You need to replace everything but `[a-zA-Z0-9.-]`. 
The `^` within the brackets stands for &quot;NOT&quot;.

    myString = myString.replaceAll(&quot;[^a-zA-Z0-9\\.\\-]&quot;, &quot;_&quot;);

If you are looking for options on windows platform then you can try below solution to make use of all valid characters other than &quot;\\/:*?&quot;&lt;&gt;|&quot; in file name.

    fileName = fileName.replaceAll(&quot;[\\\\/:*?\&quot;&lt;&gt;|]&quot;, &quot;_&quot;);

Keep it simple.

    myString = myString.replaceAll(&quot;[^a-zA-Z0-9.-]&quot;, &quot;_&quot;);
    
http://ideone.com/TINsr4

Even simpler

    myString = myString.replaceAll(&quot;[^\\w.-]&quot;, &quot;_&quot;);

Predefined Character Classes:

 - `\w` 	A word character: `[a-zA-Z_0-9]`

I know there have been some answers here already, but I would like to point out that I had to alter the given suggestions slightly.

    filename.matches(&quot;^.*[^a-zA-Z0-9._-].*$&quot;)

This is what I had to use for .matches in Java to get the desired results. I am not sure if this is 100% correct, but this is how it worked for me, it would return true if it encountered any character other than a-z A-Z 0-9 (.) (_) and (-).

I would like to know if there are any flaws with my logic here.

In previous answers I&#39;ve seen some discussion of what should or should not be escaped. For this example, I&#39;ve gotten away without escaping anything, but you should escape the (-) minus character to be safe as it will &quot;break&quot; your expression unless it is at the end of the list.
The (.) dot character doesn&#39;t have to be escaped within the ([]) Square Braces it would seem, but it will not hurt you if you do escape it.

Please see Java [Patterns][1] for more details.

  [1]: https://docs.oracle.com/javase/8/docs/api/java/util/regex/Pattern.html

If you want to use more than like [A-Za-z0-9], then check [MS Naming Conventions][1], and dont forget to filter out &quot;...Characters whose integer representations are in the range from 1 through 31,...&quot;.


  [1]: https://msdn.microsoft.com/en-us/library/windows/desktop/aa365247%28v=vs.85%29.aspx#naming_conventions

Hello I&#39;m creating an API using REST and Laravel following [this][1] article.

Everything works well as expected.

Now, I want to map a GET request to recognise a variable using &quot;?&quot;.

For example: `domain/api/v1/todos?start=1&amp;limit=2`.

Below is the contents of my `routes.php` : 

    Route::any(&#39;api/v1/todos/(:num?)&#39;, array(
        &#39;as&#39;   =&gt; &#39;api.todos&#39;,
        &#39;uses&#39; =&gt; &#39;api.todos@index&#39;
    ));

My `controllers/api/todos.php` :

    class Api_Todos_Controller extends Base_Controller {

		public $restful = true;

		public function get_index($id = null) {
			if(is_null($id)) {
				return Response::eloquent(Todo::all(1));

			} else {
				$todo = Todo::find($id);
				if (is_null($todo)) {
					return Response::json(&#39;Todo not found&#39;, 404);
				} else {
					return Response::eloquent($todo);	
				}
			}
		}
    }

How do I GET a parameter using &quot;?&quot; ?

  [1]: http://maxoffsky.com/code-blog/building-restful-api-in-laravel-start-here/

Getting GET &quot;?&quot; Variable in Laravel

I am working a project using the AngularJS framework. I am pretty new to using this framework; in the past I have only worked with pure JavaScript and jQuery. The project is a kind of web designer application for a niche market.

As the user moves between pages while designing I want to maintain a session of all the changes they are making.

Now if the user signs in we load the session using data from the database. When the user clicks on save button we update the database with the session data. Someone told me that I can maintain session in Angular similar to backbone. Is this possible? If yes, can you please direct me to a tutorial that does not focus on directives or UI? If this is not possible are there other viable options?

Maintaining Session through Angular.js

In Java, I&#39;ve a File-Name-String. There I want to replace all illegal Characters with &#39;_&#39;, but not `a-z`, `0-9`, `-`,`.` and `_`

I tried following code: But this did not worked!

    myString = myString.replaceAll(&quot;[\\W][^\\.][^-][^_]&quot;, &quot;_&quot;);



Replacing illegal character in fileName

In Java, I've a File-Name-String. There I want to replace all illegal Characters with '_', but not <code>a-z</code>, <code>0-9</code>, <code>-</code>,<code>.</code> and <code>_</code>
I tried following code: But this did not worked!
<pre><code class="hljs language-ini">myString = myString.replaceAll("[\\W][^\\.][^-][^_]", "_");
</code></pre>

Java SSLHandshakeException &quot;no cipher suites in common&quot;

What does `.class` mean in Java? For example, if I created a class called `Print`. What does `Print.class` return?

