Programmatically obtain the phone number of the Android phone

How can I programmatically get the phone number of the device that is running my android app?

Code:

TelephonyManager tMgr = (TelephonyManager)mAppContext.getSystemService(Context.TELEPHONY_SERVICE);
String mPhoneNumber = tMgr.getLine1Number();

Required Permission:

<uses-permission android:name="android.permission.READ_PHONE_STATE"/> 

Caveats:

According to the highly upvoted comments, there are a few caveats to be aware of. This can return null or "" or even "???????", and it can return a stale phone number that is no longer valid. If you want something that uniquely identifies the device, you should use getDeviceId() instead.

There is no guaranteed solution to this problem because the phone number is not physically stored on all SIM-cards, or broadcasted from the network to the phone. This is especially true in some countries which requires physical address verification, with number assignment only happening afterwards. Phone number assignment happens on the network - and can be changed without changing the SIM card or device (e.g. this is how porting is supported).

I know it is pain, but most likely the best solution is just to ask the user to enter his/her phone number once and store it.

Update: This answer is no longer available as Whatsapp had stopped exposing the phone number as account name, kindly disregard this answer.

There is actually an alternative solution you might want to consider, if you can't get it through telephony service.

As of today, you can rely on another big application Whatsapp, using AccountManager. Millions of devices have this application installed and if you can't get the phone number via TelephonyManager, you may give this a shot.

Permission:

<uses-permission android:name="android.permission.GET_ACCOUNTS" />

Code:

AccountManager am = AccountManager.get(this);
Account[] accounts = am.getAccounts();

for (Account ac : accounts) {
    String acname = ac.name;
    String actype = ac.type;
    // Take your time to look at all available accounts
    System.out.println("Accounts : " + acname + ", " + actype);
}

Check actype for WhatsApp account

if(actype.equals("com.whatsapp")){
    String phoneNumber = ac.name;
}

Of course you may not get it if user did not install WhatsApp, but its worth to try anyway. And remember you should always ask user for confirmation.

So that's how you request a phone number through the Play Services API without the permission and hacks. Source and Full example.

In your build.gradle (version 10.2.x and higher required):

compile "com.google.android.gms:play-services-auth:$gms_version"

In your activity (the code is simplified):

@Override
protected void onCreate(Bundle savedInstanceState) {
    // ...
    googleApiClient = new GoogleApiClient.Builder(this)
            .addApi(Auth.CREDENTIALS_API)
            .build();
    requestPhoneNumber(result -> {
        phoneET.setText(result);
    });
}

public void requestPhoneNumber(SimpleCallback<String> callback) {
    phoneNumberCallback = callback;
    HintRequest hintRequest = new HintRequest.Builder()
            .setPhoneNumberIdentifierSupported(true)
            .build();

    PendingIntent intent = Auth.CredentialsApi.getHintPickerIntent(googleApiClient, hintRequest);
    try {
        startIntentSenderForResult(intent.getIntentSender(), PHONE_NUMBER_RC, null, 0, 0, 0);
    } catch (IntentSender.SendIntentException e) {
        Logs.e(TAG, "Could not start hint picker Intent", e);
    }
}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == PHONE_NUMBER_RC) {
        if (resultCode == RESULT_OK) {
            Credential cred = data.getParcelableExtra(Credential.EXTRA_KEY);
            if (phoneNumberCallback != null){
                phoneNumberCallback.onSuccess(cred.getId());
            }
        }
        phoneNumberCallback = null;
    }
}

This will generate a dialog like this:

As posted in my earlier answer

Use below code :

TelephonyManager tMgr = (TelephonyManager)mAppContext.getSystemService(Context.TELEPHONY_SERVICE);
String mPhoneNumber = tMgr.getLine1Number();

In AndroidManifest.xml, give the following permission:

 <uses-permission android:name="android.permission.READ_PHONE_STATE"/> 

But remember, this code does not always work, since Cell phone number is dependent on the SIM Card and the Network operator / Cell phone carrier.

Also, try checking in Phone--> Settings --> About --> Phone Identity, If you are able to view the Number there, the probability of getting the phone number from above code is higher. If you are not able to view the phone number in the settings, then you won't be able to get via this code!

Suggested Workaround:

1. Get the user's phone number as manual input from the user.
2. Send a code to the user's mobile number via SMS.
3. Ask user to enter the code to confirm the phone number.
4. Save the number in sharedpreference.

