SQLAlchemy equivalent to SQL "LIKE" statement
PythonSqlalchemyPython Problem Overview
A tags column has values like "apple banana orange" and "strawberry banana lemon". I want to find the SQLAlchemy equivalent statement to
SELECT * FROM table WHERE tags LIKE "%banana%";
What should I pass to Class.query.filter() to do this?
Python Solutions
Solution 1 - Python
Each column has like() method, which can be used in query.filter(). Given a search string, add a % character on either side to search as a substring in both directions.
tag = request.form["tag"]
search = "%{}%".format(tag)
posts = Post.query.filter(Post.tags.like(search)).all()
Solution 2 - Python
Adding to the above answer, whoever looks for a solution, you can also try 'match' operator instead of 'like'. Do not want to be biased but it perfectly worked for me in Postgresql.
Note.query.filter(Note.message.match("%somestr%")).all()
It inherits database functions such as CONTAINS and MATCH. However, it is not available in SQLite.
For more info go Common Filter Operators
Solution 3 - Python
try this code
output = dbsession.query(<model_class>).filter(<model_calss>.email.ilike('%' + < email > + '%'))
Solution 4 - Python
In case you want the case insensitive like clause implementation:
session.query(TableName).filter(TableName.colName.ilike(f'%{search_text}%')).all()
Solution 5 - Python
If you use native sql, you can refer to my code, otherwise just ignore my answer.
SELECT * FROM table WHERE tags LIKE "%banana%";
from sqlalchemy import text
bar_tags = "banana"
# '%' attention to spaces
query_sql = """SELECT * FROM table WHERE tags LIKE '%' :bar_tags '%'"""
# db is sqlalchemy session object
tags_res_list = db.execute(text(query_sql), {"bar_tags": bar_tags}).fetchall()
Solution 6 - Python
Using PostgreSQL like (see accepted answer above) somehow didn't work for me although cases matched, but ilike (case insensisitive like) does.
Solution 7 - Python
In SQLAlchemy 1.4/2.0:
q = session.query(User).filter(User.name.like('e%'))