What does .class mean in Java?

How do you pass in null values into a HashMap?  
The following code snippet works with options filled in:  

    HashMap&lt;String, String&gt; options = new HashMap&lt;String, String&gt;();  
    options.put(&quot;name&quot;, &quot;value&quot;);
    Person person = sample.searchPerson(options);  
    System.out.println(Person.getResult().get(o).get(Id));    

So the issue is what has to be entered into the options and or method to pass in a null value?  
I tried the following code without any success:    

    options.put(null, null);  
    Person person = sample.searchPerson(null);    

    options.put(&quot; &quot;, &quot; &quot;);  
    Person person = sample.searchPerson(null);    

    options.put(&quot;name&quot;, &quot; &quot;);  
    Person person = sample.searchPerson(null);  

    options.put();  
    Person person = sample.searchPerson();    

HashMaps and Null values?

I&#39;d like to be able to remotely connect to a Java service that has JMX exposed, however it is blocked by a firewall.  I have tried to use ssh local port forwarding, however the connection fails.  Looking at wireshark, it appears that when you try to connect with jconsole, it wants to connect via some ephemeral ports after connecting to port 9999, which are blocked by the firewall.

Is there any way to make jconsole only connect through 9999 or use a proxy?  Is [this article still the best solution][1]?  Or, am I missing something?

  [1]: https://web.archive.org/web/20150202095729/https://blogs.oracle.com/jmxetc/entry/connecting_through_firewall_using_jmx

JConsole over ssh local port forwarding

I have a jks keystore with no password.  When I run the command

    keytool -list -keystore mykeystore.jks

And it prompts me for the keystore password, I simply hit &#39;enter&#39;.

Please note that the keystore password IS NOT the default java password of &#39;changeit&#39;. It is blank

When I try to run

    keytool -storepasswd -keystore mykeystore.jks

to change the password to a non blank string. It firsts prompts me for the current password. Simply hitting enter since it is blank says

    keytool -storepasswd -keystore mykeystore.jks
    Enter keystore password:
    Keystore password is too short - must be at least 6 characters 

Just to confirm with everyone that the password is not &#39;changeit&#39;

    keytool -storepasswd -keystore mykeystore.jks
    Enter keystore password:  changeit
    keytool error: java.io.IOException: Keystore was tampered with, or password was incorrect

Any idea how I can change the keystore password if the existing password is blank?

Change keystore password from no password to a non blank password

I want to check if a String contains the words &quot;stores&quot;, &quot;store&quot;, and &quot;product&quot; in that order, no matter what is in between them.

I tried using `someString.contains(stores%store%product);` and also `.contains(&quot;stores%store%product&quot;);`

Do I need to explicitly declare a regex and pass it on the method or can I not pass a regex at all?

How to use regex in String.contains() method in Java

Could someone explain what `(?i)` and `(?-i)` wrapping a word in regex mean?

    (?i)test(?-i)

I tested and it matches `test`, `TEST`, and `teSt`. But I have never seen this before. What does the `?` before `i` mean? I saw this [here](https://github.com/dwilkie/carrierwave_direct/blob/master/lib/carrierwave_direct/uploader.rb#L85).


What do `?i` and `?-i` in regex mean?

I can use this code below to create a new file with the substitution of `a` with `aa` using regular expressions.

    import re

    with open(&quot;notes.txt&quot;) as text:
        new_text = re.sub(&quot;a&quot;, &quot;aa&quot;, text.read())
        with open(&quot;notes2.txt&quot;, &quot;w&quot;) as result:
            result.write(new_text)

 I was wondering do I have to use this line, `new_text = re.sub(&quot;a&quot;, &quot;aa&quot;, text.read())`, multiple times but substitute the string for others letters that I want to change in order to change more than one letter in my text? 

That is, so `a`--&gt;`aa`,`b`--&gt; `bb` and `c`--&gt; `cc`. 

So I have to write that line for all the letters I want to change or is there an easier way. Perhaps to create a &quot;dictionary&quot; of translations. Should I put those letters into an array? I&#39;m not sure how to call on them if I do. 

How can I do multiple substitutions using regex?

One of the lines in my script contains a PHP closing tag inside a string. Under normal operation this does not cause a problem, but I need to comment out the line.

