os.path.dirname(__file__) returns empty
PythonPython Problem Overview
I want to get the path of the current directory under which a .py file is executed.
For example a simple file D:\test.py with code:
import os
print os.getcwd()
print os.path.basename(__file__)
print os.path.abspath(__file__)
print os.path.dirname(__file__)
It is weird that the output is:
D:\
test.py
D:\test.py
EMPTY
I am expecting the same results from the getcwd() and path.dirname().
Given os.path.abspath = os.path.dirname + os.path.basename, why
os.path.dirname(__file__)
returns empty?
Python Solutions
Solution 1 - Python
Because os.path.abspath = os.path.dirname + os.path.basename does not hold. we rather have
os.path.dirname(filename) + os.path.basename(filename) == filename
Both dirname() and basename() only split the passed filename into components without taking into account the current directory. If you want to also consider the current directory, you have to do so explicitly.
To get the dirname of the absolute path, use
os.path.dirname(os.path.abspath(__file__))
Solution 2 - Python
import os.path
dirname = os.path.dirname(__file__) or '.'
Solution 3 - Python
can be used also like that:
dirname(dirname(abspath(__file__)))
Solution 4 - Python
os.path.split(os.path.realpath(__file__))[0]
os.path.realpath(__file__) return the abspath of the current script; os.path.split(abspath)[0] return the current dir
Solution 5 - Python
print(os.path.join(os.path.dirname(__file__)))
You can also use this way
Solution 6 - Python
Since Python 3.4, you can use pathlib to get the current directory:
from pathlib import Path
# get parent directory
curr_dir = Path(__file__).parent
file_path = curr_dir.joinpath('otherfile.txt')
Solution 7 - Python
I guess this is a straight forward code without the os module..
__file__.split(__file__.split("/")[-1])[0]