Sharing a URL with a query string on Twitter

TwitterQuery StringShareUrl Encoding

Twitter Problem Overview


I'm trying to put a Twitter share link in an email. Because this is in an email I can't rely on JavaScript, and have to use the "Build Your Own" Tweet button.

For example, sharing a link to Google:

<a href="http://www.twitter.com/share?url=http://www.google.com/>Tweet</a>

This works fine. The problem I'm having is when the URL has a query string.

<a href="http://www.twitter.com/share?url=http://mysite.org/foo.htm?bar=123&baz=456">Tweet</a>

URLs with query strings confuse Twitter's URL shortening service, t.co. I've tried URL encoding this in various ways and cannot get anything to work. The closest I have gotten is by doing this.

<a href="http://www.twitter.com/share?url=http://mysite.org/foo.htm%3Fbar%3D123%26baz%3D456">Tweet</a>

Here I've encoded only the query string. When I do this, t.co successfully shortens the URL, but upon following the shortened link, it takes you to the encoded URL. I see http://mysite.org/foo.htm%3Fbar%3D123%26baz%3D456 in the address bar, and get the following error in the browser

> Not Found > > The requested URL /foo.htm?bar=123&baz=456 was not found on this server.

I'm at a loss as to how to solve this problem.

Edit: Re: onteria_

I've tried encoding the entire URL. When I do that no URL shows up in the Tweet.

Twitter Solutions


Solution 1 - Twitter

This will Work For You

http://twitter.com/share?text=text goes here&url=http://url goes here&hashtags=hashtag1,hashtag2,hashtag3

Here is a Live Example About it


http://twitter.com/share?text=Im Sharing on Twitter&url=https://stackoverflow.com/users/2943186/youssef-subehi&hashtags=stackoverflow,example,youssefusf

Solution 2 - Twitter

This can be solved by using https://twitter.com/intent/tweet instead of http://www.twitter.com/share. Using the intent/tweet function, you simply URL encode your entire URL and it works like a charm.

https://dev.twitter.com/web/intents

Solution 3 - Twitter

Use tweet web intent, this is the simple link:

https://twitter.com/intent/tweet?url=<?=urlencode($url)?>

more variables at https://dev.twitter.com/web/tweet-button/web-intent

Solution 4 - Twitter

It's working for me:

<div class="links">
    <ul>
    <li class="social-share facebook">Share on Facebook</li>
    <li class="social-share twitter">Share on Twitter</li>
    <li class="social-share linkedin">Share on LinkedIn</li>
    </ul>
</div>

And in js file add this:


setShareLinks();

    function socialWindow(url) {
    var left = (screen.width -570) / 2;
    var top = (screen.height -570) / 2;
    var params = "menubar=no,toolbar=no,status=no,width=570,height=570,top=" + top + ",left=" + left;  window.open(url,"NewWindow",params);}

function setShareLinks() {
    var pageUrl = encodeURIComponent(document.URL);
    var tweet = encodeURIComponent($("meta[property='og:description']").attr("content"));

$(".social-share.facebook").on("click", function() { url="https://www.facebook.com/sharer.php?u=" + pageUrl;
socialWindow(url);
});

$(".social-share.twitter").on("click", function() {
url = "https://twitter.com/intent/tweet?url=" + pageUrl + "&text=" + tweet;
socialWindow(url);
});

$(".social-share.linkedin").on("click", function() {
    url = "https://www.linkedin.com/shareArticle?mini=true&url=" + pageUrl;
socialWindow(url);
})
}

Hope this will work well.

Solution 5 - Twitter

You can use these functions:

 function shareOnFB(){
       var url = "https://www.facebook.com/sharer/sharer.php?u=https://yoururl.com&t=your message";
       window.open(url, '', 'menubar=no,toolbar=no,resizable=yes,scrollbars=yes,height=300,width=600');
       return false;
  }


function shareOntwitter(){
    var url = 'https://twitter.com/intent/tweet?url=URL_HERE&via=getboldify&text=yourtext';
    TwitterWindow = window.open(url, 'TwitterWindow',width=600,height=300);
    return false;
 }


function shareOnGoogle(){
     var url = "https://plus.google.com/share?url=https://yoururl.com";
     window.open(url, '', 'menubar=no,toolbar=no,resizable=yes,scrollbars=yes,height=350,width=480');
     return false;
}


<a onClick="shareOnFB()"> Facebook </a>
<a onClick="shareOntwitter()"> Twitter </a>
<a onClick="shareOnGoogle()"> Google </a>

Solution 6 - Twitter

Doesn't get simpler than this:

<a href="https://twitter.com/intent/tweet?text=optional%20promo%20text%20http://example.com/foo.htm?bar=123&baz=456" target="_blank">Tweet</a>

Solution 7 - Twitter

You must to change & to %26 in query string from your url

Look at this: https://dev.twitter.com/discussions/8616

Solution 8 - Twitter

I reference all the methods.

Encode the query twice is the fast solution.

const query = a=123&b=456;
const url = `https://example.com/test?${encodeURIComponent(encodeURIComponent(query),)}`;


const twitterSharingURL=`https://twitter.com/intent/tweet?&url=${url}`

Solution 9 - Twitter

You don't necessarily need to use intent, it you encode your URL it will work with twitter share as well.

Solution 10 - Twitter

As @onteria_ mentioned, you need to encode the entire parameter. For anyone else facing the same issue, you can use the following bookmarklet to generate the properly encoded url. Copy paste it into your browser's address bar to create the twitter share url. Make sure that the javascript: prefix is there when you copy it into address bar, Google Chrome removes it when copying.

javascript:(function(){var url=prompt("Enter the url to share");if(url)prompt("Share the following url - ","http://www.twitter.com/share?url="+encodeURIComponent(url))})();

Source on JS Fiddle http://jsfiddle.net/2frkV/

Solution 11 - Twitter

If you add it manual on html site, just replace:

&

With

&amp;

Standard html code for &

Solution 12 - Twitter

Twitter now lets you send the URL through a data attribute. This works great for me:

<a href="javascript:;" class="twitter-share-button" data-lang="en" data-text="check out link b" data-url="http://www.lyricvideos.org/tracks?videoURL=SX05JZ4FisE">Tweet</a>

Solution 13 - Twitter

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionhaydenmuhlView Question on Stackoverflow
Solution 1 - TwitterYoussef SubehiView Answer on Stackoverflow
Solution 2 - TwitterhaydenmuhlView Answer on Stackoverflow
Solution 3 - TwitterkampageddonView Answer on Stackoverflow
Solution 4 - TwitterMahfuz KhandakerView Answer on Stackoverflow
Solution 5 - TwitterPHP Worm...View Answer on Stackoverflow
Solution 6 - TwitterRonen RabinoviciView Answer on Stackoverflow
Solution 7 - TwitterThiago ValentimView Answer on Stackoverflow
Solution 8 - TwitterDana ChenView Answer on Stackoverflow
Solution 9 - TwitterDragos RusuView Answer on Stackoverflow
Solution 10 - TwitterJoyce BabuView Answer on Stackoverflow
Solution 11 - TwitterHans GantengView Answer on Stackoverflow
Solution 12 - Twitteruser3798322View Answer on Stackoverflow
Solution 13 - TwitterWil GichuView Answer on Stackoverflow