}

testCases.forEach(testCase => {
  if (checkPathForTruthy(obj, testCase[0]) === testCase[1]) {
    console.log("Passed: " + testCase[0]);
  } else {
    console.log("Failed: " + testCase[0] + " expected " + testCase[1]);
  }
});

Solution 34 - Javascript

Based on a previous comment, here is another version where the main object could not be defined either:

// Supposing that our property is at first.second.third.property:
var property = (((typeof first !== 'undefined' ? first : {}).second || {}).third || {}).property;

Solution 35 - Javascript

Slight edit to this answer to allow nested arrays in the path

var has = function (obj, key) {
    return key.split(".").every(function (x) {
        if (typeof obj != "object" || obj === null || !x in obj)
            return false;
        if (obj.constructor === Array) 
            obj = obj[0];
        obj = obj[x];
        return true;
    });
}

Check linked answer for usages :)

Solution 36 - Javascript

I thought I'd add another one that I came up with today. The reason I am proud of this solution is that it avoids nested brackets that are used in many solutions such as Object Wrap (by Oliver Steele):

(in this example I use an underscore as a placeholder variable, but any variable name will work)

//the 'test' object
var test = {level1: {level2: {level3: 'level3'}}};

let _ = test;

if ((_=_.level1) && (_=_.level2) && (_=_.level3)) {

  let level3 = _;
  //do stuff with level3

}

//you could also use 'stacked' if statements. This helps if your object goes very deep. 
//(formatted without nesting or curly braces except the last one)

let _ = test;

if (_=_.level1)
if (_=_.level2)
if (_=_.level3) {

   let level3 = _;
   //do stuff with level3
}


//or you can indent:
if (_=_.level1)
  if (_=_.level2)
    if (_=_.level3) {

      let level3 = _;
      //do stuff with level3
}

Solution 37 - Javascript

Well there are no really good answer for one-liners to use in html templates, so i made one using ES6 Proxies. You just pass an object or value to the "traverse" function and do as much nested calls as you want closing them with function call which will return value or fallback value. Using:

const testObject = { 
  deep: { 
    nested: { 
      obj: { 
        closure: () => { return "closure" },
        number: 9,
        boolean: true,
        array: [1, 2, { foo: { bar: true } }]
      } 
    }
  }
}

traverse(testObject).deep() 
// {nested: {…}}

traverse(testObject).non.existent() 
// undefined

traverse(testObject).deep.nested.obj.closure()() 
// closure

traverse(testObject).deep.nested.obj.array[5]('fallback')
// fallback

traverse(testObject).deep.nested.obj.array[2]()
// {foo: {…}}

traverse(testObject).deep.nested.obj.array[2].foo.bar()
// true

traverse(testObject).deep.nested.obj.array[2].foo.bar[4]('fallback')
// fallback

traverse(testObject).completely.wrong[3].call().WILL_THROW()
// Uncaught TypeError: Cannot read property 'WILL_THROW' of undefined

Function itself:

const traverse = (input) => {
    // unique empty object
    const unset = new Object();
    // we need wrapper to ensure we have access to the same unique empty object
    const closure = (input) => {
        // wrap each input into this
        const handler = new Function();
        handler.input = input;    
        // return wrappers proxy 
        return new Proxy(handler, {
            // keep traversing
            get: (target, name) => {
                // if undefined supplied as initial input
                if (!target.input) {
                    return closure(unset);
                }
                // otherwise
                if (target.input[name] !== undefined) {
                    // input has that property
                    return closure(target.input[name]);
                } else {
                    return closure(unset);
                }
            },
            // result with fallback
            apply: (target, context, args) => {
                return handler.input === unset ? 
                    args[0] : handler.input;
            }
        })
    }
    return closure(input);    
}

Solution 38 - Javascript

You can try Optional chaining (but be careful of browser compatibility).

let test = {level1: {level2: {level3: 'level3'}}};

let level3 = test?.level1?.level2?.level3;
console.log(level3); // level3

level3 = test?.level0?.level1?.level2?.level3;
console.log(level3); // undefined

There is a babel plugin(@babel/plugin-proposal-optional-chaining) for optinal chaning. So, please upgrade your babel if necessary.