Do the above 4 steps as one time activity during the app's first launch. Later on, whenever phone number is required, use the value available in shared preference.

There is a new Android api that allows the user to select their phonenumber without the need for a permission. Take a look at: https://android-developers.googleblog.com/2017/10/effective-phone-number-verification.html

// Construct a request for phone numbers and show the picker
private void requestHint() {
    HintRequest hintRequest = new HintRequest.Builder()
       .setPhoneNumberIdentifierSupported(true)
       .build();

    PendingIntent intent = Auth.CredentialsApi.getHintPickerIntent(
        apiClient, hintRequest);
    startIntentSenderForResult(intent.getIntentSender(),
        RESOLVE_HINT, null, 0, 0, 0);
} 

private String getMyPhoneNumber(){
	TelephonyManager mTelephonyMgr;
	mTelephonyMgr = (TelephonyManager)
		getSystemService(Context.TELEPHONY_SERVICE); 
	return mTelephonyMgr.getLine1Number();
}

private String getMy10DigitPhoneNumber(){
	String s = getMyPhoneNumber();
	return s != null && s.length() > 2 ? s.substring(2) : null;
}

Code taken from http://www.androidsnippets.com/get-my-phone-number

Just want to add a bit here to above explanations in the above answers. Which will save time for others as well.

In my case this method didn't returned any mobile number, an empty string was returned. It was due to the case that I had ported my number on the new sim. So if I go into the Settings>About Phone>Status>My Phone Number it shows me "Unknown".

Sometimes, below code returns null or blank string.

TelephonyManager tMgr = (TelephonyManager)mAppContext.getSystemService(Context.TELEPHONY_SERVICE);
String mPhoneNumber = tMgr.getLine1Number();

With below permission

<uses-permission android:name="android.permission.READ_PHONE_STATE"/>

There is another way you will be able to get your phone number, I haven't tested this on multiple devices but above code is not working every time.

Try below code:

String main_data[] = {"data1", "is_primary", "data3", "data2", "data1", "is_primary", "photo_uri", "mimetype"};
Object object = getContentResolver().query(Uri.withAppendedPath(android.provider.ContactsContract.Profile.CONTENT_URI, "data"),
		main_data, "mimetype=?",
		new String[]{"vnd.android.cursor.item/phone_v2"},
		"is_primary DESC");
if (object != null) {
	do {
		if (!((Cursor) (object)).moveToNext())
			break;
        // This is the phoneNumber
		String s1 = ((Cursor) (object)).getString(4);
	} while (true);
	((Cursor) (object)).close();
}

You will need to add these two permissions.

<uses-permission android:name="android.permission.READ_CONTACTS" />
<uses-permission android:name="android.permission.READ_PROFILE" />

Hope this helps, Thanks!

First of all getting users mobile number is against the Ethical policy, earlier it was possible but now as per my research there no solid solution available for this, By using some code it is possible to get mobile number but no guarantee may be it will work only in few device. After lot of research i found only three solution but they are not working in all device.

There is the following reason why we are not getting.

1.Android device and new Sim Card not storing mobile number if mobile number is not available in device and in sim then how it is possible to get number, if any old sim card having mobile number then using Telephony manager we can get the number other wise it will return the “null” or “” or “??????”

<uses-permission android:name="android.permission.READ_PHONE_STATE"/>

 TelephonyManager tel= (TelephonyManager)this.getSystemService(Context.
            TELEPHONY_SERVICE);
    String PhoneNumber =  tel.getLine1Number();

> Note:- I have tested this solution in following device Moto x, Samsung Tab 4, Samsung S4, Nexus 5 and Redmi 2 prime but it doesn’t work every > time it return empty string so conclusion is it's useless

2. This method is working only in Redmi 2 prime, but for this need to add read contact permission in manifest.

> Note:- This is also not the guaranteed and efficient solution, I have tested this solution in many device but it worked only in Redmi 2 prime > which is dual sim device it gives me two mobile number first one is > correct but the second one is not belong to my second sim it belong to > my some old sim card which i am not using.

 String main_data[] = {"data1", "is_primary", "data3", "data2", "data1",
            "is_primary", "photo_uri", "mimetype"};
    Object object = getContentResolver().
            query(Uri.withAppendedPath(android.provider.ContactsContract.Profile.CONTENT_URI, "data"),
            main_data, "mimetype=?",
            new String[]{"vnd.android.cursor.item/phone_v2"},
            "is_primary DESC");
    String s1="";
    if (object != null) {
        do {
            if (!((Cursor) (object)).moveToNext())
                break;
            // This is the phoneNumber
             s1 =s1+"---"+ ((Cursor) (object)).getString(4);
        } while (true);
        ((Cursor) (object)).close();
    }

3. In my research i have found earlier it was possible to get mobile number using WhatsApp account but now new Whatsapp version doesn’t storing user's mobile number.

