No, there isn&#39;t. I suggest to place the CSS images in at least the same level as the CSS file so that you don&#39;t need to go backwards in the path. E.g. `/css` folder for CSS files and `/css/images` folder for CSS images. Then you can consistently use `url(&#39;images/name.ext&#39;)` for CSS images. This way you can place the root `/css` folder practically everywhere without fiddling with the image URL&#39;s.

As an alternative, you could dynamically add a class to your body tag, and use that in selectors to override css URLs depending on which directory your file is served from.

An alternative way to set the base directory in the CSS (which seems to be impossible) is to set the base directory of the HTML document with the ```&lt;base&gt;``` tag. This tag is not well known in the community but I found a nice tutorial in the web:

[https://webdesign.tutsplus.com/articles/quick-tip-set-relative-urls-with-the-base-tag--cms-21399][1]


  [1]: https://webdesign.tutsplus.com/articles/quick-tip-set-relative-urls-with-the-base-tag--cms-21399

It seems to be totally a good solution.

&gt; **Possible Duplicates:**  
&gt; [Terminating a Python script](https://stackoverflow.com/questions/73663/terminating-a-python-script)  
&gt; [Terminating a Python Program ](https://stackoverflow.com/questions/949504/terminating-a-python-program)  

&lt;!-- End of automatically inserted text --&gt;

My question is how to exit out in Python main function? I have tried &#39;`return`&#39; but it gave the error `SyntaxError: &#39;return&#39; outside function`. Can anyone help? Thanks.

    if __name__ == &#39;__main__&#39;:
      try:
        if condition:
    	(I want to exit here) 
    	do something
      finally:
    	do something



Python how to exit main function

I have created a minimal maven project with a single child module in eclipse helios.

In the src/test/resources folder I have put a single file &quot;install.xml&quot;. In the folder src/test/java I have created a single package with a single class that does:

      @Test
      public void doit() throws Exception {
        URL url = this.getClass().getClassLoader().getResource(&quot;install.xml&quot;);
        System.out.println(url.getPath());
    
      }

but when I run the code as a junit 4 unit test I just get a NullPointerException. This has worked fine a million of times before. Any ideas?

I have followed this guide:

http://www.fuyun.org/2009/11/how-to-read-input-files-in-maven-junit/

but still get the same error.

this.getClass().getClassLoader().getResource(&quot;...&quot;) and NullPointerException

I had to split up a long css file. I put the smaller css files within a `styles` directory.

Now I have to update the the urls to go up one level with the `../` notation.

Is there anyway to specify the base URL from which to load assets like with the base tag in HTML, but with CSS?

Specifying base url for css

I had to split up a long css file. I put the smaller css files within a <code>styles</code> directory.
Now I have to update the the urls to go up one level with the <code>../</code> notation.
Is there anyway to specify the base URL from which to load assets like with the base tag in HTML, but with CSS?

I&#39;m trying to load an image selected by the user through an &lt;input type=&quot;file&quot;&gt; element.

I added a onchange event handler to the input element like this:

    &lt;input type=&quot;file&quot; name=&quot;picField&quot; id=&quot;picField&quot; size=&quot;24&quot; onchange=&quot;preview_2(this);&quot; alt=&quot;&quot;/&gt;

and the preview_2 function is:

    var outImage =&quot;imagenFondo&quot;;
    function preview_2(what){
    	globalPic = new Image();
    	globalPic.onload = function() {
    		document.getElementById(outImage).src = globalPic.src;
    	}
    	globalPic.src=what.value;
    }

where outImage has the id value of the &lt;img&gt; tag where I want the new picture to be loaded.

However, it appears that the onload never happens and it does not load anything to the html.

What should I do?

Loading an image to a &lt;img&gt; from &lt;input file&gt;

I&#39;m piecing together a cheapo app that amongst other things &quot;frames&quot; some of our websites...  Pretty simple with the `WebViewClient`. until I hit the video.

