Spring Data and Native Query with pagination

SpringSpring DataSpring Data-Jpa

Spring Problem Overview


In a web project, using latest spring-data (1.10.2) with a MySQL 5.6 database, I'm trying to use a native query with pagination but I'm experiencing an org.springframework.data.jpa.repository.query.InvalidJpaQueryMethodException at startup.

According to Example 50 at Using @Query from spring-data documentation this is possible specifying the query itself and a countQuery, like this:

public interface UserRepository extends JpaRepository<User, Long> {
  @Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1",
    countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
    nativeQuery = true)
  Page<User> findByLastname(String lastname, Pageable pageable);
}

Out of curiosity, In NativeJpaQuery class I can see that it contains the following code to check if it's a valid jpa query:

public NativeJpaQuery(JpaQueryMethod method, EntityManager em, String queryString, EvaluationContextProvider evaluationContextProvider, SpelExpressionParser parser) {
   super(method, em, queryString, evaluationContextProvider, parser);
   JpaParameters parameters = method.getParameters();
   boolean hasPagingOrSortingParameter = parameters.hasPageableParameter() || parameters.hasSortParameter();
   boolean containsPageableOrSortInQueryExpression = queryString.contains("#pageable") || queryString.contains("#sort");
   if(hasPagingOrSortingParameter && !containsPageableOrSortInQueryExpression) {
       throw new InvalidJpaQueryMethodException("Cannot use native queries with dynamic sorting and/or pagination in method " + method);
   }
}

My query contains a Pageable parameter, so hasPagingOrSortingParameter is true, but it's also looking for a #pageable or #sort sequence inside the queryString, which I do not provide.

I've tried adding #pageable (it's a comment) at the end of my query, which makes validation to pass but then, it fails at execution saying that the query expects one additional parameter: 3 instead of 2.

Funny thing is that, if I manually change containsPageableOrSortInQueryExpression from false to true while running, the query works fine so I don't know why it's checking for that string to be at my queryString and I don't know how to provide it.

Any help would be much appreciated.

Update 01/30/2018 It seems that developers at spring-data project are working on a fix for this issue with a PR by Jens Schauder

Spring Solutions


Solution 1 - Spring

My apologies in advance, this is pretty much summing up the original question and the comment from Janar, however...

I run into the same problem: I found the Example 50 of Spring Data as the solution for my need of having a native query with pagination but Spring was complaining on startup that I could not use pagination with native queries.

I just wanted to report that I managed to run successfully the native query I needed, using pagination, with the following code:

	@Query(value="SELECT a.* "
			+ "FROM author a left outer join mappable_natural_person p on a.id = p.provenance_id "
			+ "WHERE p.update_time is null OR (p.provenance_name='biblio_db' and a.update_time>p.update_time)"
			+ "ORDER BY a.id \n#pageable\n", 
		/*countQuery="SELECT count(a.*) "
			+ "FROM author a left outer join mappable_natural_person p on a.id = p.provenance_id "
			+ "WHERE p.update_time is null OR (p.provenance_name='biblio_db' and a.update_time>p.update_time) \n#pageable\n",*/
		nativeQuery=true)
public List<Author> findAuthorsUpdatedAndNew(Pageable pageable);

The countQuery (that is commented out in the code block) is needed to use Page<Author> as the return type of the query, the newlines around the "#pageable" comment are needed to avoid the runtime error on the number of expected parameters (workaround of the workaround). I hope this bug will be fixed soon...

Solution 2 - Spring

This is a hack for program using Spring Data JPA before Version 2.0.4.

Code has worked with PostgreSQL and MySQL :

public interface UserRepository extends JpaRepository<User, Long> {

@Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1 ORDER BY ?#{#pageable}",
       countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
       nativeQuery = true)
   Page<User> findByLastname(String lastname, Pageable pageable);   
}

ORDER BY ?#{#pageable} is for Pageable. countQuery is for Page<User>.

Solution 3 - Spring

Just for the record, using H2 as testing database, and MySQL at runtime, this approach works (example is newest object in group):

@Query(value = "SELECT t.* FROM t LEFT JOIN t AS t_newer " +
        "ON t.object_id = t_newer.object_id AND t.id < t_newer.id AND o_newer.user_id IN (:user_ids) " +
        "WHERE t_newer.id IS NULL AND t.user_id IN (:user_ids) " +
        "ORDER BY t.id DESC \n-- #pageable\n",
        countQuery = "SELECT COUNT(1) FROM t WHERE t.user_id IN (:user_ids) GROUP BY t.object_id, t.user_id",
        nativeQuery = true)
Page<T> findByUserIdInGroupByObjectId(@Param("user_ids") Set<Integer> userIds, Pageable pageable);

Spring Data JPA 1.10.5, H2 1.4.194, MySQL Community Server 5.7.11-log (innodb_version 5.7.11).

