Omitting the first line from any Linux command output

I have a requirement where i'd like to omit the 1st line from the output of ls -latr "some path" Since I need to remove total 136 from the below output

So I wrote ls -latr /home/kjatin1/DT_901_linux//autoInclude/system | tail -q which excluded the 1st line, but when the folder is empty it does not omit it. Please tell me how to omit 1st line in any linux command output

The tail program can do this:

ls -lart | tail -n +2

The -n +2 means “start passing through on the second line of output”.

Pipe it to awk:

awk '{if(NR>1)print}'

or sed

sed -n '1!p'

ls -lart | tail -n +2 #argument means starting with line 2

This is a quick hacky way: ls -lart | grep -v ^total.

Basically, remove any lines that start with "total", which in ls output should only be the first line.

A more general way (for anything):

ls -lart | sed "1 d"

sed "1 d" means only print everything but first line.

You can use awk command:

For command output use pipe: | awk 'NR>1'

For output of file: awk 'NR>1' file.csv