The video is done as `HTML5` &lt;video&gt; elements, and these work fine and dandy on Chrome, iPhones, and now that we fixed the encoding issues it works great on `Android` in the native browser.

Now the rub: `WebView` doesn&#39;t like it.  At all.  I can click on the poster image, and nothing happens.

Googling, I found [this][1] which is close, but seems to be based on a &#39;link&#39; (as in a href...) instead of a video element.  (onDownloadListener does not appear to get invoked on video elements...)

I also see references to overriding onShowCustomView, but that seems to not get called on video elements... nor does shouldOverrideUrlLoading.. 

I would rather not get into &quot;pull xml from the server, reformat it in the app&quot;.. by keeping the story layout on the server, I can control the content a bit better without forcing people to keep updating an app.  So if I can convince WebView to handle &lt;video&gt; tags like the native browser, that would be best.

I&#39;m clearly missing something obvious.. but I have no clue what.


  [1]: http://www.codelark.com/2010/05/12/android-viewing-video-from-embedded-webview/

WebView and HTML5 &lt;video&gt;

How can I overlay a div with semi-transparent opacity over a youtube iframe embedded video?

    &lt;iframe class=&quot;youtube-player&quot; type=&quot;text/html&quot; width=&quot;520&quot; height=&quot;330&quot; src=&quot;http://www.youtube.com/embed/NWHfY_lvKIQ&quot; frameborder=&quot;0&quot;&gt;&lt;/iframe&gt;
    &lt;div id=&quot;overlay&quot;&gt;&lt;/div&gt;

CSS

    #overlay {
        position:fixed;
        top:0;
        left:0;
        width:100%;
        height:100%;
        background:#000;
        opacity:0.8;
        /*background:rgba(255,255,255,0.8); or just this*/
        z-index:50;
        color:#fff;
    }





**edit (added more clarification):**
HTML5 is approaching us, with more and more devices that use it instead of flash, which complicates the embedding of youtube videos, thankfully youtube provides a special embeddable iFrame with handles all of the video embedding compatibility issues, but now the previously working method of overlaying a video object with a semi-transparent div is no longer valid, I am now unable to add a `&lt;param name=&quot;wmode&quot; value=&quot;transparent&quot;&gt;` to the object, because it is now a iFrame, so how do I add a opaque div on top of the iframe embedded video?


overlay opaque div over youtube iframe

Trying to find the links on a page. 

my regex is:

    /&lt;a\s[^&gt;]*href=(\&quot;\&#39;??)([^\&quot;\&#39; &gt;]*?)[^&gt;]*&gt;(.*)&lt;\/a&gt;/

but seems to fail at

    &lt;a title=&quot;this&quot; href=&quot;that&quot;&gt;what?&lt;/a&gt;

How would I change my regex to deal with href not placed first in the a tag?


Grabbing the href attribute of an A element

I need to upload only image file through `&lt;input type=&quot;file&quot;&gt;` tag. 

Right now, it accepts all file types. But, I want to restrict it to only specific image file extensions which include `.jpg`, `.gif` etc.

How can I achieve this functionality?

How to allow &lt;input type=&quot;file&quot;&gt; to accept only image files?

What is the right way to use `@font-face` so that the browser will not download the font if the user already have it?

I am using @font-face to define DejaVu, which is already installed on my system (linux).
Firefox is not downloading the font, but Chromium is downloading it every time!