Solution 4 - Spring

Try this:

public interface UserRepository extends JpaRepository<User, Long> {
  @Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1 ORDER BY /*#pageable*/",
    countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
    nativeQuery = true)
  Page<User> findByLastname(String lastname, Pageable pageable);
}

("/* */" for Oracle notation)

Solution 5 - Spring

I have exact same symptom like @Lasneyx. My workaround for Postgres native query

@Query(value = "select * from users where user_type in (:userTypes) and user_context='abc'--#pageable\n", nativeQuery = true)
List<User> getUsersByTypes(@Param("userTypes") List<String> userTypes, Pageable pageable);

Solution 6 - Spring

I use oracle database and I did not get the result but an error with generated comma which d-man speak about above.

Then my solution was:

Pageable pageable = new PageRequest(current, rowCount);

As you can see without order by when create Pagable.

And the method in the DAO:

public interface UserRepository extends JpaRepository<User, Long> {
  @Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1 /*#pageable*/ ORDER BY LASTNAME",
    countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
    nativeQuery = true)
  Page<User> findByLastname(String lastname, Pageable pageable);
 }

Solution 7 - Spring

I am adding this answer just as a placeholder for those users who are using more recent versions of Spring Boot. On Spring Boot 2.4.3, I observed that none of the workaround were necessary, and the following code worked straight out of the box for me:

public interface UserRepository extends JpaRepository<User, Long> {
    @Query(value="SELECT * FROM USERS WHERE LASTNAME = ?1", nativeQuery=true)
    Page<User> findByLastname(String lastname, Pageable pageable);
}

The countQuery definition was not necessary, and a call to Page#getTotalElements() in fact already was returning the correct count, as returned by JPA's own internal count query.

The above code is extremely powerful, offering pagination made via a native query, yet which return results into actual Java entities (rather than the ugly and bulky List<Object[]>, which sometimes is necessary).

Solution 8 - Spring

I could successfully integrate Pagination in

> spring-data-jpa-2.1.6

as follows.

@Query(
 value = “SELECT * FROM Users”, 
 countQuery = “SELECT count(*) FROM Users”, 
 nativeQuery = true)
Page<User> findAllUsersWithPagination(Pageable pageable);

Solution 9 - Spring

Both the following approaches work fine with MySQL for paginating native query. They doesn't work with H2 though. It will complain the sql syntax error.

  • ORDER BY ?#{#pageable}
  • ORDER BY a.id \n#pageable\n

Solution 10 - Spring

Using "ORDER BY id DESC \n-- #pageable\n " instead of "ORDER BY id \n#pageable\n" worked for me with MS SQL SERVER

Solution 11 - Spring

This worked for me (I am using Postgres) in Groovy:

@RestResource(path="namespaceAndNameAndRawStateContainsMostRecentVersion", rel="namespaceAndNameAndRawStateContainsMostRecentVersion")
    @Query(nativeQuery=true,
            countQuery="""
            SELECT COUNT(1) 
            FROM 
            (
                SELECT
                ROW_NUMBER() OVER (
                    PARTITION BY name, provider_id, state
                    ORDER BY version DESC) version_partition,
                *
                FROM mydb.mytable
                WHERE
                (name ILIKE ('%' || :name || '%') OR (:name = '')) AND
                (namespace ILIKE ('%' || :namespace || '%') OR (:namespace = '')) AND
                (state = :state OR (:state = ''))
            ) t
            WHERE version_partition = 1
            """,
            value="""
            SELECT id, version, state, name, internal_name, namespace, provider_id, config, create_date, update_date 
            FROM 
            (
                SELECT 
                ROW_NUMBER() OVER (
                    PARTITION BY name, provider_id, state
                    ORDER BY version DESC) version_partition,
                *
                FROM mydb.mytable
                WHERE 
                (name ILIKE ('%' || :name || '%') OR (:name = '')) AND
                (namespace ILIKE ('%' || :namespace || '%') OR (:namespace = '')) AND
                (state = :state OR (:state = ''))		
            ) t            
            WHERE version_partition = 1             
            /*#{#pageable}*/
            """)
    public Page<Entity> findByNamespaceContainsAndNameContainsAndRawStateContainsMostRecentVersion(@Param("namespace")String namespace, @Param("name")String name, @Param("state")String state, Pageable pageable)

The key here was to use: /*#{#pageable}*/

It allows me to do sorting and pagination. You can test it by using something like this: http://localhost:8080/api/v1/entities/search/namespaceAndNameAndRawStateContainsMostRecentVersion?namespace=&name=&state=published&page=0&size=3&sort=name,desc

