Select row and element in awk

Awk

Awk Problem Overview


I learned that in awk, $2 is the 2nd column. How to specify the ith line and the element at the ith row and jth column?

Awk Solutions


Solution 1 - Awk

To print the second line:

awk 'FNR == 2 {print}'

To print the second field:

awk '{print $2}'

To print the third field of the fifth line:

awk 'FNR == 5 {print $3}'

Here's an example with a header line and (redundant) field descriptions:

awk 'BEGIN {print "Name\t\tAge"}  FNR == 5 {print "Name: "$3"\tAge: "$2}'

There are better ways to align columns than "\t\t" by the way.

Use exit to stop as soon as you've printed the desired record if there's no reason to process the whole file:

awk 'FNR == 2 {print; exit}'

Solution 2 - Awk

To print the columns with a specific string, you use the // search pattern. For example, if you are looking for second columns that contains abc:

awk '$2 ~ /abc/'

... and if you want to print only a particular column:

awk '$2 ~ /abc/ { print $3 }'

... and for a particular line number:

awk '$2 ~ /abc/ && FNR == 5 { print $3 }'

Solution 3 - Awk

To expand on Dennis's answer, use awk's -v option to pass the i and j values:

# print the j'th field of the i'th line
awk -v i=5 -v j=3 'FNR == i {print $j}'

Solution 4 - Awk

Since awk and perl are closely related...


Perl equivalents of @Dennis's awk solutions:

To print the second line:
perl -ne 'print if $. == 2' file

To print the second field:
perl -lane 'print $F[1]' file

To print the third field of the fifth line:
perl -lane 'print $F[2] if $. == 5' file


Perl equivalent of @Glenn's solution:

Print the j'th field of the i'th line

perl -lanse 'print $F[$j-1] if $. == $i' -- -i=5 -j=3 file


Perl equivalents of @Hai's solutions:

if you are looking for second columns that contains abc:

perl -lane 'print if $F[1] =~ /abc/' foo

... and if you want to print only a particular column:

perl -lane 'print $F[2] if $F[1] =~ /abc/' foo

... and for a particular line number:

perl -lane 'print $F[2] if $F[1] =~ /abc/ && $. == 5' foo


-l removes newlines, and adds them back in when printing
-a autosplits the input line into array @F, using whitespace as the delimiter
-n loop over each line of the input file
-e execute the code within quotes
$F[1] is the second element of the array, since Perl starts at 0
$. is the line number

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionTimView Question on Stackoverflow
Solution 1 - AwkDennis WilliamsonView Answer on Stackoverflow
Solution 2 - AwkHai VuView Answer on Stackoverflow
Solution 3 - Awkglenn jackmanView Answer on Stackoverflow
Solution 4 - AwkChris KoknatView Answer on Stackoverflow