Shortcut to generate an NSRange for entire length of NSString?
IosObjective CNsstringNsrangeIos Problem Overview
Is there a short way to say "entire string" rather than typing out:
NSMakeRange(0, myString.length)]
It seems silly that the longest part of this kind of code is the least important (because I usually want to search/replace within entire string)…
[myString replaceOccurrencesOfString:@"replace_me"
withString:replacementString
options:NSCaseInsensitiveSearch
range:NSMakeRange(0, myString.length)];
Ios Solutions
Solution 1 - Ios
Function? Category method?
- (NSRange)fullRange
{
return (NSRange){0, [self length]};
}
[myString replaceOccurrencesOfString:@"replace_me"
withString:replacementString
options:NSCaseInsensitiveSearch
range:[myString fullRange]];
Solution 2 - Ios
Swift 4+, useful for NSRegularExpression
and NSAttributedString
extension String {
var nsRange : NSRange {
return NSRange(self.startIndex..., in: self)
}
func range(from nsRange: NSRange) -> Range<String.Index>? {
return Range(nsRange, in: self)
}
}
Solution 3 - Ios
Not that I know of. But you could easily add an NSString
category:
@interface NSString (MyRangeExtensions)
- (NSRange)fullRange
@end
@implementation NSString (MyRangeExtensions)
- (NSRange)fullRange {
return (NSRange){0, self.length};
}
Solution 4 - Ios
Swift
NSMakeRange(0, str.length)
or as an extension
:
extension NSString {
func fullrange() -> NSRange {
return NSMakeRange(0, self.length)
}
}
Solution 5 - Ios
Swift 2:
extension String {
var fullRange:Range<String.Index> { return startIndex..<endIndex }
}
as in
let swiftRange = "abc".fullRange
or
let nsRange = "abc".fullRange.toRange
Solution 6 - Ios
This is not shorter, but... Oh well
NSRange range = [str rangeOfString:str];