Possible Loss of Fraction
C#MathC# Problem Overview
Forgive me if this is a naïve question, however I am at a loss today.
I have a simple division calculation such as follows:
double returnValue = (myObject.Value / 10);
Value is an int in the object.
I am getting a message that says Possible Loss of Fraction. However, when I change the double to an int, the message goes away.
Any thoughts on why this would happen?
C# Solutions
Solution 1 - C#
When you divide two int's into a floating point value the fraction portion is lost. If you cast one of the items to a float, you won't get this error.
So for example turn 10 into a 10.0
double returnValue = (myObject.Value / 10.0);
Solution 2 - C#
You're doing integer division if myObject.Value
is an int, since both sides of the /
are of integer type.
To do floating-point division, one of the numbers in the expression must be of floating-point type. That would be true if myObject.Value were a double, or any of the following:
double returnValue = myObject.Value / 10.0;
double returnValue = myObject.Value / 10d; //"d" is the double suffix
double returnValue = (double)myObject.Value / 10;
double returnValue = myObject.Value / (double)10;
Solution 3 - C#
An integer divided by an integer will return your an integer. Cast either Value to a double or divide by 10.0.
Solution 4 - C#
Assuming that myObject.Value
is an int
, the equation myObject.Value / 10
will be an integer division which will then be cast to a double.
That means that myObject.Value being 12 will result in returnValue becoming 1, not 1.2.
You need to cast the value(s) first:
double returnValue = (double)(myObject.Value) / 10.0;
This would result in the correct value 1.2, at least as correct as doubles will allow given their limitations but that's discussed elsewhere on SO, almost endlessly :-).
Solution 5 - C#
I think since myObject is an int, you should
double returnValue=(myObject.Value/10.0);