Spring classpath prefix difference
JavaSpringClasspathJava Problem Overview
Documented here it states
> This special prefix specifies that all > classpath resources that match the > given name must be obtained > (internally, this essentially happens > via a ClassLoader.getResources(...) > call), and then merged to form the > final application context definition.
Can someone explain this?
What is the difference between using classpath*:conf/appContext.xml
as opposed to classpath:conf/appContext.xml
without the asterisk.
Java Solutions
Solution 1 - Java
SIMPLE DEFINITION
The classpath*:conf/appContext.xml
simply means that all appContext.xml files under conf
folders in all your jars on the classpath will be picked up and joined into one big application context.
In contrast, classpath:conf/appContext.xml
will load only one such file... the first one found on your classpath.
Solution 2 - Java
The classpath*:...
syntax is useful primarily when you want to build an application context from multiple bean definition files, using wildcard syntax.
For example, if you construct your context using classpath*:appContext.xml
, the classpath will be scanned for every resource called appContext.xml
in the classpath, and the bean definitions from all of them merged into a single context.
In contrast, classpath:conf/appContext.xml
will obtain one and only one file called appContext.xml
from the the classpath. If there is more than one, the others will be ignored.
Solution 3 - Java
classpath:* It refers to a list of resources and loads all such files present in the classpath and list can be empty and if no such file is present in the classpath then application does not throw any exception(just ignores the error).
classpath: It refers to a certain resource and loads only the first file found on the classpath and if no such file is present in the classpath it will throw an exception
java.io.FileNotFoundException: class path resource [conf/appContext.xml] cannot be opened because it does not exist
Solution 4 - Java
The source code of Spring:
public Resource[] getResources(String locationPattern) throws IOException {
Assert.notNull(locationPattern, "Location pattern must not be null");
//CLASSPATH_ALL_URL_PREFIX="classpath*:"
if (locationPattern.startsWith(CLASSPATH_ALL_URL_PREFIX)) {
// a class path resource (multiple resources for same name possible)
if (getPathMatcher().isPattern(locationPattern.substring(CLASSPATH_ALL_URL_PREFIX.length()))) {
// a class path resource pattern
return findPathMatchingResources(locationPattern);
}
else {
// all class path resources with the given name
return findAllClassPathResources(locationPattern.substring(CLASSPATH_ALL_URL_PREFIX.length()));
}
}
else {
// Only look for a pattern after a prefix here
// (to not get fooled by a pattern symbol in a strange prefix).
int prefixEnd = locationPattern.indexOf(":") + 1;
if (getPathMatcher().isPattern(locationPattern.substring(prefixEnd))) {
// a file pattern
return findPathMatchingResources(locationPattern);
}
else {
// a single resource with the given name
return new Resource[] {getResourceLoader().getResource(locationPattern)};
}
}
}