Solution 39 - Javascript

Another ES5 solution:

function hasProperties(object, properties) {
    return !properties.some(function(property){
        if (!object.hasOwnProperty(property)) {
            return true;
        }
        object = object[property];
        return false;
    });
}

Solution 40 - Javascript

My solution that I use since long time (using string unfortunaly, couldn't find better)

function get_if_exist(str){
	try{return eval(str)}
	catch(e){return undefined}
}

// way to use
if(get_if_exist('test.level1.level2.level3')) {
    alert(test.level1.level2.level3);
}

// or simply 
alert(get_if_exist('test.level1.level2.level3'));

edit: this work only if object "test" have global scope/range. else you have to do something like :

// i think it's the most beautiful code I have ever write :p
function get_if_exist(obj){
	return arguments.length==1 || (obj[arguments[1]] && get_if_exist.apply(this,[obj[arguments[1]]].concat([].slice.call(arguments,2))));
}

alert(get_if_exist(test,'level1','level2','level3'));

edit final version to allow 2 method of call :

function get_if_exist(obj){
    var a=arguments, b=a.callee; // replace a.callee by the function name you choose because callee is depreceate, in this case : get_if_exist
    // version 1 calling the version 2
    if(a[1] && ~a[1].indexOf('.')) 
        return b.apply(this,[obj].concat(a[1].split('.')));
    // version 2
    return a.length==1 ? a[0] : (obj[a[1]] && b.apply(this,[obj[a[1]]].concat([].slice.call(a,2))));
}

// method 1
get_if_exist(test,'level1.level2.level3');


// method 2
get_if_exist(test,'level1','level2','level3');

Solution 41 - Javascript

Another option (close to this answer) :

function resolve(root, path){
	try {
		return (new Function(
			'root', 'return root.' + path + ';'
		))(root);
	} catch (e) {}
}

var tree = { level1: [{ key: 'value' }] };
resolve(tree, 'level1[0].key'); // "value"
resolve(tree, 'level1[1].key'); // undefined

More on this : https://stackoverflow.com/a/18381564/1636522

Solution 42 - Javascript

Yet another version:

function nestedPropertyExists(obj, props) {
	var prop = props.shift();
	return prop === undefined
		? true
		: obj.hasOwnProperty(prop) ? nestedPropertyExists(obj[prop], props) : false;
}

nestedPropertyExists({a:{b:{c:1}}}, ['a','b','c']); // returns true
nestedPropertyExists({a:{b:{c:1}}}, ['a','b','c','d']); // returns false

Solution 43 - Javascript

I wrote a library called l33teral to help test for nested properties. You can use it like this:

var myObj = {/*...*/};
var hasNestedProperties = leet(myObj).probe('prop1.prop2.prop3');

I do like the ES5/6 solutions here, too.

Solution 44 - Javascript

function isIn(string, object){
    var arr = string.split(".");
    var notFound = true;
    var length = arr.length;
    for (var i = 0; i < length; i++){
        var key = arr[i];
        if (!object.hasOwnProperty(key)){
            notFound = false;
            break;
        }
        if ((i + length) <= length){
            object = object[key];
        }
    }
    return notFound;
}
var musicCollection = {
    hasslehoff: {
        greatestHits : true
    }
};
console.log(isIn("hasslehoff.greatestHits", musicCollection));
console.log(isIn("hasslehoff.worseHits", musicCollection));

here my String based delimiter version.

Solution 45 - Javascript

Based on @Stephane LaFlèche's answer, I came up with my alternative version of the script.

