Pandas: sum up multiple columns into one column without last column

PythonPandasSum

Python Problem Overview


If I have a dataframe similar to this one

Apples   Bananas   Grapes   Kiwis
2        3         nan      1
1        3         7        nan
nan      nan       2        3

I would like to add a column like this

Apples   Bananas   Grapes   Kiwis   Fruit Total
2        3         nan      1        6
1        3         7        nan      11
nan      nan       2        3        5

I guess you could use df['Apples'] + df['Bananas'] and so on, but my actual dataframe is much larger than this. I was hoping a formula like df['Fruit Total']=df[-4:-1].sum could do the trick in one line of code. That didn't work however. Is there any way to do it without explicitly summing up all columns?

Python Solutions


Solution 1 - Python

You can first select by iloc and then sum:

df['Fruit Total']= df.iloc[:, -4:-1].sum(axis=1)
print (df)
   Apples  Bananas  Grapes  Kiwis  Fruit Total
0     2.0      3.0     NaN    1.0          5.0
1     1.0      3.0     7.0    NaN         11.0
2     NaN      NaN     2.0    3.0          2.0

For sum all columns use:

df['Fruit Total']= df.sum(axis=1)

Solution 2 - Python

This may be helpful for beginners, so for the sake of completeness, if you know the column names (e.g. they are in a list), you can use:

column_names = ['Apples', 'Bananas', 'Grapes', 'Kiwis']
df['Fruit Total']= df[column_names].sum(axis=1)

This gives you flexibility about which columns you use as you simply have to manipulate the list column_names and you can do things like pick only columns with the letter 'a' in their name. Another benefit of this is that it's easier for humans to understand what they are doing through column names. Combine this with list(df.columns) to get the column names in a list format. Thus, if you want to drop the last column, all you have to do is:

column_names = list(df.columns)
df['Fruit Total']= df[column_names[:-1]].sum(axis=1)

Solution 3 - Python

It is possible to do it without knowing the number of columns and even without iloc:

print(df)
   Apples  Bananas  Grapes  Kiwis
0     2.0      3.0     NaN    1.0
1     1.0      3.0     7.0    NaN
2     NaN      NaN     2.0    3.0

cols_to_sum = df.columns[ : df.shape[1]-1]

df['Fruit Total'] = df[cols_to_sum].sum(axis=1)

print(df)
   Apples	Bananas	Grapes	Kiwis	Fruit Total
0  2.0	    3.0	    NaN	    1.0	    5.0
1  1.0	    3.0	    7.0	    NaN	    11.0
2  NaN	    NaN	    2.0	    3.0	    5.0

Solution 4 - Python

Using df['Fruit Total']= df.iloc[:, -4:-1].sum(axis=1) over your original df won't add the last column ('Kiwis'), you should use df.iloc[:, -4:] instead to select all columns:

print(df)
   Apples  Bananas  Grapes  Kiwis
0     2.0      3.0     NaN    1.0
1     1.0      3.0     7.0    NaN
2     NaN      NaN     2.0    3.0

df['Fruit Total']=df.iloc[:,-4:].sum(axis=1)

print(df)
   Apples  Bananas  Grapes  Kiwis  Fruit Total
0     2.0      3.0     NaN    1.0          6.0
1     1.0      3.0     7.0    NaN         11.0
2     NaN      NaN     2.0    3.0          5.0

Solution 5 - Python

I want to build on Ramon's answer if you want to come up with the total without knowing the shape/size of the dataframe. I will use his answer below but fix one item that didn't include the last column for the total. I have removed the -1 from the shape:

cols_to_sum = df.columns[ : df.shape[1]-1]

To this:

cols_to_sum = df.columns[ : df.shape[1]]
print(df)
   Apples  Bananas  Grapes  Kiwis
0     2.0      3.0     NaN    1.0
1     1.0      3.0     7.0    NaN
2     NaN      NaN     2.0    3.0

cols_to_sum = df.columns[ : df.shape[1]]

df['Fruit Total'] = df[cols_to_sum].sum(axis=1)

print(df)
   Apples   Bananas Grapes  Kiwis   Fruit Total
0  2.0      3.0     NaN     1.0     6.0
1  1.0      3.0     7.0     NaN     11.0
2  NaN      NaN     2.0     3.0     5.0

Which then gives you the correct total without skipping the last column.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionTuutsrednasView Question on Stackoverflow
Solution 1 - PythonjezraelView Answer on Stackoverflow
Solution 2 - PythonkelkkaView Answer on Stackoverflow
Solution 3 - PythonRamonView Answer on Stackoverflow
Solution 4 - PythonFrancisco DuraView Answer on Stackoverflow
Solution 5 - PythonJLKView Answer on Stackoverflow