I have tried to comment out this line with `//`, `/*` `*/` and `#` but none of them work, the parser considers closing tag to be an actual closing tag.

Here is the line in question:

    $string = preg_replace(&#39;#&lt;br\s*/?&gt;(?:\s*&lt;br\s*/?&gt;)+#i&#39;, &#39;&lt;br /&gt;&#39;, $string);
    //                              ^^             ^^

What can I do to comment out the above line?


Convert PHP closing tag into comment

of course I could replace specific arguments like this:

        mydata=c(&quot;&#225;&quot;,&quot;&#233;&quot;,&quot;&#243;&quot;)
        mydata=gsub(&quot;&#225;&quot;,&quot;a&quot;,mydata)
        mydata=gsub(&quot;&#233;&quot;,&quot;e&quot;,mydata)
        mydata=gsub(&quot;&#243;&quot;,&quot;o&quot;,mydata)
        mydata

but surely there is a easier way to do this all in onle line, right?
I dont find the gsub help to be very comprehensive on this. 

Replace multiple letters with accents with gsub

I need to recursively search for a specified string within all files and subdirectories within a directory and replace this string with another string.

I know that the command to find it might look like this:

    grep &#39;string_to_find&#39; -r ./*

But how can I replace every instance of `string_to_find` with another string?

How to grep and replace

I&#39;m trying to replace multiple words in a string with multiple other words. The string is &quot;I have a cat, a dog, and a goat.&quot;


However, this does not produce &quot;I have a dog, a goat, and a cat&quot;, but instead it produces &quot;I have a cat, a cat, and a cat&quot;. Is it possible to replace multiple strings with multiple other strings at the same time in JavaScript, so that the correct result will be produced?

    var str = &quot;I have a cat, a dog, and a goat.&quot;;
    str = str.replace(/cat/gi, &quot;dog&quot;);
    str = str.replace(/dog/gi, &quot;goat&quot;);
    str = str.replace(/goat/gi, &quot;cat&quot;);
    
    //this produces &quot;I have a cat, a cat, and a cat&quot;
    //but I wanted to produce the string &quot;I have a dog, a goat, and a cat&quot;.

Replace multiple strings with multiple other strings

I need to replace the whole line with `sed` if it matches a pattern.
For example if the line is &#39;one two six three four&#39; and if &#39;six&#39; is there, then the whole line should be replaced with &#39;fault&#39;.



Replace whole line when match found with sed

I have a parameter file of the form:

    parameter-name parameter-value

Where the parameters may be in any order but there is only one parameter per line.  I want to replace one parameter&#39;s `parameter-value` with a new value.

I am using a line replace function [posted previously][1] to replace the line which uses Python&#39;s [`string.replace(pattern, sub)`][2].  The regular expression that I&#39;m using works for instance in vim but doesn&#39;t appear to work in `string.replace()`. 

Here is the regular expression that I&#39;m using:

    line.replace(&quot;^.*interfaceOpDataFile.*$/i&quot;, &quot;interfaceOpDataFile %s&quot; % (fileIn))

Where `&quot;interfaceOpDataFile&quot;` is the parameter name that I&#39;m replacing (/i for case-insensitive) and the new parameter value is the contents of the `fileIn` variable. 

Is there a way to get Python to recognize this regular expression or else is there another way to accomplish this task?


  [1]: https://stackoverflow.com/questions/39086/search-and-replace-a-line-in-a-file-in-python
  [2]: http://www.tutorialspoint.com/python/string_replace.htm%20String.Replace

Python string.replace regular expression

How do I use JavaScript to detect

    &lt;br&gt;
    &lt;br&gt;
    &lt;br&gt;

to become one 

    &lt;br&gt;
?

I tried with:

    jQuery(&#39;body&#39;).html().replace(/(\&lt;br\&gt;\r\n){3, }/g,&quot;\n&quot;);

but this is not working for me.


Content Type	Original Author	Original Content on Stackoverflow
Question	bbholzbb	View Question on Stackoverflow
Solution 1 - Java	poitroae	View Answer on Stackoverflow
Solution 2 - Java	Prakash	View Answer on Stackoverflow
Solution 3 - Java	Matt Ball	View Answer on Stackoverflow
Solution 4 - Java	IvanRF	View Answer on Stackoverflow
Solution 5 - Java	Atspulgs	View Answer on Stackoverflow
Solution 6 - Java	wandlang	View Answer on Stackoverflow

Replacing illegal character in fileName

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Maintaining Session through Angular.js

Getting GET "?" Variable in Laravel

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