Open an image using URI in Android's default gallery image viewer
AndroidAndroid ImageAndroid Problem Overview
I have extracted image uri, now I would like to open image with Android's default image viewer. Or even better, user could choose what program to use to open the image. Something like File Explorers offer you if you try to open a file.
Android Solutions
Solution 1 - Android
Accepted answer was not working for me,
What had worked:
Intent intent = new Intent();
intent.setAction(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.parse("file://" + "/sdcard/test.jpg"), "image/*");
startActivity(intent);
Solution 2 - Android
If your app targets Android N (7.0) and above, you should not use the answers above (of the "Uri.fromFile" method), because it won't work for you.
Instead, you should use a ContentProvider.
For example, if your image file is in external folder, you can use this (similar to the code I've made here) :
File file = ...;
final Intent intent = new Intent(Intent.ACTION_VIEW)//
.setDataAndType(VERSION.SDK_INT >= VERSION_CODES.N ?
FileProvider.getUriForFile(this,getPackageName() + ".provider", file) : Uri.fromFile(file),
"image/*").addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
manifest:
<provider
android:name="androidx.core.content.FileProvider"
android:authorities="${applicationId}.provider"
android:exported="false"
android:grantUriPermissions="true">
<meta-data
android:name="android.support.FILE_PROVIDER_PATHS"
android:resource="@xml/provider_paths"/>
</provider>
res/xml/provider_paths.xml :
<?xml version="1.0" encoding="utf-8"?>
<paths>
<!--<external-path name="external_files" path="."/>-->
<external-path
name="files_root"
path="Android/data/${applicationId}"/>
<external-path
name="external_storage_root"
path="."/>
</paths>
If your image is in the private path of the app, you should create your own ContentProvider, as I've created "OpenFileProvider" on the link.
Solution 3 - Android
Ask myself, answer myself also:
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("content://media/external/images/media/16"))); /** replace with your own uri */
It will also ask what program to use to view the file.
Solution 4 - Android
Try use it:
Uri uri = Uri.fromFile(entry);
Intent intent = new Intent(android.content.Intent.ACTION_VIEW);
String mime = "*/*";
MimeTypeMap mimeTypeMap = MimeTypeMap.getSingleton();
if (mimeTypeMap.hasExtension(
mimeTypeMap.getFileExtensionFromUrl(uri.toString())))
mime = mimeTypeMap.getMimeTypeFromExtension(
mimeTypeMap.getFileExtensionFromUrl(uri.toString()));
intent.setDataAndType(uri,mime);
startActivity(intent);
Solution 5 - Android
Based on Vikas answer but with a slight modification: The Uri is received by parameter:
private void showPhoto(Uri photoUri){
Intent intent = new Intent();
intent.setAction(Intent.ACTION_VIEW);
intent.setDataAndType(photoUri, "image/*");
startActivity(intent);
}
Solution 6 - Android
This thing might help if your working with android N and below
File file=new File(Environment.getExternalStorageDirectory()+"/directoryname/"+filename);
Uri path= FileProvider.getUriForFile(MainActivity.this,BuildConfig.APPLICATION_ID + ".provider",file);
Intent intent=new Intent(Intent.ACTION_VIEW);
intent.setDataAndType(path,"image/*");
intent.setFlags(FLAG_GRANT_READ_URI_PERMISSION | FLAG_GRANT_WRITE_URI_PERMISSION); //must for reading data from directory
Solution 7 - Android
A much cleaner, safer answer to this problem (you really shouldn't hard code Strings):
public void openInGallery(String imageId) {
Uri uri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI.buildUpon().appendPath(imageId).build();
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(intent);
}
All you have to do is append the image id to the end of the path for the EXTERNAL_CONTENT_URI. Then launch an Intent with the View action, and the Uri.
The image id comes from querying the content resolver.
Solution 8 - Android
All the above answers not opening image.. when second time I try to open it show the gallery not image.
I got solution from mix of various SO answers..
Intent galleryIntent = new Intent(Intent.ACTION_VIEW, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
galleryIntent.setDataAndType(Uri.fromFile(mImsgeFileName), "image/*");
galleryIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(galleryIntent);
This one only worked for me..
Solution 9 - Android
The problem with showing a file using Intent.ACTION_VIEW
, is that if you pass the Uri
parsing the path. Doesn't work in all cases. To fix that problem, you need to use:
Uri.fromFile(new File(filePath));
Instead of:
Uri.parse(filePath);
Edit
Here is my complete code:
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.fromFile(new File(mediaFile.filePath)), mediaFile.getExtension());
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
Info
MediaFile
is my domain class to wrap files from database in objects.
MediaFile.getExtension()
returns a String
with Mimetype
for the file extension. Example: "image/png"
Aditional code: needed for showing any file (extension)
import android.webkit.MimeTypeMap;
public String getExtension () {
MimeTypeMap myMime = MimeTypeMap.getSingleton();
return myMime.getMimeTypeFromExtension(MediaFile.fileExtension(filePath));
}
public static String fileExtension(String path) {
if (path.indexOf("?") > -1) {
path = path.substring(0, path.indexOf("?"));
}
if (path.lastIndexOf(".") == -1) {
return null;
} else {
String ext = path.substring(path.lastIndexOf(".") + 1);
if (ext.indexOf("%") > -1) {
ext = ext.substring(0, ext.indexOf("%"));
}
if (ext.indexOf("/") > -1) {
ext = ext.substring(0, ext.indexOf("/"));
}
return ext.toLowerCase();
}
}
Let me know if you need more code.
Solution 10 - Android
I use this it works for me
Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent,
"Select Picture"), 1);
Solution 11 - Android
My solution using File Provider
private void viewGallery(File file) {
Uri mImageCaptureUri = FileProvider.getUriForFile(
mContext,
mContext.getApplicationContext()
.getPackageName() + ".provider", file);
Intent view = new Intent();
view.setAction(Intent.ACTION_VIEW);
view.setData(mImageCaptureUri);
List < ResolveInfo > resInfoList =
mContext.getPackageManager()
.queryIntentActivities(view, PackageManager.MATCH_DEFAULT_ONLY);
for (ResolveInfo resolveInfo: resInfoList) {
String packageName = resolveInfo.activityInfo.packageName;
mContext.grantUriPermission(packageName, mImageCaptureUri, Intent.FLAG_GRANT_WRITE_URI_PERMISSION | Intent.FLAG_GRANT_READ_URI_PERMISSION);
}
view.addFlags(Intent.FLAG_GRANT_WRITE_URI_PERMISSION);
Intent intent = new Intent();
intent.setAction(Intent.ACTION_VIEW);
intent.setDataAndType(mImageCaptureUri, "image/*");
mContext.startActivity(intent);
}
Solution 12 - Android
Almost NO chance to use photo or gallery application(might exist one), but you can try the content-viewer.
Please checkout another answer to similar question here
Solution 13 - Android
My solution
Intent intent = new Intent();
intent.setAction(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.fromFile(new File(Environment.getExternalStorageDirectory().getPath()+"/your_app_folder/"+"your_picture_saved_name"+".png")), "image/*");
context.startActivity(intent);
Solution 14 - Android
The uri must be content uri not file uri, You can get contentUri by FileProvider as
Uri contentUri = FileProvider.getUriForFile(getContext(),"com.github.myApp",curFile);
Don't forget adding provider in Manifest file.
<provider
android:name="androidx.core.content.FileProvider"
android:authorities="com.github.myApp"
android:exported="false"
android:grantUriPermissions="true">
<meta-data
android:name="android.support.FILE_PROVIDER_PATHS"
android:resource="@xml/provider_paths" />
</provider>