Remove the last chars of the Java String variable

JavaString

Java Problem Overview


A java String variable whose value is

String path = "http://cdn.gs.com/new/downloads/Q22010MVR_PressRelease.pdf.null"

I want to remove the last four characters i.e., .null. Which method I can use in order to split.

Java Solutions


Solution 1 - Java

I think you want to remove the last five characters ('.', 'n', 'u', 'l', 'l'):

path = path.substring(0, path.length() - 5);

Note how you need to use the return value - strings are immutable, so substring (and other methods) don't change the existing string - they return a reference to a new string with the appropriate data.

Or to be a bit safer:

if (path.endsWith(".null")) {
  path = path.substring(0, path.length() - 5);
}

However, I would try to tackle the problem higher up. My guess is that you've only got the ".null" because some other code is doing something like this:

path = name + "." + extension;

where extension is null. I would conditionalise that instead, so you never get the bad data in the first place.

(As noted in a question comment, you really should look through the String API. It's one of the most commonly-used classes in Java, so there's no excuse for not being familiar with it.)

Solution 2 - Java

import org.apache.commons.lang3.StringUtils;

// path = "http://cdn.gs.com/new/downloads/Q22010MVR_PressRelease.pdf.null"
StringUtils.removeEnd(path, ".null");
// path = "http://cdn.gs.com/new/downloads/Q22010MVR_PressRelease.pdf"

Solution 3 - Java

path = path.substring(0, path.length() - 5);

Solution 4 - Java

I am surprised to see that all the other answers (as of Sep 8, 2013) either involve counting the number of characters in the substring ".null" or throw a StringIndexOutOfBoundsException if the substring is not found. Or both :(

I suggest the following:

public class Main {

    public static void main(String[] args) {

        String path = "file.txt";
        String extension = ".doc";

        int position = path.lastIndexOf(extension);

        if (position!=-1)
            path = path.substring(0, position);
        else
            System.out.println("Extension: "+extension+" not found");

        System.out.println("Result: "+path);
    }

}

If the substring is not found, nothing happens, as there is nothing to cut off. You won't get the StringIndexOutOfBoundsException. Also, you don't have to count the characters yourself in the substring.

Solution 5 - Java

If you like to remove last 5 characters, you can use:

path.substring(0,path.length() - 5)

( could contain off by one error ;) )

If you like to remove some variable string:

path.substring(0,path.lastIndexOf('yoursubstringtoremove));

(could also contain off by one error ;) )

Solution 6 - Java

Another way:

if (s.size > 5) s.reverse.substring(5).reverse

BTW, this is Scala code. May need brackets to work in Java.

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionSangram AnandView Question on Stackoverflow
Solution 1 - JavaJon SkeetView Answer on Stackoverflow
Solution 2 - JavaMatthew Steven MonkanView Answer on Stackoverflow
Solution 3 - Javajuergen dView Answer on Stackoverflow
Solution 4 - JavaAliView Answer on Stackoverflow
Solution 5 - JavaKonstantin PribludaView Answer on Stackoverflow
Solution 6 - JavaJus12View Answer on Stackoverflow