SQL query for a carriage return in a string and ultimately removing carriage return

SQL query for a carriage return in a string and ultimately removing carriage return

I have some data in a table and there are some carriage returns in places where I don't want them. I am trying to write a query to get all of the strings that contain carriage returns.

I tried this

select * from Parameters
where Name LIKE '%"\n" %'

Also

select * from Parameters
where Name LIKE '\r'

'

Both are valid SQL but are not returning what I am looking for. Do I need to use the Like command or a different command? How do I get the carriage return into the query?

The carriage return is not necessarily at the end of the line either (may be in the middle).

this will be slow, but if it is a one time thing, try...

select * from parameters where name like '%'+char(13)+'%' or name like '%'+char(10)+'%'

Note that the ANSI SQL string concatenation operator is "||", so it may need to be:

select * from parameters where name like '%' || char(13) || '%' or name like '%' || char(10) || '%'

The main question was to remove the CR/LF. Using the replace and char functions works for me:

Select replace(replace(Name,char(10),''),char(13),'')

For Postgres or Oracle SQL, use the CHR function instead:

       replace(replace(Name,CHR(10),''),CHR(13),'')

In SQL Server I would use:

WHERE CHARINDEX(CHAR(13), name) <> 0 OR CHARINDEX(CHAR(10), name) <> 0

This will search for both carriage returns and line feeds.

If you want to search for tabs too just add:

OR CHARINDEX(CHAR(9), name) <> 0

You can also use regular expressions:

SELECT * FROM Parameters WHERE Name REGEXP '\n';

this works: select * from table where column like '%(hit enter)%'

Ignore the brackets and hit enter to introduce new line.

You can create a function:

CREATE FUNCTION dbo.[Check_existance_of_carriage_return_line_feed]
(
      @String VARCHAR(MAX)
)
RETURNS VARCHAR(MAX)
BEGIN
DECLARE @RETURN_BOOLEAN INT
 
;WITH N1 (n) AS (SELECT 1 UNION ALL SELECT 1),
N2 (n) AS (SELECT 1 FROM N1 AS X, N1 AS Y),
N3 (n) AS (SELECT 1 FROM N2 AS X, N2 AS Y),
N4 (n) AS (SELECT ROW_NUMBER() OVER(ORDER BY X.n)
FROM N3 AS X, N3 AS Y)
 
SELECT @RETURN_BOOLEAN =COUNT(*)
FROM N4 Nums
WHERE Nums.n<=LEN(@String) AND ASCII(SUBSTRING(@String,Nums.n,1)) 
IN (13,10)    
 
RETURN (CASE WHEN @RETURN_BOOLEAN >0 THEN 'TRUE' ELSE 'FALSE' END)
END
GO

Then you can simple run a query like this:

SELECT column_name, dbo.[Check_existance_of_carriage_return_line_feed] (column_name)
AS [Boolean]
FROM [table_name]

Omit the double quotes from your first query.

... LIKE '%\n%' 

Something like this seems to work for me:

SELECT * FROM Parameters WHERE Name LIKE '%\n%'

This also works

SELECT TRANSLATE(STRING_WITH_NL_CR, CHAR(10) || CHAR(13), '  ') FROM DUAL;

If you are considering creating a function, try this: DECLARE @schema sysname = 'dbo' , @tablename sysname = 'mvtEST' , @cmd NVarchar(2000) , @ColName sysname

    DECLARE @NewLine Table
    (ColumnName Varchar(100)
    ,Location Int
    ,ColumnValue Varchar(8000)
    )
    
    SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE  TABLE_SCHEMA = @schema AND TABLE_NAME =  @tablename AND DATA_TYPE LIKE '%CHAR%'
    
    DECLARE looper CURSOR FAST_FORWARD for
    SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = @schema AND TABLE_NAME =  @tablename AND DATA_TYPE LIKE '%CHAR%'
    OPEN looper
    FETCH NEXT FROM looper INTO @ColName
    
    WHILE @@fetch_status = 0
    BEGIN
    SELECT @cmd = 'select ''' +@ColName+    ''',  CHARINDEX(Char(10),  '+  @ColName +') , '+ @ColName + ' from '+@schema + '.'+@tablename +' where CHARINDEX(Char(10),  '+  @ColName +' ) > 0 or CHARINDEX(CHAR(13), '+@ColName +') > 0'
    PRINT @cmd
    INSERT @NewLine ( ColumnName, Location, ColumnValue )
    EXEC sp_executesql @cmd
    FETCH NEXT FROM looper INTO @ColName
    end
    CLOSE looper
    DEALLOCATE looper
    
    
    SELECT * FROM  @NewLine