SQL - Update multiple records in one query

Mysql Problem Overview

I have table - config. Schema: config_name | config_value

And I would like to update multiple records in one query. I try like that:

UPDATE config 
SET t1.config_value = 'value'
  , t2.config_value = 'value2' 
WHERE t1.config_name = 'name1' 
  AND t2.config_name = 'name2';

but that query is wrong :(

Can you help me?

Mysql Solutions

Solution 1 - Mysql

Try either multi-table update syntax

UPDATE config t1 JOIN config t2
    ON t1.config_name = 'name1' AND t2.config_name = 'name2'
   SET t1.config_value = 'value',
       t2.config_value = 'value2';

Here is a SQLFiddle demo

or conditional update

UPDATE config
   SET config_value = CASE config_name 
                      WHEN 'name1' THEN 'value' 
                      WHEN 'name2' THEN 'value2' 
                      ELSE config_value
                      END
 WHERE config_name IN('name1', 'name2');

Here is a SQLFiddle demo

Solution 2 - Mysql

You can accomplish it with INSERT as below:

INSERT INTO mytable (id, a, b, c)
VALUES (1, 'a1', 'b1', 'c1'),
(2, 'a2', 'b2', 'c2'),
(3, 'a3', 'b3', 'c3'),
(4, 'a4', 'b4', 'c4'),
(5, 'a5', 'b5', 'c5'),
(6, 'a6', 'b6', 'c6')
ON DUPLICATE KEY UPDATE id=VALUES(id),
a=VALUES(a),
b=VALUES(b),
c=VALUES(c);

This insert new values into table, but if primary key is duplicated (already inserted into table) that values you specify would be updated and same record would not be inserted second time.

Solution 3 - Mysql

in my case I have to update the records which are more than 1000, for this instead of hitting the update query each time I preferred this,

   UPDATE mst_users 
   SET base_id = CASE user_id 
   WHEN 78 THEN 999 
   WHEN 77 THEN 88 
   ELSE base_id END WHERE user_id IN(78, 77)

78,77 are the user Ids and for those user id I need to update the base_id 999 and 88 respectively.This works for me.

Solution 4 - Mysql

instead of this

UPDATE staff SET salary = 1200 WHERE name = 'Bob';
UPDATE staff SET salary = 1200 WHERE name = 'Jane';
UPDATE staff SET salary = 1200 WHERE name = 'Frank';
UPDATE staff SET salary = 1200 WHERE name = 'Susan';
UPDATE staff SET salary = 1200 WHERE name = 'John';

you can use

UPDATE staff SET salary = 1200 WHERE name IN ('Bob', 'Frank', 'John');

Solution 5 - Mysql

maybe for someone it will be useful

for Postgresql 9.5 works as a charm

INSERT INTO tabelname(id, col2, col3, col4)
VALUES
	(1, 1, 1, 'text for col4'),
	(DEFAULT,1,4,'another text for col4')
ON CONFLICT (id) DO UPDATE SET
	col2 = EXCLUDED.col2,
	col3 = EXCLUDED.col3,
	col4 = EXCLUDED.col4

this SQL updates existing record and inserts if new one (2 in 1)

Solution 6 - Mysql

Camille's solution worked. Turned it into a basic PHP function, which writes up the SQL statement. Hope this helps someone else.

    function _bulk_sql_update_query($table, $array)
    {
        /*
         * Example:
        INSERT INTO mytable (id, a, b, c)
        VALUES (1, 'a1', 'b1', 'c1'),
        (2, 'a2', 'b2', 'c2'),
        (3, 'a3', 'b3', 'c3'),
        (4, 'a4', 'b4', 'c4'),
        (5, 'a5', 'b5', 'c5'),
        (6, 'a6', 'b6', 'c6')
        ON DUPLICATE KEY UPDATE id=VALUES(id),
        a=VALUES(a),
        b=VALUES(b),
        c=VALUES(c);
    */
        $sql = "";

        $columns = array_keys($array[0]);
        $columns_as_string = implode(', ', $columns);

        $sql .= "
      INSERT INTO $table
      (" . $columns_as_string . ")
      VALUES ";

        $len = count($array);
        foreach ($array as $index => $values) {
            $sql .= '("';
            $sql .= implode('", "', $array[$index]) . "\"";
            $sql .= ')';
            $sql .= ($index == $len - 1) ? "" : ", \n";
        }

        $sql .= "\nON DUPLICATE KEY UPDATE \n";

        $len = count($columns);
        foreach ($columns as $index => $column) {

            $sql .= "$column=VALUES($column)";
            $sql .= ($index == $len - 1) ? "" : ", \n";
        }

        $sql .= ";";

        return $sql;
    }

Solution 7 - Mysql

Execute the code below to update n number of rows, where Parent ID is the id you want to get the data from and Child ids are the ids u need to be updated so it's just u need to add the parent id and child ids to update all the rows u need using a small script.

 UPDATE [Table]
 SET column1 = (SELECT column1 FROM Table WHERE IDColumn = [PArent ID]),
     column2 = (SELECT column2 FROM Table WHERE IDColumn = [PArent ID]),
     column3 = (SELECT column3 FROM Table WHERE IDColumn = [PArent ID]),
     column4 = (SELECT column4 FROM Table WHERE IDColumn = [PArent ID]),
 WHERE IDColumn IN ([List of child Ids])

Solution 8 - Mysql

Execute the below code if you want to update all record in all columns:

update config set column1='value',column2='value'...columnN='value';

and if you want to update all columns of a particular row then execute below code:

update config set column1='value',column2='value'...columnN='value' where column1='value'

Solution 9 - Mysql

Assuming you have the list of values to update in an Excel spreadsheet with config_value in column A1 and config_name in B1 you can easily write up the query there using an Excel formula like

=CONCAT("UPDATE config SET config_value = ","'",A1,"'", " WHERE config_name = ","'",B1,"'")

Solution 10 - Mysql

INSERT INTO tablename
    (name, salary)
    VALUES 
        ('Bob', 1125),
        ('Jane', 1200),
        ('Frank', 1100),
        ('Susan', 1175),
        ('John', 1150)
        ON DUPLICATE KEY UPDATE salary = VALUES(salary);

Solution 11 - Mysql

UPDATE 2021 / MySql v8.0.20 and later

The most upvoted answer advises to use the VALUES function which is now DEPRECATED for the ON DUPLICATE KEY UPDATE syntax. With v8.0.20 you get a deprecation warning with the VALUES function:

INSERT INTO chart (id, flag)
VALUES (1, 'FLAG_1'),(2, 'FLAG_2')
ON DUPLICATE KEY UPDATE id = VALUES(id), flag = VALUES(flag);

> [HY000][1287] 'VALUES function' is deprecated and will be removed in a future release. Please use an alias (INSERT INTO ... VALUES (...) AS alias) and replace VALUES(col) in the ON DUPLICATE KEY UPDATE clause with alias.col instead

Use the new alias syntax instead:

INSERT INTO chart (id, flag) 
VALUES (1, 'FLAG_1'),(2, 'FLAG_2') AS aliased
ON DUPLICATE KEY UPDATE flag=aliased.flag;

Solution 12 - Mysql