My CSS code, based on [font squirrel](http://www.fontsquirrel.com) and [that question](https://stackoverflow.com/questions/2436749/how-to-define-bold-italic-using-font-face) look like this:

    @font-face {
    	font-family: &#39;DejaVu Serif&#39;;
    	src: url(&#39;DejaVuSerif-webfont.eot&#39;);
    	src: local(&#39;DejaVu Serif&#39;), url(&#39;DejaVuSerif-webfont.woff&#39;) format(&#39;woff&#39;), url(&#39;DejaVuSerif-webfont.ttf&#39;) format(&#39;truetype&#39;), url(&#39;DejaVuSerif-webfont.svg#webfontCFu7RF0I&#39;) format(&#39;svg&#39;);
    	font-weight: normal;
    	font-style: normal;
    }
    
    /* ... @font-face definitions for italic and bold omitted ... */
    
    @font-face {
    	font-family: &#39;DejaVu Serif&#39;;
    	src: url(&#39;DejaVuSerif-BoldItalic-webfont.eot&#39;);
    	src: local(&#39;DejaVu Serif Bold Italic&#39;), url(&#39;DejaVuSerif-BoldItalic-webfont.woff&#39;) format(&#39;woff&#39;), url(&#39;DejaVuSerif-BoldItalic-webfont.ttf&#39;) format(&#39;truetype&#39;), url(&#39;DejaVuSerif-BoldItalic-webfont.svg#webfontQAewh7pf&#39;) format(&#39;svg&#39;);
    	font-weight: bold;
    	font-style: italic;
    }


@font-face src: local - How to use the local font if the user already has it?

How can I set line spacing with CSS, like we can set it in MS Word?

Set line spacing

Developing an iPad website I tried to use the CSS property `overflow: auto` to get the scrollbars if needed in a `div`, but my device is refusing to show them even if the two fingers scroll is working.

I tried with

    overflow: auto;

and

    overflow: scroll;

and the result is the same.

I&#39;m only testing on an iPad (on desktop browsers works perfectly). 

Any ideas?

How to get the scroll bar with CSS overflow on iOS

I have used CSS before and I came across the below CSS style, don&#39;t have a clue what it does. 

&lt;!-- language: lang-css --&gt;

    a[href^=&quot;http:&quot;] {
       background: url(img/keys.gif) no-repeat right top;
    }
    a[href^=&quot;http://mysite.com&quot;], a[href^=&quot;http://www.mysite.com&quot;] {
       background-image: none; padding-right:0;
    }


What does a[href^=&quot;...&quot;] do in CSS?

I am using a ALAsset Framework for accessing the files in the device&#39;s photo gallery.
  
So far I am able to access the thumbnail and display it.  
I want to display the actual image in an image view but I am unable to figure out how to do this.  

I tried using the URLs field in the ALAsset object but was unsuccessful.
  
Anybody knows how this can be done?  

Here&#39;s some code where I was able to access the thumbnail and place it in a table cell:  

    - (UITableViewCell *)tableView:(UITableView *)tableView 
             cellForRowAtIndexPath:(NSIndexPath *)indexPath {

 
      static NSString *CellIdentifier = @&quot;Cell&quot;;
 
      UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
      if (cell == nil) {
        cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease];
      }
      //here &#39;asset&#39; represents the ALAsset object
 

      asset = [assets objectAtIndex:indexPath.row];
           //i am accessing the thumbnail here
      [cell.imageView setImage:[UIImage imageWithCGImage:[asset thumbnail]]];
      [cell.textLabel setText:[NSString stringWithFormat:@&quot;Photo %d&quot;, indexPath.row+1]];
 
      return cell;
    }


display image from URL retrieved from ALAsset in iPhone

I know i can do this

    var nv = HttpUtility.ParseQueryString(req.RawUrl);

But is there a way to convert this back to a url?

    var newUrl = HttpUtility.Something(&quot;/page&quot;, nv);

NameValueCollection to URL Query?

Given the following URL (working, try it!)

&gt; https://select-test.wp3.rbsworldpay.com/wcc/purchase?instId=151711&amp;cartId=28524&amp;currency=GBP&amp;amount=1401.49&amp;testMode=100&amp;name=Tom%20Gul&amp;address=24%20House%20Road\nSome
&gt; Place\nCounty&amp;postcode=TR33%20999&amp;email=email@mail.com&amp;country=GB

If you click on the link and go through to the payment page, the address in the address box is not displaying properly, the newline characters are displaying as text.

