StaleElementReferenceException on Python Selenium
PythonHtmlSelenium WebdriverDomPython Problem Overview
I am getting the following error while using Selenium in python:
selenium.common.exceptions.StaleElementReferenceException: Message: u'stale element reference: element is not attached to the page document\n
Interestingly enough, the error pops up at different times in the for loop. Sometimes it gets through eg. 4 iterations and other times eg. 7.
Some of the relevant code being run is:
for i in range(0, 22):
u = driver.find_elements_by_id("data")
text = u[0].get_attribute("innerHTML")
driver.find_elements_by_class_name("aclassname")[0].click()
What does this error mean and what is something I can try to fix this?
Python Solutions
Solution 1 - Python
It means the element is no longer in the DOM, or it changed.
The following code will help you find the element by controlling and ignoring StaleElementExceptions and handling them just like any other NoSuchElementException. It waits for the element to NOT be stale, just like it waits for the element to be present. It also serves as a good example on how to properly wait for conditions in Selenium.
from selenium.common.exceptions import NoSuchElementException
from selenium.common.exceptions import StaleElementReferenceException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions
my_element_id = 'something123'
ignored_exceptions=(NoSuchElementException,StaleElementReferenceException,)
your_element = WebDriverWait(your_driver, some_timeout,ignored_exceptions=ignored_exceptions)\
.until(expected_conditions.presence_of_element_located((By.ID, my_element_id)))
To better understand the problem, imagine you are inside a for loop and think what happens during the iterations:
- something changes when you click on the element (last line)
- So the page is changing
- You enter the next iteration. Now are trying to find a new element (your first line inside the loop).
- You found the element
- It finishes changing
- You try to use it by getting an attribute
- Bam! The element is old. You got it in step 4, but it finished changing on step 5
Solution 2 - Python
Selenium Support Explicit
and Implicit
Waits. If you think waiting for certain amount of time is enough for your page to be loaded, use:
driver.implicitly_wait(secs)
but if you want to wait for a special event (e.g. waiting for a particular element to be loaded) you can do something like:
from selenium.webdriver.support.ui import WebDriverWait
...
...
def find(driver):
element = driver.find_elements_by_id("data")
if element:
return element
else:
return False
element = WebDriverWait(driver, secs).until(find)
Solution 3 - Python
Beyond the answers here, if you are using ActionChains, and the page has changed, be sure to reinstantiate your ActionChains object (dont reuse an old one), otherwise your ActionChain will be using a stale DOM. I.e. do this;
action_chain = ActionChains(driver)
action_chain.double_click(driver.find_element_by_xpath("//tr[2]/p")).perform()
Or better yet dont use an instantiation;
ActionChains(driver).double_click(driver.find_element_by_xpath("//tr[2]/p")).perform()
Solution 4 - Python
For my python scripts, on quite simple pages, all above mentioned solutions didn't work. I found here -> https://www.softwaretestingmaterial.com/stale-element-reference-exception-selenium-webdriver/ the simplest way for my problem. It's just refreshing before clicking.
driver.refresh()
driver.find_element_by_id('normal').click()
Note: I'm using driver.implicitly_wait(5)
instead of explicit waits but it works in both options.
Solution 5 - Python
>>>Stale Exceptions can be handled using **StaleElementReferenceException** to continue the for loop execution.
from selenium.common import exceptions
# and customize your code of for loop as:
for i in range(0, 22):
try:
u = driver.find_elements_by_id("data")
text = u[0].get_attribute("innerHTML")
driver.find_elements_by_class_name("aclassname")[0].click()
except exceptions.StaleElementReferenceException,e:
print(e)
pass
Note: Python 3+ : replace exceptions.StaleElementReferenceException,e -> exceptions.StaleElementReferenceException as e
Solution 6 - Python
I Would like to add one more solution here which is worked for me.
I was trying to access the button in the top menu panel on my webpage after refreshing the content area on the same page, Which gave me the following error,
raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.StaleElementReferenceException: Message: The element reference of <span id="dk1-combobox" class="dk-selected combinationText visibleElements "> is stale; either the element is no longer attached to the DOM, it is not in the current frame context, or the document has been refreshed
Then I started to search for the solution to click the stale element on the web page. After two days of thinking and googling, I got a solution.
To access the stale element on the page, first, we need to focus the mouse over the particular section and perform click option
EditReport1 = driver.find_element_by_id('internalTab1')
ActionChains(driver).move_to_element(EditReport1).click(EditReport1).perform()
move_to_element will move the mouse over the stale element which we need to access once we got our control on the element the click operation is successfully performed.
This is worked for me. If anyone finds it working please comment your's as well which will help some other in future.
Thank you
Solution 7 - Python
When webpage got refreshed or switched back from different window or form and trying to access an element user will get staleelementexception.
