Set Action Listener Programmatically in Swift

XcodeSwift

Xcode Problem Overview


I saw some example codes that assign the same OnClick event to all the buttons in Android (even if they perform completely different action) . How can do it with Swift

Android Example:

@Override 
public void onCreate(Bundle savedInstanceState) {
        button1.setOnClickListener(onClickListener);
        button2.setOnClickListener(onClickListener);
        button3.setOnClickListener(onClickListener);
} 
 
private OnClickListener onClickListener = new OnClickListener() {
     @Override 
     public void onClick(View v) {
         switch(v.getId()){
             case R.id.button1:
                  //DO something 
             break; 
             case R.id.button2:
                  //DO something 
             break; 
             case R.id.button3:
                  //DO something 
             break; 
         } 
 
   } 
}; 

Note: I don't want create the button programatically.

Xcode Solutions


Solution 1 - Xcode

On iOS, you're not setting a listener; you add a target (an object) and an action (method signature, "selector" in iOS parlance) to your UIControl (which UIButton is a subclass of):

button1.addTarget(self, action: "buttonClicked:", for: .touchUpInside)
button2.addTarget(self, action: "buttonClicked:", for: .touchUpInside)
button3.addTarget(self, action: "buttonClicked:", for: .touchUpInside)

The first parameter is the target object, in this case self. The action is a selector (method signature) and there are basically two options (more on that later). The control event is a bit specific to the UIControl - .TouchUpInside is commonly used for tapping a button.

Now, the action. That's a method (the name is your choice) of one of the following formats:

func buttonClicked()
func buttonClicked(_ sender: AnyObject?)

To use the first one use "buttonClicked", for the second one (which you want here) use "buttonClicked:" (with trailing colon). The sender will be the source of the event, in other words, your button.

func buttonClicked(_ sender: AnyObject?) {
  if sender === button1 {
    // do something
  } else if sender === button2 {
    // do something
  } else if sender === button3 {
    // do something
  }
}

(this assumes that button1, button2 and button3 are instance variables).

Instead of this one method with the big switch statement consider using separate methods for each button. Based on your specific use case either approach might be better:

func button1Clicked() {
  // do something
}

func button2Clicked() {
  // do something
}

func button3Clicked() {
  // do something
}

Here, I'm not even using the sender argument because I don't need it.

P.S.: Instead of adding targets and actions programmatically you can do so in your Storyboard or nib file. In order to expose the actions you put IBAction in front of your function, e.g.:

@IBAction func button1Clicked() {
  // do something
}

Solution 2 - Xcode

Swift 4.*

button.addTarget(self, action: #selector(didButtonClick), for: .touchUpInside)

And the button triggers this function:

@objc func didButtonClick(_ sender: UIButton) {
    // your code goes here
}

Solution 3 - Xcode

An Swift 5 Extension Solution

Create A SwiftFile "SetOnClickListener.swift"
copy paste this code

import UIKit

class ClosureSleeve {
  let closure: () -> ()

  init(attachTo: AnyObject, closure: @escaping () -> ()) {
    self.closure = closure
    objc_setAssociatedObject(attachTo, "[\(arc4random())]", self, .OBJC_ASSOCIATION_RETAIN)
  }

  @objc func invoke() {
    closure()
  }
}

extension UIControl {
    func setOnClickListener(for controlEvents: UIControl.Event = .primaryActionTriggered, action: @escaping () -> ()) {
        let sleeve = ClosureSleeve(attachTo: self, closure: action)
        addTarget(sleeve, action: #selector(ClosureSleeve.invoke), for: controlEvents)
    }
}

How To use
for example buttonA is a UIButton

buttonA.setOnClickListener {
  print("button A clicked")                  
}

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionGilberto IbarraView Question on Stackoverflow
Solution 1 - XcodeThomas MüllerView Answer on Stackoverflow
Solution 2 - XcodeGilad BrunfmanView Answer on Stackoverflow
Solution 3 - XcodeMuhammad AsyrafView Answer on Stackoverflow