Print multiple arguments in Python

This is just a snippet of my code:

print("Total score for %s is %s  ", name, score)

But I want it to print out:

> "Total score for (name) is (score)"

where name is a variable in a list and score is an integer. This is Python 3.3 if that helps at all.

There are many ways to do this. To fix your current code using %-formatting, you need to pass in a tuple:

1. Pass it as a tuple:

    print("Total score for %s is %s" % (name, score))
   

A tuple with a single element looks like ('this',).

Here are some other common ways of doing it:

2. Pass it as a dictionary:

    print("Total score for %(n)s is %(s)s" % {'n': name, 's': score})
   

There's also new-style string formatting, which might be a little easier to read:

3. Use new-style string formatting:

    print("Total score for {} is {}".format(name, score))
   

4. Use new-style string formatting with numbers (useful for reordering or printing the same one multiple times):

    print("Total score for {0} is {1}".format(name, score))
   

5. Use new-style string formatting with explicit names:

    print("Total score for {n} is {s}".format(n=name, s=score))
   

6. Concatenate strings:

    print("Total score for " + str(name) + " is " + str(score))
   

The clearest two, in my opinion:

7. Just pass the values as parameters:

    print("Total score for", name, "is", score)
   

   If you don't want spaces to be inserted automatically by print in the above example, change the sep parameter:

    print("Total score for ", name, " is ", score, sep='')
   

   If you're using Python 2, won't be able to use the last two because print isn't a function in Python 2. You can, however, import this behavior from __future__:

    from __future__ import print_function
   

8. Use the new f-string formatting in Python 3.6:

    print(f'Total score for {name} is {score}')
   

There are many ways to print that.

Let's have a look with another example.

a = 10
b = 20
c = a + b

#Normal string concatenation
print("sum of", a , "and" , b , "is" , c) 

#convert variable into str
print("sum of " + str(a) + " and " + str(b) + " is " + str(c)) 

# if you want to print in tuple way
print("Sum of %s and %s is %s: " %(a,b,c))  

#New style string formatting
print("sum of {} and {} is {}".format(a,b,c)) 

#in case you want to use repr()
print("sum of " + repr(a) + " and " + repr(b) + " is " + repr(c))

EDIT :

#New f-string formatting from Python 3.6:
print(f'Sum of {a} and {b} is {c}')

 

Use: .format():

print("Total score for {0} is {1}".format(name, score))

Or:

// Recommended, more readable code

print("Total score for {n} is {s}".format(n=name, s=score))

Or:

print("Total score for" + name + " is " + score)

Or:

print("Total score for %s is %d" % (name, score))

Or: f-string formatting from Python 3.6:

print(f'Total score for {name} is {score}')

Can use repr and automatically the '' is added:

print("Total score for" + repr(name) + " is " + repr(score))

# or for advanced: 
print(f'Total score for {name!r} is {score!r}') 

In Python 3.6, f-string is much cleaner.

In earlier version:

print("Total score for %s is %s. " % (name, score))

In Python 3.6:

print(f'Total score for {name} is {score}.')

will do.

It is more efficient and elegant.

Keeping it simple, I personally like string concatenation:

print("Total score for " + name + " is " + score)

It works with both Python 2.7 an 3.X.

NOTE: If score is an int, then, you should convert it to str:

print("Total score for " + name + " is " + str(score))

Just follow this

grade = "the biggest idiot"
year = 22
print("I have been {} for {} years.".format(grade, year))

OR

grade = "the biggest idiot"
year = 22
print("I have been %s for %s years." % (grade, year))

And forget all others, else the brain won't be able to map all the formats.

Just try:

print("Total score for", name, "is", score)

Use f-string:

print(f'Total score for {name} is {score}')

Or

Use .format:

print("Total score for {} is {}".format(name, score))

print("Total score for %s is %s  " % (name, score))

%s can be replace by %d or %f

If score is a number, then

print("Total score for %s is %d" % (name, score))

If score is a string, then

print("Total score for %s is %s" % (name, score))

If score is a number, then it's %d, if it's a string, then it's %s, if score is a float, then it's %f

This is what I do:

print("Total score for " + name + " is " + score)

Remember to put a space after for and before and after is.

The easiest way is as follows

print(f"Total score for {name} is {score}")

Just put an "f" in front.

This was probably a casting issue. Casting syntax happens when you try to combine two different types of variables. Since we cannot convert a string to an integer or float always, we have to convert our integers into a string. This is how you do it.: str(x). To convert to a integer, it's: int(x), and a float is float(x). Our code will be:

print('Total score for ' + str(name) + ' is ' + str(score))

Also! Run this snippet to see a table of how to convert different types of variables!

<table style="border-collapse: collapse; width: 100%;background-color:maroon; color: #00b2b2;">
<tbody>
<tr>
<td style="width: 50%;font-family: serif; padding: 3px;">Booleans</td>
<td style="width: 50%;font-family: serif; padding: 3px;"><code>bool()</code></td>
  </tr>
 <tr>
<td style="width: 50%;font-family: serif;padding: 3px">Dictionaries</td>
<td style="width: 50%;font-family: serif;padding: 3px"><code>dict()</code></td>
</tr>
<tr>
<td style="width: 50%;font-family: serif;padding: 3px">Floats</td>
<td style="width: 50%;font-family: serif;padding: 3px"><code>float()</code></td>
</tr>
<tr>
<td style="width: 50%;font-family: serif;padding:3px">Integers</td>
<td style="width: 50%;font-family: serif;padding:3px;"><code>int()</code></td>
</tr>
<tr>
<td style="width: 50%;font-family: serif;padding: 3px">Lists</td>
<td style="width: 50%font-family: serif;padding: 3px;"><code>list()</code></td>
</tr>
</tbody>
</table>