> Conclusion:- Android doesn’t have any guaranteed solution to get > user's mobile number programmatically. > > Suggestion:- 1. If you want to verify user’s mobile number then ask to > user to provide his number, using otp you can can verify that. > > 2. If you want to identify the user’s device, for this you can easily get device IMEI number.

This is a more simplified answer:

public String getMyPhoneNumber()
{
	return ((TelephonyManager) getSystemService(TELEPHONY_SERVICE))
			.getLine1Number();
}

TelephonyManager is not the right solution, because in some cases the number is not stored in the SIM. I suggest that you should use the shared preference to store the user's phone number for the first time the application is open and the number will used whenever you need.

Here's a combination of the solutions I've found (sample project here, if you want to also check auto-fill):

manifest

    <uses-permission android:name="android.permission.READ_PHONE_STATE" />

build.gradle

    implementation "com.google.android.gms:play-services-auth:17.0.0"

MainActivity.kt

class MainActivity : AppCompatActivity() {
    private lateinit var googleApiClient: GoogleApiClient

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.activity_main)
        tryGetCurrentUserPhoneNumber(this)
        googleApiClient = GoogleApiClient.Builder(this).addApi(Auth.CREDENTIALS_API).build()
        if (phoneNumber.isEmpty()) {
            val hintRequest = HintRequest.Builder().setPhoneNumberIdentifierSupported(true).build()
            val intent = Auth.CredentialsApi.getHintPickerIntent(googleApiClient, hintRequest)
            try {
                startIntentSenderForResult(intent.intentSender, REQUEST_PHONE_NUMBER, null, 0, 0, 0);
            } catch (e: IntentSender.SendIntentException) {
                Toast.makeText(this, "failed to show phone picker", Toast.LENGTH_SHORT).show()
            }
        } else
            onGotPhoneNumberToSendTo()

    }

    override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
        super.onActivityResult(requestCode, resultCode, data)
        if (requestCode == REQUEST_PHONE_NUMBER) {
            if (resultCode == Activity.RESULT_OK) {
                val cred: Credential? = data?.getParcelableExtra(Credential.EXTRA_KEY)
                phoneNumber = cred?.id ?: ""
                if (phoneNumber.isEmpty())
                    Toast.makeText(this, "failed to get phone number", Toast.LENGTH_SHORT).show()
                else
                    onGotPhoneNumberToSendTo()
            }
        }
    }

    private fun onGotPhoneNumberToSendTo() {
        Toast.makeText(this, "got number:$phoneNumber", Toast.LENGTH_SHORT).show()
    }


    companion object {
        private const val REQUEST_PHONE_NUMBER = 1
        private var phoneNumber = ""

        @SuppressLint("MissingPermission", "HardwareIds")
        private fun tryGetCurrentUserPhoneNumber(context: Context): String {
            if (phoneNumber.isNotEmpty())
                return phoneNumber
            if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
                val subscriptionManager = context.getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE) as SubscriptionManager
                try {
                    subscriptionManager.activeSubscriptionInfoList?.forEach {
                        val number: String? = it.number
                        if (!number.isNullOrBlank()) {
                            phoneNumber = number
                            return number
                        }
                    }
                } catch (ignored: Exception) {
                }
            }
            try {
                val telephonyManager = context.getSystemService(Context.TELEPHONY_SERVICE) as TelephonyManager
                val number = telephonyManager.line1Number ?: ""
                if (!number.isBlank()) {
                    phoneNumber = number
                    return number
                }
            } catch (e: Exception) {
            }
            return ""
        }
    }
}

Add this dependency: implementation 'com.google.android.gms:play-services-auth:18.0.0'

To fetch phone number list use this:

val hintRequest = HintRequest.Builder()
    .setPhoneNumberIdentifierSupported(true)
    .build()

val intent = Credentials.getClient(context).getHintPickerIntent(hintRequest)

startIntentSenderForResult(
    intent.intentSender,
    PHONE_NUMBER_FETCH_REQUEST_CODE,
    null,
    0,
    0,
    0,
    null
)

After tap on play services dialog:

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent? { 
    super.onActivityResult(requestCode, resultCode, data)

    if (requestCode == PHONE_NUMBER_FETCH_REQUEST_CODE) {
        data?.getParcelableExtra<Credential>(Credential.EXTRA_KEY)?.id?.let { 
            useFetchedPhoneNumber(it)
        }
    }
}

A little contribution. In my case, the code launched an error exception. I have needed put an annotation that for the code be run and fix that problem. Here I let this code.

public static String getLineNumberPhone(Context scenario) {
    TelephonyManager tMgr = (TelephonyManager) scenario.getSystemService(Context.TELEPHONY_SERVICE);
    @SuppressLint("MissingPermission") String mPhoneNumber = tMgr.getLine1Number();
    return mPhoneNumber;
}

For android version >= LOLLIPOP_MR1 :

Add permission :

And call this :

 val subscriptionManager =
        getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE) as SubscriptionManager
    
if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
        
val list = subscriptionManager.activeSubscriptionInfoList
        for (info in list) {
            Log.d(TAG, "number " + info.number)
            Log.d(TAG, "network name : " + info.carrierName)
            Log.d(TAG, "country iso " + info.countryIso)
        }
    }

I noticed several answers posting the same thing. First of all things changed as per 2021, onActivityResult is deprecated. Here is the non-deprecated solution.

private fun requestHint() {

    val hintRequest = HintRequest.Builder()
        .setPhoneNumberIdentifierSupported(true)
        .build()

    val intent = Credentials.getClient(this).getHintPickerIntent(hintRequest)
    val intentSender = IntentSenderRequest.Builder(intent.intentSender).build()

    val resultLauncher = registerForActivityResult(
        ActivityResultContracts.StartIntentSenderForResult()
    ) { result ->
        if (result.resultCode == Activity.RESULT_OK) {
            val credential: Credential? = result.data?.getParcelableExtra(Credential.EXTRA_KEY)
            // Phone number with country code
            Log.i("mTag", "Selected phone No: ${credential?.id}")
        }
    }
    resultLauncher.launch(intentSender)
}

Note: While many of you think this allows you to retrieve user's mobile phone number. That is usually not the case. Google Play Services has cached few phone numbers and sometimes the dialog shows phone numbers in which none belongs to user.

An important import com.google.android.gms.auth.api.credentials.Credential

Reference Documentation provides details but the code is somewhat deprecated.

Although it's possible to have multiple voicemail accounts, when calling from your own number, carriers route you to voicemail. So, TelephonyManager.getVoiceMailNumber() or TelephonyManager.getCompleteVoiceMailNumber(), depending on the flavor you need.

Hope this helps.

Wouldn't be recommending to use TelephonyManager as it requires the app to require READ_PHONE_STATE permission during runtime.

<uses-permission android:name="android.permission.READ_PHONE_STATE"/> 

Should be using Google's Play Service for Authentication, and it will able to allow User to select which phoneNumber to use, and handles multiple SIM cards, rather than us trying to guess which one is the primary SIM Card.

implementation "com.google.android.gms:play-services-auth:$play_service_auth_version"

fun main() {
    val googleApiClient = GoogleApiClient.Builder(context)
        .addApi(Auth.CREDENTIALS_API).build()

    val hintRequest = HintRequest.Builder()
        .setPhoneNumberIdentifierSupported(true)
        .build()

    val hintPickerIntent = Auth.CredentialsApi.getHintPickerIntent(
        googleApiClient, hintRequest
    )

    startIntentSenderForResult(
        hintPickerIntent.intentSender, REQUEST_PHONE_NUMBER, null, 0, 0, 0
    )
}

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    super.onActivityResult(requestCode, resultCode, data)
    when (requestCode) {
        REQUEST_PHONE_NUMBER -> {
            if (requestCode == Activity.RESULT_OK) {
                val credential = data?.getParcelableExtra<Credential>(Credential.EXTRA_KEY)
                val selectedPhoneNumber = credential?.id
            }
        }
    }
}

while working on a security app which needed to get the phone number of who so ever my phone might get into their hands, I had to do this;

1. receive Boot completed and then try getting Line1_Number from telephonyManager which returns a string result.
2. compare the String result with my own phone number and if they don't match or string returns null then,
3. secretly send an SMS containing the string result plus a special sign to my office number.
4. if message sending fails, start a service and keep trying after each hour until sent SMS pending intent returns successful. With this steps I could get the number of the person using my lost phone. it doesn't matter if the person is charged.