When plotting a plot using matplotlib:

How to remove the box of the legend?

    plt.legend(frameon=False)

How to change the color of the border of the legend box?

    leg = plt.legend()
    leg.get_frame().set_edgecolor(&#39;b&#39;)

How to remove only the border of the box of the legend?

    leg = plt.legend()
    leg.get_frame().set_linewidth(0.0)

For the `matplotlib` object oriented approach:

    axes.legend(frameon=False)
    
    leg = axes.legend()
    leg.get_frame().set_edgecolor(&#39;b&#39;)
    leg.get_frame().set_linewidth(0.0)

One more related question, since it took me forever to find the answer:

**How to make the legend background blank (*i.e.* transparent, not white):**

    legend = plt.legend()
    legend.get_frame().set_facecolor(&#39;none&#39;)

Warning, you want `&#39;none&#39;` (the string). `None` means the default color instead.

I have created an ubuntu image with nginx, php and postgres.

I want to connect the postgres database in my current image with `pgadmin` located on my local machine. 

I have tried using docker inspector to try to use the image ip to make a connection with my local pgadmin but without much success. I&#39;ve also tried configuring some ports on local to make connection work.

docker postgres pgadmin local connection

I am very new to Swift (got started this week) and I&#39;m migrating my app from Objective-C. I have basically the following code in Objective-C that works fine:

    typedef enum : int {
        MyTimeFilter1Hour = 1,
        MyTimeFilter1Day = 2,
        MyTimeFilter7Day = 3,
        MyTimeFilter1Month = 4,
    } MyTimeFilter;

    ...

    - (void)selectFilter:(id)sender
    {
        self.timeFilterSelected = (MyTimeFilter)((UIButton *)sender).tag;
        [self closeAnimated:YES];
    }

When translating it to Swift, I did the following:

    enum MyTimeFilter : Int {
        case OneHour = 1
        case OneDay = 2
        case SevenDays = 3
        case OneMonth = 4
    }
    
    ...
    
    @IBAction func selectFilter(sender: AnyObject) {
        self.timeFilterSelected = (sender as UIButton).tag as MyTimeFilter
        self.close(true)
    }

By doing that, I get the error :

&gt; &#39;Int&#39; is not convertible to &#39;MyTimeFilter&#39;

I don&#39;t know if my approach (using the tag property) is the best, but anyway I need to do this kind of casting in different places in my app. Does anyone have an idea of how to get rid of this error?

Thanks!

Swift - Cast Int into enum:Int

When plotting a plot using matplotlib:

 1. How to remove the box of the legend? 
 2. How to change the color of the border of the legend box?
 3. How to remove only the border of the box of the legend?

 

Remove or adapt border of frame of legend using matplotlib

When plotting a plot using matplotlib:
<ol>
<li>
How to remove the box of the legend?
</li>
<li>
How to change the color of the border of the legend box?
</li>
<li>
How to remove only the border of the box of the legend?
</li>
</ol>

I need some way to use a function within pool.map() that accepts more than one parameter. As per my understanding, the target function of pool.map() can only have one iterable as a parameter but is there a way that I can pass other parameters in as well? In this case, I need to pass in a few configuration variables, like my Lock() and logging information to the target function.

I have tried to do some research and I think that I may be able to use partial functions to get it to work? However I don&#39;t fully understand how these work. Any help would be greatly appreciated! Here is a simple example of what I want to do:

    def target(items, lock):
        for item in items:
            # Do cool stuff
            if (... some condition here ...):
                lock.acquire()
                # Write to stdout or logfile, etc.
                lock.release()

    def main():
        iterable = [1, 2, 3, 4, 5]
        pool = multiprocessing.Pool()
        pool.map(target(PASS PARAMS HERE), iterable)
        pool.close()
        pool.join()



Passing multiple parameters to pool.map() function in Python

I am attempting to use a partial function so that pool.map() can target a function that has more than one parameter (in this case a Lock() object).