Demo on JSFiddle

var obj = {"a":{"b":{"c":"Hello World"}},"resTest":"potato","success":"This path exists"};
checkForPathInObject = function(object,path,value) {
        var pathParts 	= path.split("."),
        	result 		= false;
        // Check if required parameters are set; if not, return false
        if(!object || typeof object == 'undefined' || !path || typeof path != 'string')
            return false;
        /* Loop through object keys to find a way to the path or check for value
		 * If the property does not exist, set result to false
		 * If the property is an object, update @object
		 * Otherwise, update result */
        for(var i=0;i<pathParts.length;i++){
			var currentPathPart = pathParts[i];
			if(!object.hasOwnProperty( currentPathPart )) {
				result = false;
			} else if (object[ currentPathPart ] && path == pathParts[i]) {
				result = pathParts[i];
				break;
			} else if(typeof object[ currentPathPart ] == 'object') {
				object = object[ currentPathPart ];
			} else {
				result = object[ currentPathPart ];
			}
		}
        /* */
        if(typeof value != 'undefined' && value == result)
            return true;
        return result;
};
// Uncomment the lines below to test the script
// alert( checkForPathInObject(obj,'a.b.c') ); // Results "Hello World"
// alert( checkForPathInObject(obj,'a.success') ); // Returns false
// alert( checkForPathInObject(obj,'resTest', 'potato') ); // Returns true

Solution 46 - Javascript

I am using a function in the following fashion.

var a = {};
a.b = {};
a.b.c = {};
a.b.c.d = "abcdabcd";

function isDefined(objectChainString) {
    try {
        var properties = objectChainString.split('.');
        var currentLevel = properties[0];
        if (currentLevel in window) {
            var consolidatedLevel = window[currentLevel];
            for (var i in properties) {
                if (i == 0) {
                    continue;
                } else {
                    consolidatedLevel = consolidatedLevel[properties[i]];
                }
            }
            if (typeof consolidatedLevel != 'undefined') {
                return true;
            } else {
                return false;
            }
        } else {
            return false;
        }
    } catch (e) {
        return false;
    }
}

// defined
console.log(checkUndefined("a.b.x.d"));
//undefined
console.log(checkUndefined("a.b.c.x"));
console.log(checkUndefined("a.b.x.d"));
console.log(checkUndefined("x.b.c.d"));

Solution 47 - Javascript

The very best and simplest answer is:

var isDefinedPath = function (path) {

    var items = path.split ('.');

    if (!items || items.length < 1 || !(items[0] in window)) { return false; }

    var buffer = [items[0]];
    for (var i = 1, e = items.length; i < e; i ++) {
    	buffer.push (items[i]);
    	if (eval ('typeof(' + buffer.join ('.') + ') == "undefined"')) {
    		return false;
    	}
    }

    return true;

}

test: isDefinedPath ('level1.level2.level3');

first level cannot be array, others can

Solution 48 - Javascript

CMS solution works great but usage/syntax can be more convenient. I suggest following

var checkNested = function(obj, structure) {

  var args = structure.split(".");

  for (var i = 0; i < args.length; i++) {
    if (!obj || !obj.hasOwnProperty(args[i])) {
      return false;
    }
    obj = obj[args[i]];
  }
  return true;
};

You can simply use object notation using dot instead of supplying multiple arguments

var test = {level1:{level2:{level3:'level3'}} };

checkNested(test, 'level1.level2.level3'); // true
checkNested(test, 'level1.level2.foo'); // false

Solution 49 - Javascript

Another way to work this out is for example, having the following object :

var x = {
	a: {
		b: 3
	}
};

then, what I did was add the following function to this object :

x.getKey = function(k){
		var r ;
		try {
			r = eval('typeof this.'+k+' !== "undefined"');
		}catch(e){
			r = false;
		}
		if(r !== false){
			return eval('this.'+k);
		}else{
			console.error('Missing key: \''+k+'\'');
			return '';
		}
	};

then you can test :

x.getKey('a.b');

If it's undefined the function returns "" (empty string) else it returns the existing value.

