Got it! The clue was on [selenium.webdriver.remote.webelement — Selenium 3.14 documentation.][1]

WebElements have the properties `.size` and `.location`. Both are of type `dict`.

    driver = webdriver.Firefox()

    e = driver.find_element_by_xpath(&quot;//someXpath&quot;)

    location = e.location
    size = e.size
    w, h = size[&#39;width&#39;], size[&#39;height&#39;]

    print(location)
    print(size)
    print(w, h)
    
Output:

    {&#39;y&#39;: 202, &#39;x&#39;: 165}
    {&#39;width&#39;: 77, &#39;height&#39;: 22}
    77 22
   
    
   
They also have a property called [`rect`][2] which is itself a `dict`, and contains the element&#39;s `size` and `location`.


  [1]: https://seleniumhq.github.io/selenium/docs/api/py/webdriver_remote/selenium.webdriver.remote.webelement.html
  [2]: https://seleniumhq.github.io/selenium/docs/api/py/webdriver_remote/selenium.webdriver.remote.webelement.html#selenium.webdriver.remote.webelement.WebElement.rect

I have a table with 1000+ partitions. 

&quot;`Show partitions`&quot; command only lists a small number of partitions.

How can i show all partitions?

Update:

1. I found &quot;`show partitions`&quot; command only lists exactly 500 partitions.

2. &quot;`select ... where ...`&quot; only processes the 500 partitions!


Hive: how to show all partitions of a table?

I am totally a newbie with Maven.
I want to create a Maven project with Eclipse Juno EE with archetype &quot;webapp&quot;. I installed &quot;Maven Integration for Eclipse WTP (incubation)&quot; and I also have installed &quot;Maven Integration for Eclipse&quot; (found it on Installed tab of Eclipse Marketplace).
When I try to create new Project from **File-&gt;New_&gt;Maven Project**, I obtain error:

&lt;pre&gt;
Could not resolve archetype org.apache.maven.archetypes:maven-archetype-webapp:RELEASE from any of the configured repositories.
Could not resolve artifact org.apache.maven.archetypes:maven-archetype-webapp:pom:RELEASE
Failed to resolve version for org.apache.maven.archetypes:maven-archetype-webapp:pom:RELEASE: Could not find metadata org.apache.maven.archetypes:maven-archetype-webapp/maven-metadata.xml in local (C:\Documents and Settings\PEP35KD\.m2\repository)
Failed to resolve version for org.apache.maven.archetypes:maven-archetype-webapp:pom:RELEASE: Could not find metadata org.apache.maven.archetypes:maven-archetype-webapp/maven-metadata.xml in local (C:\Documents and Settings\PEP35KD\.m2\repository)
&lt;/pre&gt;

It happens for all kinds of archetype.
I am using a proxy, and I create file settings.xml under C:\Documents and Settings\PEP35KD\.m2\ with this content:

    &lt;proxies&gt;
        &lt;proxy&gt;
            &lt;id&gt;myId&lt;/id&gt;
            &lt;active&gt;true&lt;/active&gt;
            &lt;protocol&gt;http&lt;/protocol&gt;
            &lt;username&gt;rete\pep35kd&lt;/username&gt;
            &lt;password&gt;XXXX&lt;/password&gt;
            &lt;host&gt;XXXX&lt;/host&gt;
            &lt;port&gt;8080&lt;/port&gt;
            &lt;nonProxyHosts&gt;localhost&lt;/nonProxyHosts&gt;
        &lt;/proxy&gt;
    &lt;/proxies&gt;

Please, consider that it seems that I cannot use mvn command from command line (command not found). I never installed Maven itself, I thinked that plugin is just enough: is it a correct assumption?


**UPDATE** Problem is definitely related to proxy. By:

 - Installing Maven on local PC;
 - Installing Maven Eclipse from Eclipse
   Market Place;
 - Setting Maven Install directory to local PC Maven dir, instead of default Embedded Maven,

everything works as expected. I cannot really understand why, but probably firewall is blocking traffic with Maven servers.



Create a Maven project in Eclipse complains &quot;Could not resolve archetype&quot;

I see that there are methods for getting the screen position and dimensions of an element through various Java libraries for Selenium, such as `org.openqa.selenium.Dimension`, which offers `.getSize()`, and `org.openqa.selenium.Point` with `getLocation()`.

