Take the first command line argument and pass the rest
BashBash Problem Overview
Example:
check_prog hostname.com /bin/check_awesome -c 10 -w 13
check_remote -H $HOSTNAME -C "$ARGS"
#To be expanded as
check_remote -H hostname.com -C "/bin/check_awesome -c 10 -w 13"
I hope the above makes sense. The arguments will change as I will be using this for about 20+ commands. Its a odd method of wrapping a program, but it's to work around a few issues with a few systems we are using here (gotta love code from the 70s).
The above could be written in Perl or Python, but Bash would be the preferred method.
Bash Solutions
Solution 1 - Bash
You can use shift
shift is a shell builtin that operates on the positional parameters. Each time you invoke shift, it "shifts" all the positional parameters down by one. $2 becomes $1, $3 becomes $2, $4 becomes $3, and so on
example:
$ function foo() { echo $@; shift; echo $@; }
$ foo 1 2 3
1 2 3
2 3
Solution 2 - Bash
As a programmer I would strongly recommend against shift because operations that modify the state can affect large parts of a script and make it harder to understand, modify, and debug:sweat_smile:. You can instead use the following:
#!/usr/bin/env bash
all_args=("$@")
first_arg=$1
second_args=$2
rest_args=("${all_args[@]:2}")
echo "${rest_args[@]}"
Solution 3 - Bash
Adapting Abdullah's answer a bit:
your_command "$1" "${@:2}"
Tested on Bash (v3.2 and v5.1) and Zsh (v5.8)