Python Pandas read_csv skip rows but keep header

I'm having trouble figuring out how to skip n rows in a csv file but keep the header which is the 1 row.

What I want to do is iterate but keep the header from the first row. skiprows makes the header the first row after the skipped rows. What is the best way of doing this?

data = pd.read_csv('test.csv', sep='|', header=0, skiprows=10, nrows=10)

You can pass a list of row numbers to skiprows instead of an integer.

By giving the function the integer 10, you're just skipping the first 10 lines.

To keep the first row 0 (as the header) and then skip everything else up to row 10, you can write:

pd.read_csv('test.csv', sep='|', skiprows=range(1, 10))

---

Other ways to skip rows using read_csv

The two main ways to control which rows read_csv uses are the header or skiprows parameters.

Supose we have the following CSV file with one column:

a
b
c
d
e
f

In each of the examples below, this file is f = io.StringIO("\n".join("abcdef")).

• Read all lines as values (no header, defaults to integers)

    >>> pd.read_csv(f, header=None)
       0
    0  a
    1  b
    2  c
    3  d
    4  e
    5  f
  

• Use a particular row as the header (skip all lines before that):

    >>> pd.read_csv(f, header=3)
       d
    0  e
    1  f
  

• Use a multiple rows as the header creating a MultiIndex (skip all lines before the last specified header line):

    >>> pd.read_csv(f, header=[2, 4])                                                                                                                                                                        
       c
       e
    0  f
  

• Skip N rows from the start of the file (the first row that's not skipped is the header):

    >>> pd.read_csv(f, skiprows=3)                                                                                                                                                                      
       d
    0  e
    1  f
  

• Skip one or more rows by giving the row indices (the first row that's not skipped is the header):

    >>> pd.read_csv(f, skiprows=[2, 4])                                                                                                                                                                      
       a
    0  b
    1  d
    2  f
  

Great answers already. Consider this generalized scenario:

Say your xls/csv has junk rows in the top 2 rows (row #0,1). Row #2 (3rd row) is the real header and you want to load 10 rows starting from row #50 (i.e 51st row).

Here's the snippet:

pd.read_csv('test.csv', header=2, skiprows=range(3, 50), nrows=10)

To expand on @AlexRiley's answer, the skiprows argument takes a list of numbers which determines what rows to skip. So:

pd.read_csv('test.csv', sep='|', skiprows=range(1, 10))

is the same as:

pd.read_csv('test.csv', sep='|', skiprows=[1,2,3,4,5,6,7,8,9])

The best way to go about ignoring specific rows would be to create your ignore list (either manually or with a function like range that returns a list of integers) and pass it to skiprows.

If you're iterating through a long csv file, you can use the chunksize argument. If for some reason you need to manually step through it, you can try the following as long as you know how many iterations you need to go through:

for i in range(num_iters):
    pd.read_csv('test.csv', sep='|', header=0, 
                 skiprows = range(i*10 + 1, (i+1)*10), nrows=10)
    

If you need to skip/drop specific rows, say the first 3 rows (i.e. 0,1,2) and then 2 more rows (i.e. 4,5). You can use the following to retain the header row:

df = pd.read_csv(file_in, delimiter='\t', skiprows=[0,1,2,4,5], encoding='utf-16', usecols=cols)