SQLite DateTime comparison

SqlSqlite

Sql Problem Overview


I can't seem to get reliable results from the query against a sqlite database using a datetime string as a comparison as so:

select * 
  from table_1 
 where mydate >= '1/1/2009' and mydate <= '5/5/2009'

how should I handle datetime comparisons to sqlite?

update: field mydate is a DateTime datatype

Sql Solutions


Solution 1 - Sql

To solve this problem, I store dates as YYYYMMDD. Thus, where mydate >= '20090101' and mydate <= '20050505'

It just plain WORKS all the time. You may only need to write a parser to handle how users might enter their dates so you can convert them to YYYYMMDD.

Solution 2 - Sql

SQLite doesn't have dedicated datetime types, but does have a few datetime functions. Follow the string representation formats (actually only formats 1-10) understood by those functions (storing the value as a string) and then you can use them, plus lexicographical comparison on the strings will match datetime comparison (as long as you don't try to compare dates to times or datetimes to times, which doesn't make a whole lot of sense anyway).

Depending on which language you use, you can even get automatic conversion. (Which doesn't apply to comparisons in SQL statements like the example, but will make your life easier.)

Solution 3 - Sql

I had the same issue recently, and I solved it like this:

SELECT * FROM table WHERE 
    strftime('%s', date) BETWEEN strftime('%s', start_date) AND strftime('%s', end_date)

Solution 4 - Sql

The following is working fine for me using SQLite:

SELECT * 
    FROM ingresosgastos 
    WHERE fecharegistro BETWEEN "2010-01-01" AND "2013-01-01"

Solution 5 - Sql

Following worked for me.

SELECT *
FROM table_log
WHERE DATE(start_time) <= '2017-01-09' AND DATE(start_time) >= '2016-12-21'

Solution 6 - Sql

Sqlite can not compare on dates. we need to convert into seconds and cast it as integer.

Example

SELECT * FROM Table  
WHERE  
CAST(strftime('%s', date_field)  AS  integer) <=CAST(strftime('%s', '2015-01-01')  AS  integer) ;

Solution 7 - Sql

I have a situation where I want data from up to two days ago and up until the end of today. I arrived at the following.

WHERE dateTimeRecorded between date('now', 'start of day','-2 days') 
                           and date('now', 'start of day', '+1 day') 

Ok, technically I also pull in midnight on tomorrow like the original poster, if there was any data, but my data is all historical.

The key thing to remember, the initial poster excluded all data after 2009-11-15 00:00:00. So, any data that was recorded at midnight on the 15th was included but any data after midnight on the 15th was not. If their query was,

select * 
  from table_1 
  where mydate between Datetime('2009-11-13 00:00:00') 
                   and Datetime('2009-11-15 23:59:59')

Use of the between clause for clarity.

It would have been slightly better. It still does not take into account leap seconds in which an hour can actually have more than 60 seconds, but good enough for discussions here :)

Solution 8 - Sql

I had to store the time with the time-zone information in it, and was able to get queries working with the following format:

"SELECT * FROM events WHERE datetime(date_added) BETWEEN 
      datetime('2015-03-06 20:11:00 -04:00') AND datetime('2015-03-06 20:13:00 -04:00')"

The time is stored in the database as regular TEXT in the following format:

2015-03-06 20:12:15 -04:00

Solution 9 - Sql

Below are the methods to compare the dates but before that we need to identify the format of date stored in DB

I have dates stored in MM/DD/YYYY HH:MM format so it has to be compared in that format

  1. Below query compares the convert the date into MM/DD/YYY format and get data from last five days till today. BETWEEN operator will help and you can simply specify start date AND end date.

     select * from myTable where myColumn BETWEEN strftime('%m/%d/%Y %H:%M', datetime('now','localtime'), '-5 day') AND strftime('%m/%d/%Y %H:%M',datetime('now','localtime')); 
    
  2. Below query will use greater than operator (>).

   select * from myTable where myColumn > strftime('%m/%d/%Y %H:%M', datetime('now','localtime'), '-5 day');   

All the computation I have done is using current time, you can change the format and date as per your need.

Hope this will help you

Summved

Solution 10 - Sql

Right now i am developing using System.Data.SQlite NuGet package (version 1.0.109.2). Which using SQLite version 3.24.0.

And this works for me.

SELECT * FROM tables WHERE datetime 
BETWEEN '2018-10-01 00:00:00' AND '2018-10-10 23:59:59';

I don't need to use the datetime() function. Perhaps they already updated the SQL query on that SQLite version.

Solution 11 - Sql

You could also write up your own user functions to handle dates in the format you choose. SQLite has a fairly simple method for writing your own user functions. For example, I wrote a few to add time durations together.

Solution 12 - Sql

My query I did as follows:

SELECT COUNT(carSold) 
FROM cars_sales_tbl
WHERE date
BETWEEN '2015-04-01' AND '2015-04-30'
AND carType = "Hybrid"

I got the hint by @ifredy's answer. The all I did is, I wanted this query to be run in iOS, using Objective-C. And it works!

Hope someone who does iOS Development, will get use out of this answer too!

Solution 13 - Sql

Here is a working example in C# in three ways:

  string tableName = "TestTable";

  var startDate = DateTime.Today.ToString("yyyy-MM-dd 00:00:00"); \\From today midnight
  var endDate = date.AddDays(1).ToString("yyyy-MM-dd HH:mm:ss"); \\ Whole day

  string way1 /*long way*/ = $"SELECT * FROM {tableName} WHERE strftime(\'%s\', DateTime) 
  BETWEEN strftime('%s', \'{startDate}\') AND strftime('%s', \'{endDate}\')";
  
  string way2= $"SELECT * FROM {tableName} WHERE DateTime BETWEEN \'{startDate}\' AND \'{endDate}\'";

  string way3= $"SELECT * FROM {tableName} WHERE DateTime >= \'{startDate}\' AND DateTime <=\'{endDate}\'";

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionBradView Question on Stackoverflow
Solution 1 - SqlMark SmithView Answer on Stackoverflow
Solution 2 - SqlRoger PateView Answer on Stackoverflow
Solution 3 - SqlSimonView Answer on Stackoverflow
Solution 4 - SqlifredyView Answer on Stackoverflow
Solution 5 - SqlJose Jithin StanlyView Answer on Stackoverflow
Solution 6 - SqlHardeep SinghView Answer on Stackoverflow
Solution 7 - SqlLyall PearceView Answer on Stackoverflow
Solution 8 - SqlEternal21View Answer on Stackoverflow
Solution 9 - SqlSummved JainView Answer on Stackoverflow
Solution 10 - SqlArumanView Answer on Stackoverflow
Solution 11 - SqlJ. PolferView Answer on Stackoverflow
Solution 12 - SqlRandika VishmanView Answer on Stackoverflow
Solution 13 - SqlA. DzeboView Answer on Stackoverflow