Please also consider this other more complex solution checking the link : https://stackoverflow.com/questions/33444711/js-object-has-property-deep-check

Object.prototype.hasOwnNestedProperty = function(propertyPath){
	if(!propertyPath)
		return false;
	
    var properties = propertyPath.split('.');
	var obj = this;
	
	for (var i = 0; i < properties.length; i++) {
		var prop = properties[i];
	
		if(!obj || !obj.hasOwnProperty(prop)){
			return false;
		} else {
			obj = obj[prop];
		}
    }

    return true;
};

// Usage: 
var obj = {
   innerObject:{
       deepObject:{
           value:'Here am I'
       }
   }
}

obj.hasOwnNestedProperty('innerObject.deepObject.value');

P.S.: There is also a recursive version.

Solution 50 - Javascript

you can path object and path seprated with "."

function checkPathExist(obj, path) {
  var pathArray =path.split(".")
  for (var i of pathArray) {
    if (Reflect.get(obj, i)) {
      obj = obj[i];
		
    }else{
		return false;
    }
  }
	return true;
}

var test = {level1:{level2:{level3:'level3'}} };

console.log('level1.level2.level3 => ',checkPathExist(test, 'level1.level2.level3')); // true
console.log( 'level1.level2.foo => ',checkPathExist(test, 'level1.level2.foo')); // false

Solution 51 - Javascript

Here's a little helper function I use that, to me, is pretty simple and straightforward. Hopefully it's helpful to some :).

static issetFromIndices(param, indices, throwException = false) {
    var temp = param;

    try {
        if (!param) {
            throw "Parameter is null.";
        }

        if(!Array.isArray(indices)) {
            throw "Indices parameter must be an array.";
        }

        for (var i = 0; i < indices.length; i++) {
            var index = indices[i];
            if (typeof temp[index] === "undefined") {
                throw "'" + index + "' index is undefined.";
            }


            temp = temp[index];
        }
    } catch (e) {
        if (throwException) {
            throw new Error(e);
        } else {
            return false;
        }
    }

    return temp;
}

var person = {
    hobbies: {
        guitar: {
            type: "electric"
        }
    }
};

var indices = ["hobbies", "guitar", "type"];
var throwException = true;

try {
    var hobbyGuitarType = issetFromIndices(person, indices, throwException);
    console.log("Yay, found index: " + hobbyGuitarType);
} catch(e) {
    console.log(e);
}

Solution 52 - Javascript

getValue (o, key1, key2, key3, key4, key5) {
    try {
      return o[key1][key2][key3][key4][key5]
    } catch (e) {
      return null
    }
}

Solution 53 - Javascript

There's a little pattern for this, but can get overwhelming at some times. I suggest you use it for two or three nested at a time.

if (!(foo.bar || {}).weep) return;
// Return if there isn't a 'foo.bar' or 'foo.bar.weep'.

As I maybe forgot to mention, you could also extend this further. Below example shows a check for nested foo.bar.weep.woop or it would return if none are available.

if (!((foo.bar || {}).weep || {}).woop) return;
// So, return if there isn't a 'foo.bar', 'foo.bar.weep', or 'foo.bar.weep.woop'.
// More than this would be overwhelming.

Solution 54 - Javascript

If you happen to be using AngularJs you can use the $parse service to check if a deep object property exists, like this:

if( $parse('model.data.items')(vm) ) {
    vm.model.data.items.push('whatever');
}

to avoid statements like this:

if(vm.model && vm.model.data && vm.model.data.items) {
    ....
}

don't forget to inject the $parse service into your controller

for more info: https://glebbahmutov.com/blog/angularjs-parse-hacks/

Solution 55 - Javascript

Quite a lot of answers but still: why not simpler?

An es5 version of getting the value would be:

function value(obj, keys) {
    if (obj === undefined) return obj;
    if (keys.length === 1 && obj.hasOwnProperty(keys[0])) return obj[keys[0]];
    return value(obj[keys.shift()], keys);
}

if (value(test, ['level1', 'level2', 'level3'])) {
  // do something
}

you could also use it with value(config, ['applet', i, 'height']) || 42

Credits to CMS for his ES6 solution that gave me this idea.

Solution 56 - Javascript

function propsExists(arg) {
  try {
    const result = arg()
  
    if (typeof result !== 'undefined') {
      return true
    }

    return false
  } catch (e) {
    return false;
  }
}

This function will also test for 0, null. If they are present it will also return true.