Here is example code (taken from an answer to a previous question of mine):

    from functools import partial

    def target(lock, iterable_item):
        for item in items:
            # Do cool stuff
            if (... some condition here ...):
                lock.acquire()
                # Write to stdout or logfile, etc.
                lock.release()

    def main():
        iterable = [1, 2, 3, 4, 5]
        pool = multiprocessing.Pool()
        l = multiprocessing.Lock()
        func = partial(target, l)
        pool.map(func, iterable)
        pool.close()
        pool.join()

However when I run this code, I get the error:

    Runtime Error: Lock objects should only be shared between processes through inheritance.

What am I missing here? How can I share the lock between my subprocesses?

Python sharing a lock between processes

I&#39;m running this command:

    python manage.py test project.apps.app1.tests

and it causes this error:

&gt; AttributeError: &#39;module&#39; object has no attribute &#39;tests&#39;

Below is my directory structure. I&#39;ve also added app1 to my installed apps config.

    Traceback (most recent call last):
        File &quot;manage.py&quot;, line 10, in &lt;module&gt; execute_from_command_line(sys.argv)
        File &quot;/home/username/local/dev/local/lib/python2.7/site-packages/django/core/management/__init__.py&quot;, line 385, in execute_from_command_line
        utility.execute()
        File &quot;/home/username/local/dev/local/lib/python2.7/site-packages/django/core/management/__init__.py&quot;, line 377, in execute
        self.fetch_command(subcommand).run_from_argv(self.argv)
        File &quot;/home/username/local/dev/local/lib/python2.7/site-packages/django/core/management/commands/test.py&quot;, line 50, in run_from_argv
        super(Command, self).run_from_argv(argv)
        File &quot;/home/username/local/dev/local/lib/python2.7/site-packages/django/core/management/base.py&quot;, line 288, in run_from_argv
        self.execute(*args, **options.__dict__)
        File &quot;/home/username/local/dev/local/lib/python2.7/site-packages/django/core/management/commands/test.py&quot;, line 71, in execute
        super(Command, self).execute(*args, **options)
        File &quot;/home/username/local/dev/local/lib/python2.7/site-packages/django/core/management/base.py&quot;, line 338, in execute
        output = self.handle(*args, **options)
        File &quot;/home/username/local/dev/local/lib/python2.7/site-packages/django/core/management/commands/test.py&quot;, line 88, in handle
        failures = test_runner.run_tests(test_labels)
        File &quot;/home/username/local/dev/local/lib/python2.7/site-packages/django/test/runner.py&quot;, line 146, in run_tests
        suite = self.build_suite(test_labels, extra_tests)
        File &quot;/home/username/local/dev/local/lib/python2.7/site-packages/django/test/runner.py&quot;, line 66, in build_suite
        tests = self.test_loader.loadTestsFromName(label)
        File &quot;/usr/lib/python2.7/unittest/loader.py&quot;, line 100, in loadTestsFromName
        parent, obj = obj, getattr(obj, part)
        AttributeError: &#39;module&#39; object has no attribute &#39;tests&#39;

Directory structure:

![enter image description here][1]


  [1]: http://i.stack.imgur.com/DpRCx.png

AttributeError: &#39;module&#39; object has no attribute &#39;tests&#39;

Is there a way to do this?  I cannot seem an easy way to interface pandas series with plotting a CDF.  

Plotting CDF of a pandas series in python

I am trying to extract the text in an input box, 


    &lt;input type=&quot;text&quot; name=&quot;inputbox&quot; value=&quot;name&quot; class=&quot;box&quot;&gt;

I started with
     
    input = driver.find_element_by_name(&quot;inputbox&quot;)
    

I tried input.getText() but I got
    

    AttributeError: &#39;WebElement&#39; object has no attribute &#39;getText&#39;


Get value of an input box using Selenium (Python)

When I try to upgrade my matplotlib using pip, it outputs:

&lt;!-- language: lang-none --&gt;

    Downloading/unpacking matplotlib from https://pypi.python.org/packages/source/m/matplotlib/matplotlib-1.4.0.tar.gz#md5=1daf7f2123d94745feac1a30b210940c
      Downloading matplotlib-1.4.0.tar.gz (51.2MB): 51.2MB downloaded
      Running setup.py (path:/tmp/pip_build_root/matplotlib/setup.py) egg_info for package matplotlib
        ============================================================================
        Edit setup.cfg to change the build options

