querySelectorAll with multiple conditions

Javascript

Javascript Problem Overview


Is it possible to make a search by querySelectorAll using multiple unrelated conditions? If yes how? And how to specify whether those are AND or OR criteria?

For example:

How to find all forms, ps and legends with a single querySelectorAll call? Possible?

Javascript Solutions


Solution 1 - Javascript

> Is it possible to make a search by querySelectorAll using multiple unrelated conditions?

Yes, because querySelectorAll accepts full CSS selectors, and CSS has the concept of selector groups, which lets you specify more than one unrelated selector. For instance:

var list = document.querySelectorAll("form, p, legend");

...will return a list containing any element that is a form or p or legend.

CSS also has the other concept: Restricting based on more criteria. You just combine multiple aspects of a selector. For instance:

var list = document.querySelectorAll("div.foo");

...will return a list of all div elements that also (and) have the class foo, ignoring other div elements.

You can, of course, combine them:

var list = document.querySelectorAll("div.foo, p.bar, div legend");

...which means "Include any div element that also has the foo class, any p element that also has the bar class, and any legend element that's also inside a div."

Solution 2 - Javascript

According to the documentation, just like with any css selector, you can specify as many conditions as you want, and they are treated as logical 'OR'.

> This example returns a list of all div elements within the document > with a class of either "note" or "alert":

var matches = document.querySelectorAll("div.note, div.alert");

source: https://developer.mozilla.org/en-US/docs/Web/API/Document/querySelectorAll

Meanwhile to get the 'AND' functionality you can for example simply use a multiattribute selector, as jquery says:

https://api.jquery.com/multiple-attribute-selector/

ex. "input[id][name$='man']" specifies both id and name of the element and both conditions must be met. For classes it's as obvious as ".class1.class2" to require object of 2 classes.

All possible combinations of both are valid, so you can easily get equivalent of more sophisticated 'OR' and 'AND' expressions.

Solution 3 - Javascript

With pure JavaScript you can do this (such as SQL) and anything you need, basically:

<input type='button' value='F3' class="c2" id="btn_1">
<input type='button' value='F3' class="c3" id="btn_2">
<input type='button' value='F1' class="c2" id="btn_3">

<input type='submit' value='F2' class="c1" id="btn_4">
<input type='submit' value='F1' class="c3" id="btn_5">
<input type='submit' value='F2' class="c1" id="btn_6">

<br/>
<br/>

<button onclick="myFunction()">Try it</button>

<script>
    function myFunction() 
    {
        var arrFiltered = document.querySelectorAll('input[value=F2][type=submit][class=c1]');

            arrFiltered.forEach(function (el)
            {                
                var node = document.createElement("p");
                
                node.innerHTML = el.getAttribute('id');

                window.document.body.appendChild(node);
            });
        }
    </script>

</body>

Solution 4 - Javascript

Yes, querySelectorAll does take a group of selectors:

form, p, legend

Solution 5 - Javascript

Using just document.querySelectorAll('selector1, selector2, selector3') didn't work for me, had to use forEach() method alongside to achieve the desired result.

document.querySelectorAll('selector1, selector2, selector3').forEach(item => {
        item.//code
    })

document.querySelectorAll('#id1, #id2, #id3').style = 'background-color: red';
document.querySelectorAll('#id4, #id5, #id6').forEach(item => {
    item.style = 'background-color: red';
})

<div id="id1">id1</div>
<div id="id2">id2</div>
<div id="id3">id3</div>
<div id="id4">id4</div>
<div id="id5">id5</div>
<div id="id6">id6</div>

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionAlan CoromanoView Question on Stackoverflow
Solution 1 - JavascriptT.J. CrowderView Answer on Stackoverflow
Solution 2 - JavascriptmikusView Answer on Stackoverflow
Solution 3 - JavascriptAlejandro D.V.View Answer on Stackoverflow
Solution 4 - JavascriptBergiView Answer on Stackoverflow
Solution 5 - Javascriptfirst userView Answer on Stackoverflow