Example:

function propsExists(arg) {
  try {
    const result = arg()
  
    if (typeof result !== 'undefined') {
      return true
    }

    return false
  } catch (e) {
    return false;
  }
}

let obj = {
  test: {
    a: null,
    b: 0,
    c: undefined,
    d: 4,
    e: 'Hey',
    f: () => {},
    g: 5.4,
    h: false,
    i: true,
    j: {},
   	k: [],
    l: {
    	a: 1,
    }
  }
};


console.log('obj.test.a', propsExists(() => obj.test.a))
console.log('obj.test.b', propsExists(() => obj.test.b))
console.log('obj.test.c', propsExists(() => obj.test.c))
console.log('obj.test.d', propsExists(() => obj.test.d))
console.log('obj.test.e', propsExists(() => obj.test.e))
console.log('obj.test.f', propsExists(() => obj.test.f))
console.log('obj.test.g', propsExists(() => obj.test.g))
console.log('obj.test.h', propsExists(() => obj.test.h))
console.log('obj.test.i', propsExists(() => obj.test.i))
console.log('obj.test.j', propsExists(() => obj.test.j))
console.log('obj.test.k', propsExists(() => obj.test.k))
console.log('obj.test.l', propsExists(() => obj.test.l))

Solution 57 - Javascript

Simply use https://www.npmjs.com/package/js-aid package for checking for the nested object.

Solution 58 - Javascript

function getValue(base, strValue) {

    if(base == null) return;
    
    let currentKey = base;
    
    const keys = strValue.split(".");
    
    let parts;
    
    for(let i=1; i < keys.length; i++) {
        parts = keys[i].split("[");
        if(parts == null || parts[0] == null) return;
        let idx;
        if(parts.length > 1) { // if array
            idx = parseInt(parts[1].split("]")[0]);
            currentKey = currentKey[parts[0]][idx];
        } else {
            currentKey = currentKey[parts[0]];
        }
        if(currentKey == null) return;
    }
    return currentKey;
}

Calling the function returns either undefined, if result fails anywhere withing nesting or the value itself

const a = {
  b: {
    c: [
      {
        d: 25
      }
    ]
  }
}
console.log(getValue(a, 'a.b.c[1].d'))
// output
25

Solution 59 - Javascript

How about this function? Instead of needing to list each nested property separately, it maintains the 'dot' syntax (albeit in a string) making it more readable. It returns undefined or the specified default value if the property isn't found, or the value of the property if found.

val(obj, element, default_value)
	// Recursively checks whether a property of an object exists. Supports multiple-level nested properties separated with '.' characters.
	// obj = the object to test
	// element = (string or array) the name of the element to test for.  To test for a multi-level nested property, separate properties with '.' characters or pass as array)
	// default_value = optional default value to return if the item is not found. Returns undefined if no default_value is specified.
	// Returns the element if it exists, or undefined or optional default_value if not found.
	// Examples: val(obj1, 'prop1.subprop1.subsubprop2');
	// val(obj2, 'p.r.o.p', 'default_value');
	{

		// If no element is being requested, return obj. (ends recursion - exists)
		if (!element || element.length == 0) { return obj; }

		// if the element isn't an object, then it can't have properties. (ends recursion - does not exist)
		if (typeof obj != 'object') { return default_value; }

		// Convert element to array.
		if (typeof element == 'string') { element = element.split('.') };	// Split on dot (.)