Watch out for this issue: https://stackoverflow.com/questions/51459684/spring-pageable-does-not-translate-column-name

Solution 12 - Spring

It does work as below:

public interface UserRepository extends JpaRepository<User, Long> {
    @Query(value = "select * from (select (@rowid\\:=@rowid+1) as RN, u.* from USERS u, (SELECT @rowid\\:=0) as init where  LASTNAME = ?1) as total"+
        "where RN between ?#{#pageable.offset-1} and ?#{#pageable.offset + #pageable.pageSize}",
    countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
    nativeQuery = true)
    Page<User> findByLastname(String lastname, Pageable pageable);
}

Solution 13 - Spring

For me below worked in MS SQL

 @Query(value="SELECT * FROM ABC r where r.type in :type  ORDER BY RAND() \n-- #pageable\n ",nativeQuery = true)
List<ABC> findByBinUseFAndRgtnType(@Param("type") List<Byte>type,Pageable pageable);

Solution 14 - Spring

I'm using the code below. working

@Query(value = "select * from user usr" +
  "left join apl apl on usr.user_id = apl.id" +
  "left join lang on lang.role_id = usr.role_id" +
  "where apl.scr_name like %:scrname% and apl.uname like %:uname and usr.role_id in :roleIds ORDER BY ?#{#pageable}",
  countQuery = "select count(*) from user usr" +
      "left join apl apl on usr.user_id = apl.id" +
      "left join lang on lang.role_id = usr.role_id" +
      "where apl.scr_name like %:scrname% and apl.uname like %:uname and usr.role_id in :roleIds",
  nativeQuery = true)
Page<AplUserEntity> searchUser(@Param("scrname") String scrname,@Param("uname") String  uname,@Param("roleIds") List<Long> roleIds,Pageable pageable);

Solution 15 - Spring

Removing \n#pageable\n from both query and count query worked for me. Springboot version : 2.1.5.RELEASE DB : Mysql

Solution 16 - Spring

You can use below code for h2 and MySQl

	@Query(value = "SELECT req.CREATED_AT createdAt, req.CREATED_BY createdBy,req.APP_ID appId,req.NOTE_ID noteId,req.MODEL model FROM SUMBITED_REQUESTS  req inner join NOTE note where req.NOTE_ID=note.ID and note.CREATED_BY= :userId "
		,
		 countQuery = "SELECT count(*) FROM SUMBITED_REQUESTS req inner join NOTE note WHERE req.NOTE_ID=note.ID and note.CREATED_BY=:userId",
		nativeQuery = true)
Page<UserRequestsDataMapper> getAllRequestForCreator(@Param("userId") String userId,Pageable pageable);

Solution 17 - Spring

You can achieve it by using following code,

@Query(value = "SELECT * FROM users u WHERE  ORDER BY ?#{#pageable}", nativeQuery = true)
List<User> getUsers(String name, Pageable pageable);

Simply use ORDER BY ?#{#pageable} and pass page request to your method.

Enjoy!

Solution 18 - Spring

  • Create your custom repository:
public interface ProductsCustomRepository extends JpaRepository<ProductResultEntity, Long> {
    @Query(
        value = "select tableA.id, tableB.bank_name from tableA join tableB on tableA.id = tableB.a_id where tableA.id = :id
        and (:fieldX is null or tableA.fieldX LIKE :fieldX)",
        countQuery = "select count(*) from tableA join tableB on tableA.id = tableB.a_id where tableA.id = :id
        and (:fieldX is null or tableA.fieldX LIKE :fieldX)",
        nativeQuery = true
    )
    Page<ProductResultEntity> search(@Param("id") Long aId,
        @Param("fieldX") String keyword, Pageable pageable
    );
}
  • Create View as query of:
create view zzz as select * from tableA join tableB on tableA.id = tableB.a_id
  • Generate ProductResultEntity from that zzz view (and delete view zzz when have done)
  • Test call function and enjoy it:
productsRepository.search("123", "%BANK%", PageRequest.of(0, 5, Sort.by(Sort.Direction.ASC, "id")));
  • Entity:
@Entity
public class ProductResultEntity {
    private Long id;
    private String bank;

    @Id
    @Column(name = "id", nullable = false)
    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }

    @Column(name = "bank_name", nullable = false)
    public String getBank() {
        return bank;
    }

    public void setBank(String bank) {
        this.bank = bank;
    }
}

Solution 19 - Spring

Replacing /#pageable/ with ?#{#pageable} allow to do pagination. Adding PageableDefault allow you to set size of page Elements.

Attributions

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