OpenCV & Python - Image too big to display

I have an image that is 6400 × 3200, while my screen is 1280 x 800. Therefore, the image needs to be resized for display only. I am using Python and OpenCV 2.4.9. According to [OpenCV Documentation][1],

> If you need to show an image that is bigger than the screen resolution, you will need to call namedWindow("", WINDOW_NORMAL) before the imshow.

That is what I am doing, but the image is not fitted to the screen, only a portion is shown because it's too big. I've also tried with cv2.resizeWindow, but it doesn't make any difference.

import cv2
cv2.namedWindow("output", cv2.WINDOW_NORMAL)        # Create window with freedom of dimensions
# cv2.resizeWindow("output", 400, 300)              # Resize window to specified dimensions
im = cv2.imread("earth.jpg")                        # Read image
cv2.imshow("output", im)                            # Show image
cv2.waitKey(0)                                      # Display the image infinitely until any keypress

[1]: http://docs.opencv.org/2.4/modules/highgui/doc/user_interface.html "OpenCV Documentation"

Although I was expecting an automatic solution (fitting to the screen automatically), resizing solves the problem as well.

import cv2
cv2.namedWindow("output", cv2.WINDOW_NORMAL)    # Create window with freedom of dimensions
im = cv2.imread("earth.jpg")                    # Read image
imS = cv2.resize(im, (960, 540))                # Resize image
cv2.imshow("output", imS)                       # Show image
cv2.waitKey(0)                                  # Display the image infinitely until any keypress

The other answers perform a fixed (width, height) resize. If you wanted to resize to a specific size while maintaining aspect ratio, use this

def ResizeWithAspectRatio(image, width=None, height=None, inter=cv2.INTER_AREA):
    dim = None
    (h, w) = image.shape[:2]

    if width is None and height is None:
        return image
    if width is None:
        r = height / float(h)
        dim = (int(w * r), height)
    else:
        r = width / float(w)
        dim = (width, int(h * r))

    return cv2.resize(image, dim, interpolation=inter)

Example

image = cv2.imread('img.png')
resize = ResizeWithAspectRatio(image, width=1280) # Resize by width OR
# resize = ResizeWithAspectRatio(image, height=1280) # Resize by height 

cv2.imshow('resize', resize)
cv2.waitKey()

Use this for example:

cv2.namedWindow('finalImg', cv2.WINDOW_NORMAL)
cv2.imshow("finalImg",finalImg)

In OpenCV, cv2.namedWindow() just creates a window object, but doesn't resize the original image. You can use cv2.resize(img, resolution) to solve the problem.

Here's what it displays, a 740 * 411 resolution image.

image = cv2.imread("740*411.jpg")
cv2.imshow("image", image)
cv2.waitKey(0)
cv2.destroyAllWindows()

Here, it displays a 100 * 200 resolution image after resizing. Remember the resolution parameter use column first then is row.

image = cv2.imread("740*411.jpg")
image = cv2.resize(image, (200, 100))
cv2.imshow("image", image)
cv2.waitKey(0)
cv2.destroyAllWindows()

The only way resizeWindow worked for me was to have it after imshow. This is the order I'm using:

# Create a Named Window
cv2.namedWindow(win_name, cv2.WINDOW_NORMAL)

# Move it to (X,Y)
cv2.moveWindow(win_name, X, Y)
    
# Show the Image in the Window
cv2.imshow(win_name, image)
    
# Resize the Window
cv2.resizeWindow(win_name, width, height)
    
# Wait for <> miliseconds
cv2.waitKey(wait_time)

Try this:

image = cv2.imread("img/Demo.jpg")
image = cv2.resize(image,(240,240))

The image is now resized. Displaying it will render in 240x240.

This code will resize the image so that it can retain it's aspect ratio and only ever take up a specified fraction of the screen area.

It will automatically adjust depending on your screen size and the size of the image.