I&#39;ve tried passing through `&lt;br /&gt;&#39;s` but no luck, anyone got any ideas?  I need to get  the address to display with newlines.

Commas are OK as a separator but i would much prefer being able to have newlines.  Thanks for any help!  A working example will be the accepted answer.

Transmitting newline character &quot;\n&quot;

How can I check if a string is a URL in Java?

How to verify if a String in Java is a valid URL

My Javascript ain&#39;t so hot, so before I get into some messy string operations, I thought I&#39;d ask:

If the current url is: &quot;http://stackoverflow.com/questions/ask&quot;

What&#39;s a good way to to just get: &quot;/questions/ask&quot; ?

Basically I want a string that matches the Url without the domain or the &quot;http://&quot;

What&#39;s an easy way to get the url in the current window minus the domain name?

Is there anything built into `System.IO.Path` that gives me just the filepath?

For example, if I have a `string` 

&gt; @&quot;c:\webserver\public\myCompany\configs\promo.xml&quot;,

 

is there any BCL method that will give me 

&gt; &quot;c:\webserver\public\myCompany\configs\&quot;?

Get full path without filename from path that includes filename

Question: is there a simple sh/bash/zsh/fish/... command to print the absolute path of whichever file I feed it?

Usage case: I&#39;m in directory `/a/b` and I&#39;d like to print the full path to file `c` on the command-line so that I can easily paste it into another program: `/a/b/c`. Simple, yet a little program to do this could probably save me 5 or so seconds when it comes to handling long paths, which in the end adds up. So it surprises me that I can&#39;t find a standard utility to do this — is there really none?

Here&#39;s a sample implementation, abspath.py:

    #!/usr/bin/python
    # Author: Diggory Hardy &lt;diggory.hardy@gmail.com&gt;
    # Licence: public domain
    # Purpose: print the absolute path of all input paths

    import sys
    import os.path
    if len(sys.argv)&gt;1:
        for i in range(1,len(sys.argv)):
            print os.path.abspath( sys.argv[i] )
        sys.exit(0)
    else:
        print &gt;&gt; sys.stderr, &quot;Usage: &quot;,sys.argv[0],&quot; PATH.&quot;
        sys.exit(1)


How to obtain the absolute path of a file via Shell (BASH/ZSH/SH)?

In Python, suppose I have a path like this:

    /folderA/folderB/folderC/folderD/

How can I get just the `folderD` part?

How to get only the last part of a path in Python?

Say I have a program `X.EXE` installed in folder `c:\abcd\happy\` on the system. The folder is on the system path. Now suppose there is another program on the system that&#39;s also called X.EXE but is installed in folder `c:\windows\`.

Is it possible to quickly find out from the command line that if I type in `X.EXE` which of the two `X.EXE`&#39;s will get launched? (but without having to dir search or look at the process details in Task Manager).

Maybe some sort of in-built command, or some program out there that can do something like this? :

    detect_program_path X.EXE



Finding the path of the program that will execute from the command line in Windows

I&#39;m not sure if these paths are duplicates. Given the relative path, how do I determine absolute path using a shell script?

Example:

    relative path: /x/y/../../a/b/z/../c/d

    absolute path: /a/b/c/d

Content Type	Original Author	Original Content on Stackoverflow
Question	rhlee	View Question on Stackoverflow
Solution 1 - Html	BalusC	View Answer on Stackoverflow
Solution 2 - Html	BBaysinger	View Answer on Stackoverflow
Solution 3 - Html	Guybrush	View Answer on Stackoverflow

Specifying base url for css

Html Problem Overview

Html Solutions

Solution 1 - Html

Solution 2 - Html

Solution 3 - Html

this.getClass().getClassLoader().getResource("...") and NullPointerException

Python how to exit main function

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