Selecting only first-level elements in jquery

JqueryHtmlCssCss Selectors

Jquery Problem Overview


How can I select the link elements of only the parent <ul> from a list like this?

<ul>
<li><a href="#">Link</a></li>
<li><a href="#">Link</a>
  <ul>
    <li><a href="#">Link</a></li>
    <li><a href="#">Link</a></li>
    <li><a href="#">Link</a></li>
    <li><a href="#">Link</a></li>
    <li><a href="#">Link</a></li>
  </ul>
</li>
<li><a href="#">Link</a></li>
<li><a href="#">Link</a></li>
<li><a href="#">Link</a></li>

So in css ul li a, but not ul li ul li a

Thanks

Jquery Solutions


Solution 1 - Jquery

$("ul > li a")

But you would need to set a class on the root ul if you specifically want to target the outermost ul:

<ul class="rootlist">
...

Then it's:

$("ul.rootlist > li a")....

Another way of making sure you only have the root li elements:

$("ul > li a").not("ul li ul a")

It looks kludgy, but it should do the trick

Solution 2 - Jquery

Once you have the initial ul, you can use the children() method, which will only consider the immediate children of the element. As @activa points out, one way to easily select the root element is to give it a class or an id. The following assumes you have a root ul with id root.

$('ul#root').children('li');

Solution 3 - Jquery

As stated in other answers, the simplest method is to uniquely identify the root element (by ID or class name) and use the direct descendent selector.

$('ul.topMenu > li > a')

However, I came across this question in search of a solution which would work on unnamed elements at varying depths of the DOM.

This can be achieved by checking each element, and ensuring it does not have a parent in the list of matched elements. Here is my solution, wrapped in a jQuery selector 'topmost'.

jQuery.extend(jQuery.expr[':'], {
  topmost: function (e, index, match, array) {
    for (var i = 0; i < array.length; i++) {
      if (array[i] !== false && $(e).parents().index(array[i]) >= 0) {
        return false;
      }
    }
    return true;
  }
});

Utilizing this, the solution to the original post is:

$('ul:topmost > li > a')

// Or, more simply:
$('li:topmost > a')

Complete jsFiddle available here.

Solution 4 - Jquery

Simply you can use this..

$("ul li a").click(function() {
  $(this).parent().find(">ul")...Something;
}

See example : https://codepen.io/gmkhussain/pen/XzjgRE

Solution 5 - Jquery

You might want to try this if results still flows down to children, in many cases JQuery will still apply to children.

$("ul.rootlist > li > a")

Using this method: E > F Matches any F element that is a child of an element E.

Tells JQuery to look only for explicit children. http://www.w3.org/TR/CSS2/selector.html

Solution 6 - Jquery

You can also use $("ul li:first-child") to only get the direct children of the UL.

I agree though, you need an ID or something else to identify the main UL otherwise it will just select them all. If you had a div with an ID around the UL the easiest thing to do would be$("#someDiv > ul > li")

Solution 7 - Jquery

Try this:

$("#myId > UL > LI")

Solution 8 - Jquery

I had some trouble with nested classes from any depth so I figured this out. It will select only the first level it encounters of a containing Jquery Object:

var $elementsAll = $("#container").find(".fooClass");4

var $levelOneElements = $elementsAll.not($elementsAll.children().find($elementsAll));

$levelOneElements.css({"color":"red"})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<div class="fooClass" style="color:black">
Container
  <div id="container">
    <div class="fooClass" style="color:black">
      Level One
      <div>
        <div class="fooClass" style="color:black">
             Level Two
        </div>
      </div>
    </div>
    <div class="fooClass" style="color:black">
      Level One
      <div>
        <div class="fooClass" style="color:black">
             Level Two
        </div>
      </div>
    </div>
  </div>
</div>

Solution 9 - Jquery

1

 $("ul.rootlist > target-element")
2   $("ul.rootlist").find(target-element).eq(0) (only one instance)
3   $("ul.rootlist").children(target-element)

there are probably many other ways

Solution 10 - Jquery

.add_to_cart >>> .form-item:eq(1)

the second .form-item at tree level child from the .add_to_cart

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionastonView Question on Stackoverflow
Solution 1 - JqueryPhilippe LeybaertView Answer on Stackoverflow
Solution 2 - JquerytvanfossonView Answer on Stackoverflow
Solution 3 - JqueryCourtney ChristensenView Answer on Stackoverflow
Solution 4 - JqueryGMKHussainView Answer on Stackoverflow
Solution 5 - JqueryTitanKingView Answer on Stackoverflow
Solution 6 - JqueryFiniteLooperView Answer on Stackoverflow
Solution 7 - JqueryLebnikView Answer on Stackoverflow
Solution 8 - JqueryShawn DoteyView Answer on Stackoverflow
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Solution 10 - JqueryisidoroView Answer on Stackoverflow