		// Recurse into the list of nested properties:
		let first = element.shift();
		return val(obj[first], element, default_value);

	}

Solution 60 - Javascript

/**
 * @method getValue
 * @description simplifies checking for existance and getting a deeply nested value within a ceratin context
 * @argument {string} s       string representation of the full path to the requested property 
 * @argument {object} context optional - the context to check defaults to window
 * @returns the value if valid and set, returns undefined if invalid / not available etc.
 */
var getValue = function( s, context ){
    var fn = function(){
        try{
            return eval(s);
        }catch(e){
            return undefined;
        }
    }
    return fn.call(context||window,s);
}

and usage :

if( getValue('a[0].b[0].b[0].d') == 2 ) // true

Solution 61 - Javascript

Another way :

/**
 * This API will return particular object value from JSON Object hierarchy.
 *
 * @param jsonData : json type : JSON data from which we want to get particular object
 * @param objHierarchy : string type : Hierarchical representation of object we want to get,
 * 						 For example, 'jsonData.Envelope.Body["return"].patient' OR 'jsonData.Envelope.return.patient'
 * 						 Minimal Requirements : 'X.Y' required.
 * @returns evaluated value of objHierarchy from jsonData passed.
 */
function evalJSONData(jsonData, objHierarchy){
    
	if(!jsonData || !objHierarchy){
        return null;
    }
    
    if(objHierarchy.indexOf('["return"]') !== -1){
    	objHierarchy = objHierarchy.replace('["return"]','.return');
    }
    
    let objArray = objHierarchy.split(".");
    if(objArray.length === 2){
    	return jsonData[objArray[1]];
    }
    return evalJSONData(jsonData[objArray[1]], objHierarchy.substring(objHierarchy.indexOf(".")+1));
}

Solution 62 - Javascript

I automated the process

if(isset(object,["prop1","prop2"])){
// YES!

}

function isset(object, props){
	var dump;
	try {
		for(var x in props){
			if(x == 0) {
				dump = object[props[x]];
				return;
			}
			dump = dump[props[x]];
		}
	} catch(e) {
	    return false;
	}
	
	return true;
}

Solution 63 - Javascript

Just wrote this function today which does a deep search for a property in a nested object and returns the value at the property if found.

/**
 * Performs a deep search looking for the existence of a property in a 
 * nested object. Supports namespaced search: Passing a string with
 * a parent sub-object where the property key may exist speeds up
 * search, for instance: Say you have a nested object and you know for 
 * certain the property/literal you're looking for is within a certain
 * sub-object, you can speed the search up by passing "level2Obj.targetProp"
 * @param {object} obj Object to search
 * @param {object} key Key to search for
 * @return {*} Returns the value (if any) located at the key
 */
var getPropByKey = function( obj, key ) {
	var ret = false, ns = key.split("."),
		args = arguments,
		alen = args.length;
	
	// Search starting with provided namespace
	if ( ns.length > 1 ) {
		obj = (libName).getPropByKey( obj, ns[0] );
		key = ns[1];
	}
	
	// Look for a property in the object
	if ( key in obj ) {
		return obj[key];
	} else {
		for ( var o in obj ) {
			if ( (libName).isPlainObject( obj[o] ) ) {
				ret = (libName).getPropByKey( obj[o], key );
				if ( ret === 0 || ret === undefined || ret ) {
					return ret;
				}
			}
		}
	}
	
	return false;
}

Solution 64 - Javascript

In typeScript you can do something like this:

 if (object.prop1 && object.prop1.prop2 && object.prop1.prop2.prop3) {
    const items = object.prop1.prop2.prop3
    console.log(items);
 }