Is there any way to get either the location or dimensions of an element with the Selenium Python bindings?

Selenium: get coordinates or dimensions of element with Python

<p>I see that there are methods for getting the screen position and dimensions of an element through various Java libraries for Selenium, such as <code>org.openqa.selenium.Dimension</code>, which offers <code>.getSize()</code>, and <code>org.openqa.selenium.Point</code> with <code>getLocation()</code>.</p>
<p>Is there any way to get either the location or dimensions of an element with the Selenium Python bindings?</p>


I have a function which reads a list of items from a file. How can I select only 50 items from the list randomly to write to another file?

    def randomizer(input, output=&#39;random.txt&#39;):
        query = open(input).read().split()
        out_file = open(output, &#39;w&#39;)
        
        random.shuffle(query)
        
        for item in query:
            out_file.write(item + &#39;\n&#39;)   

For example, if the total randomization file was
    
    random_total = [&#39;9&#39;, &#39;2&#39;, &#39;3&#39;, &#39;1&#39;, &#39;5&#39;, &#39;6&#39;, &#39;8&#39;, &#39;7&#39;, &#39;0&#39;, &#39;4&#39;]

and I would want a random set of 3, the result could be

    random = [&#39;9&#39;, &#39;2&#39;, &#39;3&#39;]

How can I select 50 from the list that I randomized?

Even better, how could I select 50 at random from the original list?

Select 50 items from list at random

I&#39;m trying to run a script that launches, amongst other things, a python script.  I get a ImportError: No module named ..., however, if I launch ipython and import the same module in the same way through the interpreter, the module is accepted.  

What&#39;s going on, and how can I fix it?  I&#39;ve tried to understand how python uses PYTHONPATH but I&#39;m thoroughly confused.  Any help would greatly appreciated.  

&quot;ImportError: No module named&quot; when trying to run Python script

This was causing me a bit of grief...

I created a dictionary from a list

    l = [&#39;a&#39;,&#39;b&#39;,&#39;c&#39;]
    d = dict.fromkeys(l, [0,0]) # initializing dictionary with [0,0] as values

    d[&#39;a&#39;] is d[&#39;b&#39;] # returns True

How can I make each value of the dictionary a seperate list?  Is this possible without iterating over all keys and setting them equal to a list?  I&#39;d like to modify one list without changing all the others.

dict.fromkeys all point to same list

In python how can you extend a class? For example if I have

color.py

    class Color:
        def __init__(self, color):
            self.color = color
        def getcolor(self):
            return self.color

color_extended.py

    import Color
    
    class Color:
        def getcolor(self):
            return self.color + &quot; extended!&quot;

But this doesn&#39;t work...
I expect that if I work in `color_extended.py`, then when I make a color object and use the `getcolor` function then it will return the object with the string &quot; extended!&quot; in the end. Also it should have gotton the init from the import.

Assume python 3.1

How to extend a class in python?

Working on a python assignment and was curious as to what [:-1] means in the context of the following code: `instructions = f.readline()[:-1]`

Have searched on here on S.O. and on Google but to no avail. Would love an explanation!

What does [:-1] mean/do in python?

I&#39;m trying to get the current url after a series of navigations in Selenium. I know there&#39;s a command called getLocation for ruby, but I can&#39;t find the syntax for Python.

How do I get current URL in Selenium Webdriver 2 Python?

I have a Selenium test suite that runs many tests and on each new test it opens a browser window on top of any other windows I have open. Very jarring while working in a local environment. Is there a way to tell Selenium or the OS (Mac) to open the windows in the background?




Can Selenium WebDriver open browser windows silently in the background?

I am working with the Selenium WebDriver 2.25.0 on multilingual web application &amp; mainly test the page content (For different languages like Arabic, English, Russian &amp; so on).

For my application which is better according to performance &amp; make sure that it should be support for all the browsers (i.e. IE 7,8,9, FF, Chrome etc).

Thanks in advance for your valueable suggestions.

What is the difference between cssSelector &amp; Xpath and which is better with respect to performance for cross browser testing?

