Serializing and submitting a form with jQuery and PHP

PhpJqueryFormsSerializationForm Submit

Php Problem Overview


I'm trying to send a form's data using jQuery. However, data does not reach the server. Can you please tell me what I'm doing wrong?

My HTML form:

<form id="contactForm" name="contactForm" method="post">
	<input type="text" name="nume" size="40" placeholder="Nume">
	<input type="text" name="telefon" size="40" placeholder="Telefon">
	<input type="text" name="email" size="40" placeholder="Email">
	<textarea name="comentarii" cols="36" rows="5" placeholder="Message"></textarea> 
	<input id="submitBtn" type="submit" name="submit" value="Trimite">
</form>


JavaScript (in the same file as the above form):

<script type="text/javascript">
	$(document).ready(function(e) {
	
        $("#contactForm").submit(function() {
			$.post("getcontact.php", $("#contactForm").serialize())
			// Serialization looks good: name=textInNameInput&&telefon=textInPhoneInput etc
			.done(function(data) {
				if (data.trim().length > 0) {
					$("#sent").text("Error");	
				} else {
					$("#sent").text("Success");
				}
			});
			
			return false;
		})
    });
</script>


Server side PHP (/getcontact.php):

$nume = $_REQUEST["nume"]; // $nume contains no data. Also tried $_POST
$email = $_REQUEST["email"];
$telefon = $_REQUEST["telefon"];
$comentarii = $_REQUEST["comentarii"];


Can you please tell me what I am doing wrong?


##UPDATE Checked var_dump($_POST) and it returned an empty array.

The weird thing is that the same code tested on my local machine works fine. If I upload the files on my hosting space it stops working. I tried doing an old-fashioned form without using jQuery and all data was correct.

I don't see how this would be a server configuration problem. Any ideas?

Thank you!

Php Solutions


Solution 1 - Php

You can use this function

var datastring = $("#contactForm").serialize();
$.ajax({
    type: "POST",
    url: "your url.php",
    data: datastring,
    dataType: "json",
    success: function(data) {
        //var obj = jQuery.parseJSON(data); if the dataType is not specified as json uncomment this
        // do what ever you want with the server response
    },
    error: function() {
        alert('error handling here');
    }
});

return type is json

EDIT: I use event.preventDefault to prevent the browser getting submitted in such scenarios.

Adding more data to the answer.

dataType: "jsonp" if it is a cross-domain call.

beforeSend: // this is a pre-request call back function

complete: // a function to be called after the request ends.so code that has to be executed regardless of success or error can go here

async: // by default, all requests are sent asynchronously

cache: // by default true. If set to false, it will force requested pages not to be cached by the browser.

Find the official page here

Solution 2 - Php

You can add extra data with form data

use serializeArray and add the additional data:

var data = $('#myForm').serializeArray();
    data.push({name: 'tienn2t', value: 'love'});
    $.ajax({
      type: "POST",
      url: "your url.php",
      data: data,
      dataType: "json",
      success: function(data) {
          //var obj = jQuery.parseJSON(data); if the dataType is not     specified as json uncomment this
        // do what ever you want with the server response
     },
    error: function() {
        alert('error handing here');
    }
});

Solution 3 - Php

 $("#contactForm").submit(function() {

    $.post(url, $.param($(this).serializeArray()), function(data) {

	});
 });

Solution 4 - Php

Have you checked in console if data from form is properly serialized? Is ajax request successful? Also you didn't close placeholder quote in, which can cause some problems:

 <textarea name="comentarii" cols="36" rows="5" placeholder="Message>  

Solution 5 - Php

Have you looked in firebug if POST or GET?.

check the console display.

Put in the test script:

console.log(data);

You can see the response from the server, if it shows something.

Solution 6 - Php

The problem can be PHP configuration:

Please check the setting max_input_vars in the php.ini file.

Try to increase the value of this setting to 5000 as example.

max_input_vars = 5000

Then restart your web-server and try.

Solution 7 - Php

Two End Registration or Users Automatically Registered to "Shouttoday" by ajax when they Complete Registration by form submission.

var deffered = $.ajax({
     url:"code.shouttoday.com/ajax_registration",
     type:"POST",
     data: $('form').serialize()
    });	

    	$(function(){ 
    		var form;
    		$('form').submit( function(event) {
    		    var formId = $(this).attr("id");
    		        form = this;
    		    event.preventDefault();
    		    deffered.done(function(response){
    				alert($('form').serializeArray());alert(response);
    				alert("success");
    				alert('Submitting');
    		        form.submit();
    			})
    			.error(function(){
    				alert(JSON.stringify($('form').serializeArray()).toString());
    				alert("error");
    				form.submit();
    			});
    		});
         });

 
		

Solution 8 - Php

Here is a more detailed and explained version of @rahulbhondave answer

$('#my-button').click(function () {
    $.post(this.form.action, $(this.form).serializeArray(),
            function (successMessage) {
                console.log(
                    successMessage
                );
            },
            "json"
        )
        .done(function () {
            alert("second success");
        })
        .fail(function () {
            alert("error");
        })
        .always(function () {
            alert("finished");
        });
});

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionDan DinuView Question on Stackoverflow
Solution 1 - PhpzamilView Answer on Stackoverflow
Solution 2 - PhpĐọc truyện hayView Answer on Stackoverflow
Solution 3 - PhprahulbhondaveView Answer on Stackoverflow
Solution 4 - PhpJan.JView Answer on Stackoverflow
Solution 5 - PhpA. M. MéridaView Answer on Stackoverflow
Solution 6 - PhpDXB-DEVView Answer on Stackoverflow
Solution 7 - PhpZigri2612View Answer on Stackoverflow
Solution 8 - PhpHicham O-SfhView Answer on Stackoverflow