python JSON only get keys in first level
PythonJsonPython 2.7IteratorKeyPython Problem Overview
I have a very long and complicated json object but I only want to get the items/keys in the first level!
Example:
{
"1": "a",
"3": "b",
"8": {
"12": "c",
"25": "d"
}
}
I want to get 1,3,8 as result!
I found this code:
for key, value in data.iteritems():
print key, value
But it prints all keys (also 12 and 25)
Python Solutions
Solution 1 - Python
Just do a simple .keys()
>>> dct = {
... "1": "a",
... "3": "b",
... "8": {
... "12": "c",
... "25": "d"
... }
... }
>>>
>>> dct.keys()
['1', '8', '3']
>>> for key in dct.keys(): print key
...
1
8
3
>>>
If you need a sorted list:
keylist = dct.keys()
keylist.sort()
Solution 2 - Python
for key in data.keys():
print key
Solution 3 - Python
As Karthik mentioned, dct.keys() will work but it will return all the keys in dict_keys type not in list type. So if you want all the keys in a list, then list(dct.keys()) will work.
Solution 4 - Python
A good way to check whether a python object is an instance of a type is to use isinstance() which is Python's 'built-in' function.
For Python 3.6:
dct = {
"1": "a",
"3": "b",
"8": {
"12": "c",
"25": "d"
}
}
for key in dct.keys():
if isinstance(dct[key], dict)== False:
print(key, dct[key])
#shows:
# 1 a
# 3 b