Python Convert Back Slashes to forward slashes

I am working in python and I need to convert this:

C:\folderA\folderB to C:/folderA/folderB

I have three approaches:

dir = s.replace('\\','/')

dir = os.path.normpath(s) 

dir = os.path.normcase(s)

In each scenario the output has been

C:folderAfolderB

I'm not sure what I am doing wrong, any suggestions?

I recently found this and thought worth sharing:

import os

path = "C:\\temp\myFolder\example\\"

newPath = path.replace(os.sep, '/')

print newPath


Output:<< C:/temp/myFolder/example/  >>

Your specific problem is the order and escaping of your replace arguments, should be

s.replace('\\', '/')

Then there's:

posixpath.join(*s.split('\\'))

Which on a *nix platform is equivalent to:

os.path.join(*s.split('\\'))

But don't rely on that on Windows because it will prefer the platform-specific separator. Also: > Note that on Windows, since there is a current directory for each > drive, os.path.join("c:", "foo") represents a path relative to the > current directory on drive C: (c:foo), not c:\foo.

Try

path = '/'.join(path.split('\\'))

Path names are formatted differently in Windows. the solution is simple, suppose you have a path string like this:

data_file = "/Users/username/Downloads/PMLSdata/series.csv"

simply you have to change it to this: (adding r front of the path)

data_file = r"/Users/username/Downloads/PMLSdata/series.csv"

The modifier r before the string tells Python that this is a raw string. In raw strings, the backslash is interpreted literally, not as an escape character.

To define the path's variable you have to add r initially, then add the replace statement .replace('\\', '/') at the end.

for example:

In>>  path2 = r'C:\Users\User\Documents\Project\Em2Lph\'.replace('\\', '/')
In>>  path2 
Out>> 'C:/Users/User/Documents/Project/Em2Lph/'

This solution requires no additional libraries

Sorry for being late to the party, but I wonder no one has suggested the pathlib-library.

pathlib is a module for "Object-oriented filesystem paths"

To convert from windows-style (backslash)-paths to forward-slashes (as typically for Posix-Paths) you can do so in a very verbose (AND platform-independant) fashion with pathlib:

import pathlib

pathlib.PureWindowsPath(r"C:\folderA\folderB").as_posix()
>>> 'C:/folderA/folderB'

Be aware that the example uses the string-literal "r" (to avoid having "\" as escape-char) In other cases the path should be quoted properly (with double backslashes) "C:\\folderA\\folderB"

How about :

import ntpath
import posixpath
.
.
.
dir = posixpath.join(*ntpath.split(s))
.
.

This can work also:

def slash_changer(directory):

if "\\" in directory:
    return directory.replace(os.sep, '/')
else:
    return directory

print(slash_changer(os.getcwd()))

this is the perfect solution put the letter 'r' before the string that you want to convert to avoid all special characters likes '\t' and '\f'... like the example below:

str= r"\test\hhd"

print("linux path:",str.replace("\\","\\\\"))
print("windows path:",str.replace("\\","/"))

result:

linux path: \\test\\hhd
windows path: /test/hhd