super(type, obj): obj must be an instance or subtype of type

Why do I get the following error, and how do I resolve it?

> TypeError: super(type, obj): obj must be an instance or subtype of type

Another way this error can occur is when you reload the module with the class in a Jupiter notebook.

Easy solution is to restart the kernel.

http://thomas-cokelaer.info/blog/2011/09/382/

Check out @Mike W's answer for more detail.

You should call super using the UrlManager class as first argument not the URL model. super cannot called be with an unrelated class/type:

From the docs, > super(type[, object-or-type]): > Return a proxy object that delegates method calls to a parent or > sibling class of type.

So you cannot do:

>>> class D:
...    pass
... 
>>> class C:
...    def __init__(self):
...        super(D, self).__init__()
... 
>>> C()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in __init__
TypeError: super(type, obj): obj must be an instance or subtype of type

You should do:

qs_main = super(UrlManager, self).all(*args, **kwargs)

Or in Python 3:

qs_main = super().all(*args, **kwargs)

Elaborating in @Oğuz Şerbetci's answer, in python3 (not necessary only in Jupyter), when there is the need to reload a library, for example we have class Parent and class Child defined as

class Parent(object):
    def __init__(self):
        # do something

class Child(Parent):
    def __init__(self):
        super(Child, self).__init__(self)

then if you do this

import library.Child
reload(library)

Child()

you will get TypeError: super(type, obj): obj must be an instance or subtype of type, the solution is just to re import the class after the reload

import library.Child
reload(library)
import library.Child

Child()

For Jupyter only You can get his issue in because reload logic have some bugs (issue)

Here is a simple solution/workaround that works for me until issue is not fixed

1. Add typo like 1001xx at the bottom of the file which you call in the cell
2. Run your cell - you will see some exception, just skip it
3. Remove typo which was added on step 1
4. Run the cell
5. Profit

Another interesting way is if a merge of branches has duplicated the class, so that in the file you have two definitions for the same name, e.g.

class A(Foo):
    def __init__(self):
        super(A, self).__init__()
        #...

class A(Foo):
    def __init__(self):
        super(A, self).__init__()
        #...

If you try to create an instance from a static reference to the first definition of A, once it tries to call super, inside the __init__ method, A will refer to the second definition of A, since it has been overwritten. The solution - ofcourse - is to remove the duplicate definition of the class, so it doesn't get overwritten.

This may seem like something that would never happen, but it just happened to me, when I wasn't paying close enough attention to the merge of two branches. My tests failed with the error message described in the question, so I thought I'd leave my findings here, even though it doesn't exactly answer the specific question.

The best solution that I have found for this problem is only available using python 3. You then don't need to specify the arguments of "super", then you won't have the error any more writing your class like this :

class D:
   pass

class C(D):
    def __init__(self):
        super().__init__()# no arguments given to super()

This error also pops out when you simply do not instantiate child class , and try to call a method on a class itself, like in :

class Parent:
    def method():
        pass

class Child(Parent):
    def method():
        super().method()

P = Parent()
C = Child
C.method()