Use webdriverwait in try --except block with for loop: EX : Code in which I got staleelementexception :
driver.find_element_by_id(tc.value).click()
driver.find_element_by_xpath("xpath").click()
Fix :
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver.find_element_by_id(tc.value).click()
for i in range(4):
try:
run_test = WebDriverWait(driver, 120).until( \
EC.presence_of_element_located((By.XPATH, "xpath")))
run_test.click()
break
except StaleElementReferenceException as e:
raise e
Solution 8 - Python
In my case, the problem
> stale element reference: element is not attached to the page document
was because I tried to use
actions.move_to_element(element).perform()
on actions that created from old Selenium tab.
So the solution is to create new actions instance after opening new tab:
actions = ActionChains(browser)
actions.move_to_element(element).perform()
Solution 9 - Python
One scenario in my case : I queryed the element once , and assign it to an variable for reusage,
captchaInput = driver.find_element_by_css_selector('input[name="CaptchaCode"]')
then it runs the risk of StaleElementReferenceException
, querying the element again with the above code help eliminate the exception.
Solution 10 - Python
This is the python solution for this problem:
def clickAndCatchStaleRefException(locator):
driver = sel2._current_browser()
result = False
attempts = 0
locator = locator[6:]
# This line is optional because sometimes you pass a xpath from a varibles file
# that starts with 'xpath='. This should be omitted otherwise the find_element_by_xpath
# function will throw an error.
# But if you pass an xpath directly you don't need this
while attempts < 2:
try:
driver.find_element_by_xpath(locator).click()
result = True
break
except EC as e:
raise e
finally:
attempts += 1
return result
Solution 11 - Python
from selenium.webdriver.support.expected_conditions import staleness_of
Import above saved the day for me.
Solution 12 - Python
It depends on the Website you are working with.
If you have a Website, that doesn't change itself, use Emilio's answer. WebDriverWait(...).until(...) is the correct / best solution for Websites, that don't change by themselves (and only by user interactions):
WebDriverWait(driver, delay, ignored_exceptions=(NoSuchElementException,StaleElementReferenceException)).until(expected_conditions.presence_of_element_located((By.ID, "my_id"))).click()
(For explanation see Emilio's answer)
If you work with a site, that changes by pushs from server or time based or something similar, the only working solution is retrying like in Rashids answer.
def retry_func(func, max_tries=MAX_TRIES):
for i in range(max_tries):
try:
return func()
except Exception as e:
if i >= max_tries - 1:
raise e
def click_button_helper(driver, selector, selector_type=By.XPATH, delay=DELAY, ignored_exceptions=IGNORED_EXCEPTIONS):
WebDriverWait(driver, delay, ignored_exceptions=ignored_exceptions).until(
EC.presence_of_element_located((selector_type, selector))).click()
def click_button(driver, selector, selector_type=By.XPATH, delay=DELAY, ignored_exceptions=IGNORED_EXCEPTIONS,
max_tries=MAX_TRIES):
retry_func(lambda: click_button_helper(driver, selector, selector_type, delay, ignored_exceptions), max_tries)
Because, sorry @Emilio, your answer doesn't address specific cases like the one Sylvan LE DEUNFF mentioned.
The following race condition is still possible (and not solved by WebDriverWait(...).until(...), but usually by retrying):
- The page is changing (e.g. after a click like in the question)
- We are trying to find the element.
- WebDriverWait(...).until(...) waits for us till our expected_conditions are fullfilled (so basically till it finishes changing)
- We found the element
- It starts changing again (by push, by reaching timestep, ...)
- We try to use it
- Bam! The element is old again.
Solution 13 - Python
I was getting the exception on trying to click multiple classes with the same name.
for i in range(0, 5):
actions = ActionChains(driver)
button = driver.find_element_by_class_name('dlJyA')
time.sleep(2)
if button.is_displayed():
actions.click(on_element=button).perform()
I fixed it by using time.sleep and checking if the button is displayed.
Solution 14 - Python
In my case, I tried to find element, then pass it to another class constructor for reuse. when I call 'click' on it - I got StaleException
So I've just pass css class to constructor instead of object and find element in new class
Solution 15 - Python
Adding time.sleep(3)
resolved the issue for me.
for i in range(0, 22):
u = driver.find_elements_by_id("data")
text = u[0].get_attribute("innerHTML")
driver.find_elements_by_class_name("aclassname")[0].click()
time.sleep(3)
Solution 16 - Python
Happened to me too in a while loop. Simple solution was just to wait until the element is stale before setting the variable again. Works like that:
if not first:
WebDriverWait(driver, 10).until(EC.staleness_of(Element))
Element = ...
Solution 17 - Python
I've resolved the issue by setting the variable at the start of the while loop:
should_continue = True
while should_continue:
driver.find_elements(By.CSS_SELECTOR, ".grayed b")
Solution 18 - Python
I am aware this is an old question, but depending on your purpose for using selenium, I use to different solutions. I the task is for webscraping I have the body of the webpage after all the javascript I need run have finished, and a BeautifulSoup object.
BeautifulSoup(webdriver.find_element_by_tag_name('body').get_attribute('innerHTML'))
The second is to use the Page Object Model (POM). See the link https://www.lambdatest.com/blog/page-object-model-in-selenium-python/