        BUILDING MATPLOTLIB
                    matplotlib: yes [1.4.0]
                        python: yes [2.7.6 (default, Mar 22 2014, 22:59:38)  [GCC
                                4.8.2]]
                      platform: yes [linux2]

        REQUIRED DEPENDENCIES AND EXTENSIONS
                         numpy: yes [version 1.8.2]
                           six: yes [using six version 1.7.3]
                      dateutil: yes [using dateutil version 2.2]
                       tornado: yes [using tornado version 4.0.1]
                     pyparsing: yes [using pyparsing version 2.0.2]
                         pycxx: yes [Couldn&#39;t import.  Using local copy.]
                        libagg: yes [pkg-config information for &#39;libagg&#39; could not
                                be found. Using local copy.]
        Traceback (most recent call last):
          File &quot;&lt;string&gt;&quot;, line 17, in &lt;module&gt;
          File &quot;/tmp/pip_build_root/matplotlib/setup.py&quot;, line 154, in &lt;module&gt;
            result = package.check()
          File &quot;setupext.py&quot;, line 940, in check
            if &#39;No such file or directory\ngrep:&#39; in version:
        TypeError: argument of type &#39;NoneType&#39; is not iterable
        Complete output from command python setup.py egg_info:
        ============================================================================

    Edit setup.cfg to change the build options



    BUILDING MATPLOTLIB

                matplotlib: yes [1.4.0]

                    python: yes [2.7.6 (default, Mar 22 2014, 22:59:38)  [GCC

                            4.8.2]]

                  platform: yes [linux2]



    REQUIRED DEPENDENCIES AND EXTENSIONS

                     numpy: yes [version 1.8.2]

                       six: yes [using six version 1.7.3]

                  dateutil: yes [using dateutil version 2.2]

                   tornado: yes [using tornado version 4.0.1]

                 pyparsing: yes [using pyparsing version 2.0.2]

                     pycxx: yes [Couldn&#39;t import.  Using local copy.]

                    libagg: yes [pkg-config information for &#39;libagg&#39; could not

                            be found. Using local copy.]

    Traceback (most recent call last):

      File &quot;&lt;string&gt;&quot;, line 17, in &lt;module&gt;

      File &quot;/tmp/pip_build_root/matplotlib/setup.py&quot;, line 154, in &lt;module&gt;

        result = package.check()

      File &quot;setupext.py&quot;, line 940, in check

        if &#39;No such file or directory\ngrep:&#39; in version:

    TypeError: argument of type &#39;NoneType&#39; is not iterable

    ----------------------------------------
    Cleaning up...
    Command python setup.py egg_info failed with error code 1 in /tmp/pip_build_root/matplotlib
    Storing debug log for failure in /home/username/.pip/pip.log

In the tail of the log it says:

    Exception information:
    Traceback (most recent call last):
      File &quot;/usr/local/lib/python2.7/dist-packages/pip-1.5.6-py2.7.egg/pip/basecommand.py&quot;, line 122, in main
        status = self.run(options, args)
      File &quot;/usr/local/lib/python2.7/dist-packages/pip-1.5.6-py2.7.egg/pip/commands/install.py&quot;, line 278, in run
        requirement_set.prepare_files(finder, force_root_egg_info=self.bundle, bundle=self.bundle)
      File &quot;/usr/local/lib/python2.7/dist-packages/pip-1.5.6-py2.7.egg/pip/req.py&quot;, line 1229, in prepare_files
        req_to_install.run_egg_info()
      File &quot;/usr/local/lib/python2.7/dist-packages/pip-1.5.6-py2.7.egg/pip/req.py&quot;, line 325, in run_egg_info
        command_desc=&#39;python setup.py egg_info&#39;)
      File &quot;/usr/local/lib/python2.7/dist-packages/pip-1.5.6-py2.7.egg/pip/util.py&quot;, line 697, in call_subprocess
        % (command_desc, proc.returncode, cwd))
    InstallationError: Command python setup.py egg_info failed with error code 1 in /tmp/pip_build_root/matplotlib

Why did it fail? 
Many thanks!


ubuntu 14.04, pip cannot upgrade matplotllib

I have following simple plot, and I would like to display the origin axis (x, y). I already have grid, but I need the x, y axis to be emphasized.

