Python csv string to array
PythonStringArraysCsvPython Problem Overview
Anyone know of a simple library or function to parse a csv encoded string and turn it into an array or dictionary?
I don't think I want the built in csv module because in all the examples I've seen that takes filepaths, not strings.
Python Solutions
Solution 1 - Python
You can convert a string to a file object using io.StringIO
and then pass that to the csv
module:
from io import StringIO
import csv
scsv = """text,with,Polish,non-Latin,letters
1,2,3,4,5,6
a,b,c,d,e,f
gęś,zółty,wąż,idzie,wąską,dróżką,
"""
f = StringIO(scsv)
reader = csv.reader(f, delimiter=',')
for row in reader:
print('\t'.join(row))
simpler version with split()
on newlines:
reader = csv.reader(scsv.split('\n'), delimiter=',')
for row in reader:
print('\t'.join(row))
Or you can simply split()
this string into lines using \n
as separator, and then split()
each line into values, but this way you must be aware of quoting, so using csv
module is preferred.
On Python 2 you have to import StringIO
as
from StringIO import StringIO
instead.
Solution 2 - Python
Simple - the csv module works with lists, too:
>>> a=["1,2,3","4,5,6"] # or a = "1,2,3\n4,5,6".split('\n')
>>> import csv
>>> x = csv.reader(a)
>>> list(x)
[['1', '2', '3'], ['4', '5', '6']]
Solution 3 - Python
The official doc for csv.reader()
https://docs.python.org/2/library/csv.html is very helpful, which says
> file objects and list objects are both suitable
import csv
text = """1,2,3
a,b,c
d,e,f"""
lines = text.splitlines()
reader = csv.reader(lines, delimiter=',')
for row in reader:
print('\t'.join(row))
Solution 4 - Python
> And while the module doesn’t directly support parsing strings, it can easily be done:
import csv
for row in csv.reader(['one,two,three']):
print row
Just turn your string into a single element list.
Importing StringIO seems a bit excessive to me when this example is explicitly in the docs.
Solution 5 - Python
As others have already pointed out, Python includes a module to read and write CSV files. It works pretty well as long as the input characters stay within ASCII limits. In case you want to process other encodings, more work is needed.
The [Python documentation for the csv module][1] implements an extension of csv.reader, which uses the same interface but can handle other encodings and returns unicode strings. Just copy and paste the code from the documentation. After that, you can process a CSV file like this:
with open("some.csv", "rb") as csvFile:
for row in UnicodeReader(csvFile, encoding="iso-8859-15"):
print row
[1]: http://docs.python.org/library/csv.html "CSV File Reading and Writing"
Solution 6 - Python
Not a generic CSV parser but usable for simple strings with commas.
>>> a = "1,2"
>>> a
'1,2'
>>> b = a.split(",")
>>> b
['1', '2']
To parse a CSV file:
f = open(file.csv, "r")
lines = f.read().split("\n") # "\r\n" if needed
for line in lines:
if line != "": # add other needed checks to skip titles
cols = line.split(",")
print cols
Solution 7 - Python
https://docs.python.org/2/library/csv.html?highlight=csv#csv.reader > csvfile can be any object which supports the iterator protocol and returns a string each time its next() method is called
Thus, a StringIO.StringIO()
, str.splitlines()
or even a generator are all good.
Solution 8 - Python
Use this to have a csv loaded into a list
import csv
csvfile = open(myfile, 'r')
reader = csv.reader(csvfile, delimiter='\t')
my_list = list(reader)
print my_list
>>>[['1st_line', '0'],
['2nd_line', '0']]
Solution 9 - Python
Here's an alternative solution:
>>> import pyexcel as pe
>>> text="""1,2,3
... a,b,c
... d,e,f"""
>>> s = pe.load_from_memory('csv', text)
>>> s
Sheet Name: csv
+---+---+---+
| 1 | 2 | 3 |
+---+---+---+
| a | b | c |
+---+---+---+
| d | e | f |
+---+---+---+
>>> s.to_array()
[[u'1', u'2', u'3'], [u'a', u'b', u'c'], [u'd', u'e', u'f']]
Here's the documentation