Pass Additional ViewData to a Strongly-Typed Partial View

C#asp.netasp.net Mvcasp.net Mvc-PartialviewViewdata

C# Problem Overview


I have a strongly-typed Partial View that takes a ProductImage and when it is rendered I would also like to provide it with some additional ViewData which I create dynamically in the containing page. How can I pass both my strongly typed object and my custom ViewData to the partial view with the RenderPartial call?

var index = 0;
foreach (var image in Model.Images.OrderBy(p => p.Order))
{
  Html.RenderPartial("ProductImageForm", image); // < Pass 'index' to partial
  index++;
}

C# Solutions


Solution 1 - C#

RenderPartial takes another parameter that is simply a ViewDataDictionary. You're almost there, just call it like this:

Html.RenderPartial(
      "ProductImageForm", 
       image, 
       new ViewDataDictionary { { "index", index } }
); 

Note that this will override the default ViewData that all your other Views have by default. If you are adding anything to ViewData, it will not be in this new dictionary that you're passing to your partial view.

Solution 2 - C#

To extend on what womp posted, you can pass new View Data while retaining the existing View Data if you use the constructor overload of the ViewDataDictionary like so:

Html.RenderPartial(
      "ProductImageForm", 
       image, 
       new ViewDataDictionary(this.ViewData) { { "index", index } }
); 

Solution 3 - C#

@Html.Partial("_Header", new ViewDataDictionary { { "HeaderName", "User Management" }, { "TitleName", "List Of Users" } })
or
@{Html.RenderPartial("_Header", new ViewDataDictionary { { "HeaderName", "User Management" }, { "TitleName", "List Of Users" } });}

Partial Page(_Header):

<div class="row titleBlock">
    <h1>@ViewData["HeaderName"].ToString()</h1>
    <h5>@ViewData["TitleName"].ToString()</h5>
</div>

Solution 4 - C#

I think this should work no?

ViewData["currentIndex"] = index;

Solution 5 - C#

Create another class which contains your strongly typed class.

Add your new stuff to the class and return it in the view.

Then in the view, ensure you inherit your new class and change the bits of code that will now be in error. namely the references to your fields.

Hope this helps. If not then let me know and I'll post specific code.

Solution 6 - C#

I know this is an old post but I came across it when faced with a similar issue using core 3.0, hope it helps someone.

@{
Layout = null;
ViewData["SampleString"] = "some string need in the partial";
}

<partial name="_Partial" for="PartialViewModel" view-data="ViewData" />

Solution 7 - C#

The easiest way to pass additional data is to add the data to the existing ViewData for the view as @Joel Martinez notes. However, if you don't want to pollute your ViewData, RenderPartial has a method that takes three arguments as well as the two-argument version you show. The third argument is a ViewDataDictionary. You can construct a separate ViewDataDictionary just for your partial containing just the extra data that you want to pass in.

Solution 8 - C#

This should also work.

this.ViewData.Add("index", index);

Html.RenderPartial(
      "ProductImageForm", 
       image, 
       this.ViewData
); 

Solution 9 - C#

You can use the dynamic variable ViewBag

ViewBag.AnotherValue = valueToView;

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionNathan TaylorView Question on Stackoverflow
Solution 1 - C#wompView Answer on Stackoverflow
Solution 2 - C#ctorxView Answer on Stackoverflow
Solution 3 - C#muthuvelView Answer on Stackoverflow
Solution 4 - C#Joel MartinezView Answer on Stackoverflow
Solution 5 - C#griegsView Answer on Stackoverflow
Solution 6 - C#DrytinView Answer on Stackoverflow
Solution 7 - C#tvanfossonView Answer on Stackoverflow
Solution 8 - C#MithunChopdaView Answer on Stackoverflow
Solution 9 - C#Jack1987View Answer on Stackoverflow