Use the area variable to change the max screen area you want the image to be able to take up. The example shows it displayed at quarter the screen size.

import cv2
import tkinter as tk
from math import *

img = cv2.imread("test.jpg")
area = 0.25

h, w = img.shape[:2]
root = tk.Tk()
screen_h = root.winfo_screenheight()
screen_w = root.winfo_screenwidth()
vector = sqrt(area)
window_h = screen_h * vector
window_w = screen_w * vector

if h > window_h or w > window_w:
    if h / window_h >= w / window_w:
        multiplier = window_h / h
    else:
        multiplier = window_w / w
    img = cv2.resize(img, (0, 0), fx=multiplier, fy=multiplier)

cv2.imshow("output", img)
cv2.waitKey(0)

I've also made a similar function where area is still a parameter but so is window height and window width.

If no area is input then it will use a defined height and width (window_h, window_w) of the window size you would like the image to fit inside.

If an input is given for all parameters then 'area' is prioritised.

import cv2
import tkinter as tk
from math import *

def resize_image(img, area=0.0, window_h=0, window_w=0):
    h, w = img.shape[:2]
    root = tk.Tk()
    screen_h = root.winfo_screenheight()
    screen_w = root.winfo_screenwidth()

    if area != 0.0:
        vector = math.sqrt(area)
        window_h = screen_h * vector
        window_w = screen_w * vector

    if h > window_h or w > window_w:
        if h / window_h >= w / window_w:
            multiplier = window_h / h
        else:
            multiplier = window_w / w
        img = cv2.resize(img, (0, 0), fx=multiplier, fy=multiplier)

    return img

# using area
initial_image = cv2.imread("test.jpg")
resized_image = resize_image(initial_image, area=0.25))
cv2.imshow("output", resized_image)
cv2.waitKey(0)

# using window height and width
initial_image = cv2.imread("test.jpg")
resized_image = resize_image(initial_image, window_h = 480, window_w = 270))
cv2.imshow("output", resized_image)
cv2.waitKey(0)

Looks like opencv lib is pretty sensitive to parameters passed to the methods. The following code worked for me using opencv 4.3.0:

win_name = "visualization"  #  1. use var to specify window name everywhere
cv2.namedWindow(win_name, cv2.WINDOW_NORMAL)  #  2. use 'normal' flag
img = cv2.imread(filename)
h,w = img.shape[:2]  #  suits for image containing any amount of channels
h = int(h / resize_factor)  #  one must compute beforehand
w = int(w / resize_factor)  #  and convert to INT
cv2.resizeWindow(win_name, w, h)  #  use variables defined/computed BEFOREHAND
cv2.imshow(win_name, img)

Try this code:

img = cv2.imread("Fab2_0.1 X 1.03MM GRID.jpg", cv2.IMREAD_GRAYSCALE)
image_scale_down = 3
x = (int)(img.shape[0]/image_scale_down)
y = (int)(img.shape[1]/image_scale_down)
image = cv2.resize(img, (x,y))
cv2.imshow("image_title", image)
cv2.waitKey(5000)
cv2.destroyAllWindows()

The cv2.WINDOW_NORMAL option works correctly but the first time it displays the window in an standard size.

If you resize the window like any other windows in your computer, by position the mouse over the edge of the window you want to resize and then drag the mouse to the position you want. If you do this to both width and height of the window to the size you want to obtain.

The following times you refresh the window, by executing the code, OpenCV will generate the window with the size of the last time it was shown or modified.

The most upvote answer is perfect ! I just add my code for those who want some "dynamic" resize handling depending of the ratio.

import cv2
from win32api import GetSystemMetrics

def get_resized_for_display_img(img):
    screen_w, screen_h = GetSystemMetrics(0), GetSystemMetrics(1)
    print("screen size",screen_w, screen_h)
    h,w,channel_nbr = img.shape
    # img get w of screen and adapt h
    h = h * (screen_w / w)
    w = screen_w
    if h > screen_h: #if img h still too big
        # img get h of screen and adapt w
        w = w * (screen_h / h)
        h = screen_h
    w, h = w*0.9, h*0.9 # because you don't want it to be that big, right ?
    w, h = int(w), int(h) # you need int for the cv2.resize
    return cv2.resize(img, (w, h))

Try this code

img = cv2.resize(img,(1280,800))

Try with this code:

from PIL import Image

Image.fromarray(image).show()