Python Save to file

PythonPython 2.7

Python Problem Overview


I would like to save a string to a file with a python program named Failed.py

Here is what I have so far:

myFile = open('today','r')

ips = {}

for line in myFile:
    parts = line.split(' ')
    if parts[1] == 'Failure':
        if parts[0] in ips:
            ips[pars[0]] += 1
        else:
            ips[parts[0]] = 0

for ip in [k for k, v in ips.iteritems() if v >=5]:
    #write to file called Failed.py

Python Solutions


Solution 1 - Python

file = open('Failed.py', 'w')
file.write('whatever')
file.close()

Here is a more pythonic version, which automatically closes the file, even if there was an exception in the wrapped block:

with open('Failed.py', 'w') as file:
    file.write('whatever')

Solution 2 - Python

You need to open the file again using open(), but this time passing 'w' to indicate that you want to write to the file. I would also recommend using with to ensure that the file will be closed when you are finished writing to it.

with open('Failed.txt', 'w') as f:
    for ip in [k for k, v in ips.iteritems() if v >=5]:
        f.write(ip)

Naturally you may want to include newlines or other formatting in your output, but the basics are as above.

The same issue with closing your file applies to the reading code. That should look like this:

ips = {}
with open('today','r') as myFile:
    for line in myFile:
        parts = line.split(' ')
        if parts[1] == 'Failure':
            if parts[0] in ips:
                ips[pars[0]] += 1
            else:
                ips[parts[0]] = 0

Solution 3 - Python

You can use this function:

def saveListToFile(listname, pathtosave):
    file1 = open(pathtosave,"w") 
    for i in listname:
        file1.writelines("{}\n".format(i))    
    file1.close() 

# to save:
saveListToFile(list, path)

Solution 4 - Python

In order to write into a file in Python, we need to open it in write w, append a or exclusive creation x mode.

We need to be careful with the w mode, as it will overwrite into the file if it already exists. Due to this, all the previous data are erased.

Writing a string or sequence of bytes (for binary files) is done using the write() method. This method returns the number of characters written to the file.

with open('Failed.py','w',encoding = 'utf-8') as f:
   f.write("Write what you want to write in\n")
   f.write("this file\n\n")

This program will create a new file named Failed.py in the current directory if it does not exist. If it does exist, it is overwritten.

We must include the newline characters ourselves to distinguish the different lines.

Solution 5 - Python

myFile = open('today','r')

ips = {}

for line in myFile:
    parts = line.split()
    if parts[1] == 'Failure':
        ips.setdefault(parts[0], 0)
        ips[parts[0]] += 1

of = open('failed.py', 'w')
for ip in [k for k, v in ips.iteritems() if v >=5]:
    of.write(k+'\n')

Check out setdefault, it makes the code a little more legible. Then you dump your data with the file object's write method.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionStefanView Question on Stackoverflow
Solution 1 - PythonwarvariucView Answer on Stackoverflow
Solution 2 - PythonDavid HeffernanView Answer on Stackoverflow
Solution 3 - PythonALSHARGI NEWYORKView Answer on Stackoverflow
Solution 4 - PythonMRUNAL MUNOTView Answer on Stackoverflow
Solution 5 - PythonjaimeView Answer on Stackoverflow