    &gt;&gt;&gt; stuff = &quot;Big and small&quot;
    &gt;&gt;&gt; stuff.replace(&quot; and &quot;,&quot;/&quot;)
    &#39;Big/small&#39;

Use the `replace()` method on string:

    &gt;&gt;&gt; stuff = &quot;Big and small&quot;
    &gt;&gt;&gt; stuff.replace( &quot; and &quot;, &quot;/&quot; )
    &#39;Big/small&#39;




You can easily use `.replace()` as also previously described. But it is also important to keep in mind that strings are immutable. Hence if you do not assign the change you are making to a variable, then you will not see any change. 
Let me explain by;

        &gt;&gt;stuff = &quot;bin and small&quot;
        &gt;&gt;stuff.replace(&#39;and&#39;, &#39;,&#39;)
        &gt;&gt;print(stuff)
        &quot;big and small&quot; #no change

To observe the change you want to apply, you can assign same or another variable;

        &gt;&gt;stuff = &quot;big and small&quot;
        &gt;&gt;stuff = stuff.replace(&quot;and&quot;, &quot;,&quot;)   
        &gt;&gt;print(stuff)
        &#39;big, small&#39;

In Java, I&#39;m working with the `BigDecimal` class and part of my code requires me to extract the fractional part from it.  `BigDecimal` does not appear to have any built in methods to help me get the number after the decimal point of a `BigDecimal`.

For example:

    BigDecimal bd = new BigDecimal(&quot;23452.4523434&quot;);

I want to extract the `4523434` from the number represented above.  What&#39;s the best way to do it?


Java, extract just the fractional part of a BigDecimal?

So I was looking at the [Android Dev Design site][1] for ICS and all of the apps have these subtitles/section headers:

![ICS Section Headers][2]

I was wondering if anyone knew the custom styling to achieve labels that look like this. I couldn&#39;t find any label Views that looked like this in the Android SDK but I really like the way these look.

Thanks in Advance!

  [1]: http://developer.android.com/design/index.html
  [2]: http://i.stack.imgur.com/UyC8L.png

Android 4.0 Sub-Title (section) Label Styling

I used regular expressions to get a string from a web page and part of the string may contain something I would like to replace with something else. How would it be possible to do this? My code is this, for example:

&lt;!-- language: lang-python --&gt;

    stuff = &quot;Big and small&quot;
    if stuff.find(&quot; and &quot;) == -1:
        # make stuff &quot;Big/small&quot;
    else:
        stuff = stuff

Replace part of a string in Python?

I used regular expressions to get a string from a web page and part of the string may contain something I would like to replace with something else. How would it be possible to do this? My code is this, for example:

<pre><code class="hljs language-ini">stuff = "Big and small"
if stuff.find(" and ") == -1:
 # make stuff "Big/small"
else:
 stuff = stuff
</code></pre>

I am attempting to filter users by a custom field in each users profile called profile. This field is called level and is an integer between 0-3.

If I filter using equals, I get a list of users with the chosen level as expected:

    user_list = User.objects.filter(userprofile__level = 0)

When I try to filter using less than:

    user_list = User.objects.filter(userprofile__level &lt; 3)

I get the error:

&gt; global name &#39;userprofile__level&#39; is not defined

Is there a way to filter by &lt; or &gt;, or am I barking up the wrong tree.

How to do a less than or equal to filter in Django queryset?

I am using pylab in matplotlib to create a plot and save the plot to an image file. However, when I save the image using `pylab.savefig( image_name )`, I find that the **SIZE** image saved is the same as the image that is shown when I use `pylab.show()`.

As it happens, I have a lot of data in the plot and when I am using `pylab.show()`, I have to maximize the window before I can see all of the plot correctly, and the xlabel tickers don&#39;t superimpose on each other.

Is there anyway that I can programmatically &#39;maximize&#39; the window before saving the image to file? - at the moment, I am only getting the &#39;default&#39; window size image, which results in the x axis labels being superimposed on one another.

How to make savefig() save image for &#39;maximized&#39; window instead of default size

A common antipattern in Python is to concatenate a sequence of strings using `+` in a loop. This is bad because the Python interpreter has to create a new string object for each iteration, and it ends up taking quadratic time. (Recent versions of CPython can apparently optimize this in some cases, but other implementations can&#39;t, so programmers are discouraged from relying on this.) `&#39;&#39;.join` is the right way to do this.

However, I&#39;ve heard it said ([including here on Stack Overflow](https://stackoverflow.com/questions/10001301/list-slicing-python/10001401#10001401)) that you should _never, ever_ use `+` for string concatenation, but instead always use `&#39;&#39;.join` or a format string. I don&#39;t understand why this is the case if you&#39;re only concatenating two strings. If my understanding is correct, it shouldn&#39;t take quadratic time, and I think `a + b` is cleaner and more readable than either `&#39;&#39;.join((a, b))` or `&#39;%s%s&#39; % (a, b)`.

Is it good practice to use `+` to concatenate two strings? Or is there a problem I&#39;m not aware of?

Any reason not to use &#39;+&#39; to concatenate two strings?

I want to use matplotlib to illustrate the definite integral between two regions: x_0, and x_1. 

How can I shade a region under a curve in matplotlib from x=-1, to x=1 given the following plot


    import numpy as np
    from matplotlib import pyplot as plt
    def f(t):
        return t * t

    t = np.arange(-4,4,1/40.)
    plt.plot(t,f(t))


How to shade region under the curve in matplotlib

Say I have a list `x` with unkown length from which I want to randomly pop one element so that the list does not contain the element afterwards. What is the most pythonic way to do this?