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionuser113716View Question on Stackoverflow
Solution 1 - JavascriptChristian C. SalvadóView Answer on Stackoverflow
Solution 2 - JavascriptGabe MoothartView Answer on Stackoverflow
Solution 3 - JavascriptAustin PrayView Answer on Stackoverflow
Solution 4 - JavascriptunitarioView Answer on Stackoverflow
Solution 5 - JavascriptkennebecView Answer on Stackoverflow
Solution 6 - JavascriptGajusView Answer on Stackoverflow
Solution 7 - Javascriptuser187291View Answer on Stackoverflow
Solution 8 - JavascriptGoran.itView Answer on Stackoverflow
Solution 9 - JavascriptFrank NockeView Answer on Stackoverflow
Solution 10 - JavascriptjrodeView Answer on Stackoverflow
Solution 11 - JavascriptDaniel BarralView Answer on Stackoverflow
Solution 12 - JavascriptVeganHunterView Answer on Stackoverflow
Solution 13 - JavascriptEndlessView Answer on Stackoverflow
Solution 14 - Javascriptkelvin kantariaView Answer on Stackoverflow
Solution 15 - Javascriptjfriend00View Answer on Stackoverflow
Solution 16 - JavascriptAlex MoldovanView Answer on Stackoverflow
Solution 17 - JavascriptV. SamborView Answer on Stackoverflow
Solution 18 - JavascriptmikemaccanaView Answer on Stackoverflow
Solution 19 - JavascriptNoah StahlView Answer on Stackoverflow
Solution 20 - JavascriptAnand SunderramanView Answer on Stackoverflow
Solution 21 - Javascriptuser1636522View Answer on Stackoverflow
Solution 22 - JavascriptBrian SidebothamView Answer on Stackoverflow
Solution 23 - JavascriptJulius MusseauView Answer on Stackoverflow
Solution 24 - JavascriptMike DView Answer on Stackoverflow
Solution 25 - JavascriptadutuView Answer on Stackoverflow
Solution 26 - JavascriptEgor StambakioView Answer on Stackoverflow
Solution 27 - JavascriptAnkit AryaView Answer on Stackoverflow
Solution 28 - JavascriptestaniView Answer on Stackoverflow
Solution 29 - Javascriptlahiru dilshanView Answer on Stackoverflow
Solution 30 - JavascriptBenView Answer on Stackoverflow
Solution 31 - JavascriptStephane LaFlècheView Answer on Stackoverflow
Solution 32 - JavascriptalejandroView Answer on Stackoverflow
Solution 33 - JavascriptJonathanView Answer on Stackoverflow
Solution 34 - JavascriptJuampy NRView Answer on Stackoverflow
Solution 35 - Javascriptwesley chaseView Answer on Stackoverflow
Solution 36 - JavascriptkubakozView Answer on Stackoverflow
Solution 37 - JavascriptpoolView Answer on Stackoverflow
Solution 38 - JavascriptDavidView Answer on Stackoverflow
Solution 39 - JavascriptJKSView Answer on Stackoverflow
Solution 40 - JavascriptJackView Answer on Stackoverflow
Solution 41 - Javascriptuser1636522View Answer on Stackoverflow
Solution 42 - JavascriptBartłomiej SzypelowView Answer on Stackoverflow
Solution 43 - JavascriptNicholas CloudView Answer on Stackoverflow
Solution 44 - JavascriptJFisherView Answer on Stackoverflow
Solution 45 - JavascriptdavewoodhallView Answer on Stackoverflow
Solution 46 - JavascriptPratyushView Answer on Stackoverflow
Solution 47 - Javascriptuser667540View Answer on Stackoverflow
Solution 48 - JavascriptzainengineerView Answer on Stackoverflow
Solution 49 - JavascriptTelmo DiasView Answer on Stackoverflow
Solution 50 - Javascriptabdolmajid azadView Answer on Stackoverflow
Solution 51 - JavascriptSchmeedtyView Answer on Stackoverflow
Solution 52 - Javascriptuser7188158View Answer on Stackoverflow
Solution 53 - JavascriptSmallyView Answer on Stackoverflow
Solution 54 - JavascriptMichielView Answer on Stackoverflow
Solution 55 - JavascriptiRaSView Answer on Stackoverflow
Solution 56 - JavascriptWalter MoneckeView Answer on Stackoverflow
Solution 57 - JavascriptHimanshu DhingraView Answer on Stackoverflow
Solution 58 - JavascriptVinit KhandelwalView Answer on Stackoverflow
Solution 59 - JavascriptRyan GriggsView Answer on Stackoverflow
Solution 60 - Javascriptuser4602228View Answer on Stackoverflow
Solution 61 - JavascriptRavi JiyaniView Answer on Stackoverflow
Solution 62 - JavascriptThe OrcaView Answer on Stackoverflow
Solution 63 - JavascriptXaxisView Answer on Stackoverflow
Solution 64 - JavascriptAbs0lemView Answer on Stackoverflow