Python MySQL connector - unread result found when using fetchone

PythonMysql

Python Problem Overview


I am inserting JSON data into a MySQL database

I am parsing the JSON and then inserting it into a MySQL db using the python connector

Through trial, I can see the error is associated with this piece of code

for steps in result['routes'][0]['legs'][0]['steps']:
    query = ('SELECT leg_no FROM leg_data WHERE travel_mode = %s AND Orig_lat = %s AND Orig_lng = %s AND Dest_lat = %s AND Dest_lng = %s AND time_stamp = %s')
    if steps['travel_mode'] == "pub_tran":
        travel_mode = steps['travel_mode']
        Orig_lat = steps['var_1']['dep']['lat']
        Orig_lng = steps['var_1']['dep']['lng']
        Dest_lat = steps['var_1']['arr']['lat']
        Dest_lng = steps['var_1']['arr']['lng']
        time_stamp = leg['_sent_time_stamp'] 
    if steps['travel_mode'] =="a_pied":
        query = ('SELECT leg_no FROM leg_data WHERE travel_mode = %s AND Orig_lat = %s AND Orig_lng = %s AND Dest_lat = %s AND Dest_lng = %s AND time_stamp = %s')
        travel_mode = steps['travel_mode']
        Orig_lat = steps['var_2']['lat']
        Orig_lng = steps['var_2']['lng']
        Dest_lat = steps['var_2']['lat']
        Dest_lng = steps['var_2']['lng']
        time_stamp = leg['_sent_time_stamp']
    cursor.execute(query,(travel_mode, Orig_lat, Orig_lng, Dest_lat, Dest_lng, time_stamp))
    leg_no = cursor.fetchone()[0]
    print(leg_no)

I have inserted higher level details and am now searching the database to associate this lower level information with its parent. The only way to find this unique value is to search via the origin and destination coordinates with the time_stamp. I believe the logic is sound and by printing the leg_no immediately after this section, I can see values which appear at first inspection to be correct

However, when added to the rest of the code, it causes subsequent sections where more data is inserted using the cursor to fail with this error -

    raise errors.InternalError("Unread result found.")
mysql.connector.errors.InternalError: Unread result found.

The issue seems similar to https://stackoverflow.com/questions/15336767/mysql-unread-result-with-python

Is the query too complex and needs splitting or is there another issue?

If the query is indeed too complex, can anyone advise how best to split this?

EDIT As per @Gord's help, Ive tried to dump any unread results

cursor.execute(query,(leg_travel_mode, leg_Orig_lat, leg_Orig_lng, leg_Dest_lat, leg_Dest_lng))
            leg_no = cursor.fetchone()[0]
            try:
                cursor.fetchall()
            except mysql.connector.errors.InterfaceError as ie:
                if ie.msg == 'No result set to fetch from.':
                    pass
                else:
                    raise
            cursor.execute(query,(leg_travel_mode, leg_Orig_lat, leg_Orig_lng, leg_Dest_lat, leg_Dest_lng, time_stamp))

But, I still get

raise errors.InternalError("Unread result found.")
mysql.connector.errors.InternalError: Unread result found.
[Finished in 3.3s with exit code 1]

scratches head

EDIT 2 - when I print the ie.msg, I get -

No result set to fetch from

Python Solutions


Solution 1 - Python

All that was required was for buffered to be set to true!

cursor = cnx.cursor(buffered=True)

The reason is that without a buffered cursor, the results are "lazily" loaded, meaning that "fetchone" actually only fetches one row from the full result set of the query. When you will use the same cursor again, it will complain that you still have n-1 results (where n is the result set amount) waiting to be fetched. However, when you use a buffered cursor the connector fetches ALL rows behind the scenes and you just take one from the connector so the mysql db won't complain.

Solution 2 - Python

I was able to recreate your issue. MySQL Connector/Python apparently doesn't like it if you retrieve multiple rows and don't fetch them all before closing the cursor or using it to retrieve some other stuff. For example

import mysql.connector
cnxn = mysql.connector.connect(
    host='127.0.0.1',
        user='root',
        password='whatever',
        database='mydb')
crsr = cnxn.cursor()
crsr.execute("DROP TABLE IF EXISTS pytest")
crsr.execute("""
CREATE TABLE pytest (
    id INT(11) NOT NULL AUTO_INCREMENT,
    firstname VARCHAR(20),
    PRIMARY KEY (id)
    )
""")
crsr.execute("INSERT INTO pytest (firstname) VALUES ('Gord')")
crsr.execute("INSERT INTO pytest (firstname) VALUES ('Anne')")
cnxn.commit()
crsr.execute("SELECT firstname FROM pytest")
fname = crsr.fetchone()[0]
print(fname)
crsr.execute("SELECT firstname FROM pytest")  # InternalError: Unread result found.

If you only expect (or care about) one row then you can put a LIMIT on your query

crsr.execute("SELECT firstname FROM pytest LIMIT 0, 1")
fname = crsr.fetchone()[0]
print(fname)
crsr.execute("SELECT firstname FROM pytest")  # OK now

or you can use fetchall() to get rid of any unread results after you have finished working with the rows you retrieved.

crsr.execute("SELECT firstname FROM pytest")
fname = crsr.fetchone()[0]
print(fname)
try:
    crsr.fetchall()  # fetch (and discard) remaining rows
except mysql.connector.errors.InterfaceError as ie:
    if ie.msg == 'No result set to fetch from.':
        # no problem, we were just at the end of the result set
        pass
    else:
        raise
crsr.execute("SELECT firstname FROM pytest")  # OK now

Solution 3 - Python

cursor.reset() is really what you want....

fetch_all() is not good because you may end up moving unnecessary data from the database to your client

Solution 4 - Python

If you want to get only one result from a request, and want after to reuse the same connexion for other requests, limit your sql select request to 1 using "limit 1" at the end of your request.

ex "Select field from table where x=1 limit 1;"

This method is faster using "buffered=True"

Solution 5 - Python

There is also a possibility that your connection to MySQL Workbench is disconnected. Establish the connection again. This solved the problem for me.

Solution 6 - Python

Would setting the cursor within the for loop, executing it, and then closing it again in the loop help? Like:

for steps in result['routes'][0]['legs'][0]['steps']:
    cursor = cnx.cursor()
    ....
    leg_no = cursor.fetchone()[0]
    cursor.close()
    print(leg_no)

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionLearningSlowlyView Question on Stackoverflow
Solution 1 - PythonLearningSlowlyView Answer on Stackoverflow
Solution 2 - PythonGord ThompsonView Answer on Stackoverflow
Solution 3 - PythonJames Wheeler PEView Answer on Stackoverflow
Solution 4 - PythonPatrice GView Answer on Stackoverflow
Solution 5 - PythonNattyView Answer on Stackoverflow
Solution 6 - PythonAbd_bgcView Answer on Stackoverflow