I can do it using a rather unhandy combincation of `pop`, `random.randint`, and `len`, and would like to see shorter or nicer solutions:

    import random
    x = [1,2,3,4,5,6]
    x.pop(random.randint(0,len(x)-1))

 What I am trying to achieve is consecutively pop random elements from a list. (i.e., randomly pop one element and move it to a dictionary, randomly pop another element and move it to another dictionary, ...)


Note that I am using Python 2.6 and did not find any solutions via the search function.

What is the most pythonic way to pop a random element from a list?

I tried many ways to get a ***single backslash*** from an **executed** (I don&#39;t mean an input from `html`).  

I can get *special characters* as tab, new line and many others then escape them to `\\t` or `\\n` or `\\(someother character)` but I cannot get a single backslash when a *non-special character* is next to it.  

I don&#39;t want something like:

    str = &quot;\apple&quot;;   // I want this, to return:
    console.log(str); // \apple
and if I try to get character at 0 then I get `a` instead of `\`.

How can I use backslashes (\) in a string?

&lt;p&gt;I know this is a quite easy problem but I just want to solve it for myself once and for all&lt;/p&gt;
&lt;p&gt;I would simply like to split a string into an array using a character as the split delimiter. (Much like the C#&#39;s famous &lt;b&gt;.Split()&lt;/b&gt; function. I can of course apply the brute-force approach but I wonder if there anything better than that.&lt;/p&gt;
&lt;p&gt;So far the I&#39;ve searched and probably the &lt;b&gt;closest&lt;/b&gt; solution approach is the usage of &lt;b&gt;strtok()&lt;/b&gt;, however due to it&#39;s inconvenience(converting your string to a char array etc.) I do not like using it. Is there any easier way to implement this?&lt;/p&gt;

&lt;p&gt;&lt;b&gt;Note: &lt;/b&gt;I wanted to emphasize this because people might ask &quot;How come brute-force doesn&#39;t work&quot;. My brute-force solution was to create a loop, and use the &lt;b&gt;substr()&lt;/b&gt; function inside. However since it requires the &lt;b&gt;starting point&lt;/b&gt; and the length, it fails when I want to split a date. Because user might enter it as 7/12/2012 or 07/3/2011, where I can really tell the length before calculating the next location of &#39;/&#39; delimiter.&lt;/p&gt;

Splitting a string by a character

I&#39;m trying to understand what the best practice is and why for concatenating string literals and variables for different cases. For instance, if I have code like this

    StringBuilder sb = new StringBuilder(&quot;AAAAAAAAAAAAA&quot;)
        .append(B_String).append(&quot;CCCCCCCCCCC&quot;).append(D_String)
        .append(&quot;EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE&quot;)
        .append(&quot;FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF&quot;);

Is this the way to do it? From [this post][1], I noticed that the `+` operator on Strings creates a new instance of StringBuilder, concatenates the operands, and returns a String conversion, which seems like a lot more work than just calling `.append()`; so if that&#39;s true, then that is out of the question. But what about `String.concat()`? Is it proper to use `.append()` for every concatenation? Or just for variables, and literals are okay to append with `.concat()`?

    StringBuilder sb = new StringBuilder(&quot;AAAAAAAAAAAAA&quot;)
        .append(B_String.concat(&quot;CCCCCCCCCCC&quot;)).append(D_String
        .concat(&quot;EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE&quot;)
        .concat(&quot;FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF&quot;));

What are the general rules for best practices and performance for going about these situations? Is my assumption correct on `+` and it should really just not be used?


  [1]: https://stackoverflow.com/questions/47605/java-string-concatenation

Best practices/performance: mixing StringBuilder.append with String.concat

I want to split a string like 

    &quot;first     middle  last&quot; 

with `String.split()`. But when i try to split it I get 

    String[] array = {&quot;first&quot;,&quot;&quot;,&quot;&quot;,&quot;&quot;,&quot;middle&quot;,&quot;&quot;,&quot;last&quot;}

I tried using `String.isEmpty()` to check for empty strings after I split them but I it doesn&#39;t work in android.  Here is my code:

    String s = &quot;First  Middle Last&quot;;
    String[] array = s.split(&quot; &quot;);
    for(int i=0; i&lt;array.length; i++) {
      //displays segmented strings here
    }

I think there is a way to split it like this: `{&quot;first&quot;,&quot;middle&quot;,&quot;last&quot;}` but can&#39;t figure out how.

Thanks for the help!

Splitting a string with multiple spaces

    i := 123
    s := string(i) 

s is &#39;E&#39;, but what I want is &quot;123&quot;

Please tell me how can I get &quot;123&quot;.

And in Java, I can do in this way: 

    String s = &quot;ab&quot; + &quot;c&quot;  // s is &quot;abc&quot;

how can I `concat` two strings in Go?

Content Type	Original Author	Original Content on Stackoverflow
Question	Markum	View Question on Stackoverflow
Solution 1 - Python	jamylak	View Answer on Stackoverflow
Solution 2 - Python	Russell Borogove	View Answer on Stackoverflow
Solution 3 - Python	Kubra Tas	View Answer on Stackoverflow

Replace part of a string in Python?

Python Problem Overview

Python Solutions

Solution 1 - Python

Solution 2 - Python

Solution 3 - Python

Android 4.0 Sub-Title (section) Label Styling

Java, extract just the fractional part of a BigDecimal?

Attributions