Passing second argument onwards from a shell script to Java

Bash

Bash Problem Overview

If I pass any number of arguments to a shell script that invokes a Java program internally, how can I pass second argument onwards to the Java program except the first?

./my_script.sh a b c d ....

#my_script.sh
...
java MyApp b c d ...

Bash Solutions

Solution 1 - Bash

First use shift to "consume" the first argument, then pass "$@", i.e., the list of remaining arguments:

#my_script.sh
...
shift
java MyApp "$@"

Solution 2 - Bash

You can pass second argument onwards without using "shift" as well.

set -- 1 2 3 4 5

echo "${@:0}"
echo "${@:1}"
echo "${@:2}"   # here
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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questioncm_cView Question on Stackoverflow
Solution 1 - BashBoloView Answer on Stackoverflow
Solution 2 - BashbashfuView Answer on Stackoverflow