SQL Server Convert Varchar to Datetime
SqlSql ServerDatetimeFormattingVarcharSql Problem Overview
I have this date format: 2011-09-28 18:01:00 (in varchar), and I want to convert it to datetime changing to this format 28-09-2011 18:01:00. How can I do it?
Sql Solutions
Solution 1 - Sql
SELECT CONVERT(Datetime, '2011-09-28 18:01:00', 120) -- to convert it to Datetime
SELECT CONVERT( VARCHAR(30), @date ,105) -- italian format [28-09-2011 18:01:00]
+ ' ' + SELECT CONVERT( VARCHAR(30), @date ,108 ) -- full date [with time/minutes/sec]
Solution 2 - Sql
Like this
DECLARE @date DATETIME
SET @date = '2011-09-28 18:01:00'
select convert(varchar, @date,105) + ' ' + convert(varchar, @date,108)
Solution 3 - Sql
Solution 4 - Sql
You can have all the different styles to datetime conversion :
https://www.w3schools.com/sql/func_sqlserver_convert.asp
This has range of values :-
CONVERT(data_type(length),expression,style)
For style values,
Choose anyone you need like I needed 106.
Solution 5 - Sql
Try the below
select Convert(Varchar(50),yourcolumn,103) as Converted_Date from yourtbl
Solution 6 - Sql
You could do it this way but it leaves it as a varchar
declare @s varchar(50)
set @s = '2011-09-28 18:01:00'
select convert(varchar, cast(@s as datetime), 105) + RIGHT(@s, 9)
or
select convert(varchar(20), @s, 105)
Solution 7 - Sql
As has been said, datetime has no format/string representational format.
You can change the string output with some formatting.
To convert your string to a datetime:
declare @date nvarchar(25)
set @date = '2011-09-28 18:01:00'
-- To datetime datatype
SELECT CONVERT(datetime, @date)
Gives:
-----------------------
2011-09-28 18:01:00.000
(1 row(s) affected)
To convert that to the string you want:
-- To VARCHAR of your desired format
SELECT CONVERT(VARCHAR(10), CONVERT(datetime, @date), 105) +' '+ CONVERT(VARCHAR(8), CONVERT(datetime, @date), 108)
Gives:
-------------------
28-09-2011 18:01:00
(1 row(s) affected)
Solution 8 - Sql
SELECT CONVERT(VARCHAR(10), GETDATE(), 105) + ' ' + CONVERT(VARCHAR(10), GETDATE(), 108)
Solution 9 - Sql
I got tired of all the different convert googling, ended up with this utility function that is expanded upon new variations.
CREATE FUNCTION [dbo].[ParseDatetime] (
@INPUT nvarchar(255),
@FORMAT nvarchar(255)
)
RETURNS datetime
AS
BEGIN
DECLARE @TimePart NVARCHAR(255)
DECLARE @DatePart NVARCHAR(255)
DECLARE @DayPart NVARCHAR(255)
DECLARE @ExDayPart NVARCHAR(255)
DECLARE @MonthPart NVARCHAR(255)
DECLARE @YearPart NVARCHAR(255)
DECLARE @Date DATETIME
--DECLARE @INPUTSTRING NVARCHAR(255)
--SET @INPUTSTRING = '20-10-2019 00:00:00'
--SET @FORMAT = 'D-M-YYYY HH:MM:SS'
IF(@FORMAT = 'D-M-YYYY HH:MM:SS')
BEGIN
SET @TimePart = RIGHT(@INPUT,LEN(@INPUT)-CHARINDEX(' ',@INPUT))
SET @DatePart = LEFT(@INPUT,CHARINDEX(' ',@INPUT))
SET @DayPart = LEFT(@DatePart,charindex('-',@DatePart)-1)
SET @ExDayPart = RIGHT(@DatePart,LEN(@DatePart)-charindex('-',@DatePart)+1)
SET @MonthPart = left(@ExDayPart ,charindex('-',@ExDayPart )-1)
SET @YearPart = right(@ExDayPart ,LEN(@ExDayPart )-charindex('-',@ExDayPart )+1)
SET @Date = DATEFROMPARTS(@YearPart,@MonthPart,@DayPart)
END
IF(@FORMAT = 'YYYY-MM-DD')
BEGIN
SET @DayPart = RIGHT(@INPUT,2)
SET @MonthPart = RIGHT(left(@INPUT,7),2)
SET @YearPart = LEFT(@INPUT,4)
SET @Date = DATEFROMPARTS(@YearPart,@MonthPart,@DayPart)
END
IF(@FORMAT = 'EXCEL_DAYS_SINCE_1900')
BEGIN
--DECLARE @INPUT NVARCHAR(255)
--SET @INPUT = ' 43554'
SET @Date = Dateadd(day,CAST(@INPUT AS INT),datefromparts(1900,1,1))
END
RETURN @Date
END
GO
Use it as:
SELECT
[DateAsDate] = dbo.[ParseDateTime]([DateAsString], 'YYYY-MM-DD')
FROM [tablename]