I am trying to run a Selenium Webdriver script in Python to do some basic tasks. I can get the robot to function perfectly when running it through the Selenium IDE inteface (ie: when simply getting the GUI to repeat my actions). However when I export the code as a Python script and try to execute it from the command line, the Firefox browser will open but cannot ever access the starting URL (an error is returned to command line and the program stops). This is happening me regardless of what website etc I am trying to access.

I have included a very basic code here for demonstration purposes. I don&#39;t think that I have included the proxy section of the code correctly as the error being returned seems to be generated by the proxy.

Any help would be hugely appreciated. 

The below code is simply meant to open www.google.ie and search for the word &quot;selenium&quot;. For me it opens a blank firefox browser and stops.


    from selenium import webdriver
    from selenium.webdriver.common.by import By
    from selenium.webdriver.support.ui import Select
    from selenium.common.exceptions import NoSuchElementException
    import unittest, time, re
    from selenium.webdriver.common.proxy import *
    
    class Testrobot2(unittest.TestCase):
        def setUp(self):
    
    	    myProxy = &quot;http://149.215.113.110:70&quot;
    
    	    proxy = Proxy({
    	    &#39;proxyType&#39;: ProxyType.MANUAL,
    	    &#39;httpProxy&#39;: myProxy,
    	    &#39;ftpProxy&#39;: myProxy,
    	    &#39;sslProxy&#39;: myProxy,
    	    &#39;noProxy&#39;:&#39;&#39;})
    
            self.driver = webdriver.Firefox(proxy=proxy)
            self.driver.implicitly_wait(30)
            self.base_url = &quot;https://www.google.ie/&quot;
            self.verificationErrors = []
            self.accept_next_alert = True
        
        def test_robot2(self):
            driver = self.driver
            driver.get(self.base_url + &quot;/#gs_rn=17&amp;gs_ri=psy-ab&amp;suggest=p&amp;cp=6&amp;gs_id=ix&amp;xhr=t&amp;q=selenium&amp;es_nrs=true&amp;pf=p&amp;output=search&amp;sclient=psy-ab&amp;oq=seleni&amp;gs_l=&amp;pbx=1&amp;bav=on.2,or.r_qf.&amp;bvm=bv.47883778,d.ZGU&amp;fp=7c0d9024de9ac6ab&amp;biw=592&amp;bih=665&quot;)
            driver.find_element_by_id(&quot;gbqfq&quot;).clear()
            driver.find_element_by_id(&quot;gbqfq&quot;).send_keys(&quot;selenium&quot;)
        
        def is_element_present(self, how, what):
            try: self.driver.find_element(by=how, value=what)
            except NoSuchElementException, e: return False
            return True
        
        def is_alert_present(self):
            try: self.driver.switch_to_alert()
            except NoAlertPresentException, e: return False
            return True
        
        def close_alert_and_get_its_text(self):
            try:
                alert = self.driver.switch_to_alert()
                alert_text = alert.text
                if self.accept_next_alert:
                    alert.accept()
                else:
                    alert.dismiss()
                return alert_text
            finally: self.accept_next_alert = True
        
        def tearDown(self):
            self.driver.quit()
            self.assertEqual([], self.verificationErrors)
    
    if __name__ == &quot;__main__&quot;:
        unittest.main()



Running Selenium Webdriver with a proxy in Python

I want to do mouseover function over a drop down menu. When we hover over the menu, it will show the new options.
I tried to click the new options using the xpath. But cannot click the menus directly.
So, as the manual way I am trying to hover over the drop down menu and then will click the new options.

    Actions action = new Actions(webdriver);
    WebElement we = webdriver.findElement(By.xpath(&quot;//html/body/div[13]/ul/li[4]/a&quot;));
    action.moveToElement(we).build().perform();

Content Type	Original Author	Original Content on Stackoverflow
Question	meetar	View Question on Stackoverflow
Solution 1 - Python	meetar	View Answer on Stackoverflow

Selenium: get coordinates or dimensions of element with Python

Python Problem Overview

Python Solutions

Solution 1 - Python

Create a Maven project in Eclipse complains "Could not resolve archetype"

Hive: how to show all partitions of a table?

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