![enter image description here][1]

this is my code:

    x = linspace(0.2,10,100)
    plot(x, 1/x)
    plot(x, log(x))
    axis(&#39;equal&#39;)
    grid()

I have seen [this](https://stackoverflow.com/questions/4694478/center-origin-in-matplotlib) question. The accepted answer suggests to use &quot;Axis spine&quot; and just links to some example. The example is however too complicated, using subplots. I am unable to figure out, how to use &quot;Axis spine&quot; in my simple example.


  [1]: http://i.stack.imgur.com/a9hAQ.png

show origin axis (x,y) in matplotlib plot

I am plotting a NumPy array of values, `I`, using IPython notebook in `%matplotlib` inline mode with the plot command `plt.plot(I,&#39;o&#39;)`. 

The resulting output is:  

    &lt;matplotlib.figure.Figure at 0x119e6ead0&gt;
    Out[159]:
    [&lt;matplotlib.lines.Line2D at 0x11ac57090&gt;,
     &lt;matplotlib.lines.Line2D at 0x11ac57310&gt;,
     &lt;matplotlib.lines.Line2D at 0x11ac57510&gt;,
     &lt;matplotlib.lines.Line2D at 0x11ac57690&gt;,
     &lt;matplotlib.lines.Line2D at 0x11ac57810&gt;,
     &lt;matplotlib.lines.Line2D at 0x11ac57990&gt;,
     &lt;matplotlib.lines.Line2D at 0x11ac57b10&gt;,
     ....
     ....
    ]

Then my plot shows up below these lines of output. 

Is there a way to just show the plot and hide the `&lt;matplotlib.lines.Line2D at ...&gt;` from the output?


How to hide &lt;matplotlib.lines.Line2D&gt; in IPython notebook

What&#39;s the best practise to add a row and a column header to a grid of subplots generated in a loop in ``matplotlib``? I can think of a couple, but not particularly neat:

1. For columns, with a counter to your loop you can use ``set_title()`` for the first row only. For rows this doesn&#39;t work. You would have to draw ``text`` outside of the plots.
2. You add an extra row of subplots on top and an extra column of subplots on the left, and draw text in the middle of that subplot. 

Can you suggest a better alternative?

![enter image description here][1]


  [1]: http://i.stack.imgur.com/p2knC.png

Row and column headers in matplotlib&#39;s subplots

I have the following code:

    import matplotlib.pyplot as plt
    import matplotlib.image as mpimg
    import matplotlib.cm as cm

    img = mpimg.imread(&quot;lena.jpg&quot;)

    f, axarr = plt.subplots(2, 2)
    axarr[0,0].imshow(img, cmap = cm.Greys_r)
    axarr[0,0].set_title(&quot;Rank = 512&quot;)

    rank = 128
    new_img = prune_matrix(rank, img)
    axarr[0,1].imshow(new_img, cmap = cm.Greys_r)
    axarr[0,1].set_title(&quot;Rank = %s&quot; %rank)

    rank = 32
    new_img = prune_matrix(rank, img)
    axarr[1,0].imshow(new_img, cmap = cm.Greys_r)
    axarr[1,0].set_title(&quot;Rank = %s&quot; %rank)

    rank = 16
    new_img = prune_matrix(rank, img)
    axarr[1,1].imshow(new_img, cmap = cm.Greys_r)
    axarr[1,1].set_title(&quot;Rank = %s&quot; %rank)

    plt.show()

However, the result is pretty ugly because of the values on the axes:

![enter image description here][1]


  [1]: http://i.stack.imgur.com/2BDVr.jpg

How can I turn off axes values for all subplots simultaneously?

Content Type	Original Author	Original Content on Stackoverflow
Question	Mattijn	View Question on Stackoverflow
Solution 1 - Python	Mattijn	View Answer on Stackoverflow
Solution 2 - Python	Kevin J. Black	View Answer on Stackoverflow

Remove or adapt border of frame of legend using matplotlib

Python Problem Overview

Python Solutions

Solution 1 - Python

Solution 2 - Python

Swift - Cast Int into enum:Int

docker postgres pgadmin local connection

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