Use [`unravel_index`][1]:

    numpy.unravel_index(A.argmin(), A.shape)


  [1]: http://docs.scipy.org/doc/numpy/reference/generated/numpy.unravel_index.html

[Corrected typo]

Another simple solution is 

    ri, ci = A.argmin()//A.shape[1], A.argmin()%A.shape[1]

As numpy.argmin returns the index reading in row-major order

---
Yes, you are right, it was a typo, which worked for square matrix

If I have an enum object, is it considered a primitive or a reference?

Are Java enums considered primitive or reference types?

the question is fairly simple and technical:

    var it_works = false;
    
    $.post(&quot;some_file.php&quot;, &#39;&#39;, function(data) {
    										
         it_works = true;
    
    });

    alert(it_works); # false (yes, that &#39;alert&#39; has to be here and not inside $.post itself)

What I want to achieve is:

    alert(it_works); # true

Is there a way to do that? If not can `$.post()` return a value to be applied to `it_works`?

JavaScript: Global variables after Ajax requests

How can I know the (row, column) index of the minimum of a numpy array/matrix?

For example, if `A = array([[1, 2], [3, 0]])`, I want to get `(1, 1)`

Thanks!

Numpy minimum in (row, column) format

How can I know the (row, column) index of the minimum of a numpy array/matrix?
For example, if <code>A = array([[1, 2], [3, 0]])</code>, I want to get <code>(1, 1)</code>
Thanks!

I&#39;m looking for a way to update dict dictionary1 with the contents of dict update wihout overwriting levelA

    dictionary1={&#39;level1&#39;:{&#39;level2&#39;:{&#39;levelA&#39;:0,&#39;levelB&#39;:1}}}
    update={&#39;level1&#39;:{&#39;level2&#39;:{&#39;levelB&#39;:10}}}
    dictionary1.update(update)
    print dictionary1
    {&#39;level1&#39;: {&#39;level2&#39;: {&#39;levelB&#39;: 10}}}

I know that update deletes the values in level2 because it&#39;s updating the lowest key level1.

How could I tackle this, given that dictionary1 and update can have any length?


Update value of a nested dictionary of varying depth

I have a list of objects appended from a mysql database and contain spaces. I wish to remove the spaces such as below, but the code im using doesnt work?

    hello = [&#39;999 &#39;,&#39; 666 &#39;]
    
    k = []
    
    for i in hello:
        str(i).replace(&#39; &#39;,&#39;&#39;)
        k.append(i)
    
    print k

Python: Removing spaces from list objects

I am using Python 2.6.5. My code requires the use of the &quot;more than or equal to&quot; sign. Here it goes:  

    &gt;&gt;&gt; s = u&#39;\u2265&#39;
    &gt;&gt;&gt; print s
    &gt;&gt;&gt; ≥
    &gt;&gt;&gt; print &quot;{0}&quot;.format(s)
    Traceback (most recent call last):
         File &quot;&lt;input&gt;&quot;, line 1, in &lt;module&gt; 
    UnicodeEncodeError: &#39;ascii&#39; codec can&#39;t encode character u&#39;\u2265&#39;
      in position 0: ordinal not in range(128)`  

Why do I get this error? Is there a right way to do this? I need to use the `.format()` function.


Python: Using .format() on a Unicode-escaped string

I would like to change a name of specific fields in a model:

    class Foo(models.Model):
        name = models.CharField()
        rel  = models.ForeignKey(Bar)

should change to:

    class Foo(models.Model):
        full_name     = models.CharField()
        odd_relation  = models.ForeignKey(Bar)

What&#39;s the easiest way to do this using South?


Django - How to rename a model field using South?

I&#39;m interested in subclassing the built-in `int` type in Python (I&#39;m using v. 2.5), but having some trouble getting the initialization working.

Here&#39;s some example code, which should be fairly obvious.

    class TestClass(int):
        def __init__(self):
            int.__init__(self, 5)

However, when I try to use this I get:

    &gt;&gt;&gt; a = TestClass()
    &gt;&gt;&gt; a
    0

where I&#39;d expect the result to be `5`.

What am I doing wrong? Google, so far, hasn&#39;t been very helpful, but I&#39;m not really sure what I should be searching for

Subclassing int in Python

In Java, `Arrays.equals()` allows to easily compare the content of two basic arrays (overloads are available for all the basic types).

Is there such a thing in C#? Is there any &quot;magic&quot; way of comparing the content of two arrays in C#?


Easiest way to compare arrays in C#

I&#39;m trying to sort a multidimensional array by multiple keys, and I have no idea where to start. I looked at `uasort()`, but wasn&#39;t quite sure how to write a function for what I need. 

I need to sort by the `state`, then `event_type`, then `date_start`.

My array looks like this:

    [
        [&#39;ID&#39; =&gt; 1, &#39;title&#39; =&gt; &#39;Boring Meeting&#39;,  &#39;date_start&#39; =&gt; &#39;2010-07-30&#39;, &#39;event_type&#39; =&gt; &#39;meeting&#39;, &#39;state&#39; =&gt; &#39;new-york&#39;],
        [&#39;ID&#39; =&gt; 2, &#39;title&#39; =&gt; &#39;Find My Stapler&#39;, &#39;date_start&#39; =&gt; &#39;2010-07-22&#39;, &#39;event_type&#39; =&gt; &#39;meeting&#39;, &#39;state&#39; =&gt; &#39;new-york&#39;],
        [&#39;ID&#39; =&gt; 3, &#39;title&#39; =&gt; &#39;Mario Party&#39;,     &#39;date_start&#39; =&gt; &#39;2010-07-22&#39;, &#39;event_type&#39; =&gt; &#39;party&#39;,   &#39;state&#39; =&gt; &#39;new-york&#39;],
        [&#39;ID&#39; =&gt; 4, &#39;title&#39; =&gt; &#39;Duct Tape Party&#39;, &#39;date_start&#39; =&gt; &#39;2010-07-28&#39;, &#39;event_type&#39; =&gt; &#39;party&#39;,   &#39;state&#39; =&gt; &#39;california&#39;]
    ]

My desired result is:

    [
        [&#39;ID&#39; =&gt; 4, &#39;title&#39; =&gt; &#39;Duct Tape Party&#39;, &#39;date_start&#39; =&gt; &#39;2010-07-28&#39;, &#39;event_type&#39; =&gt; &#39;party&#39;,   &#39;state&#39; =&gt; &#39;california&#39;]
        [&#39;ID&#39; =&gt; 2, &#39;title&#39; =&gt; &#39;Find My Stapler&#39;, &#39;date_start&#39; =&gt; &#39;2010-07-22&#39;, &#39;event_type&#39; =&gt; &#39;meeting&#39;, &#39;state&#39; =&gt; &#39;new-york&#39;],
        [&#39;ID&#39; =&gt; 1, &#39;title&#39; =&gt; &#39;Boring Meeting&#39;,  &#39;date_start&#39; =&gt; &#39;2010-07-30&#39;, &#39;event_type&#39; =&gt; &#39;meeting&#39;, &#39;state&#39; =&gt; &#39;new-york&#39;],
        [&#39;ID&#39; =&gt; 3, &#39;title&#39; =&gt; &#39;Mario Party&#39;,     &#39;date_start&#39; =&gt; &#39;2010-07-22&#39;, &#39;event_type&#39; =&gt; &#39;party&#39;,   &#39;state&#39; =&gt; &#39;new-york&#39;],
    ]

Sort multidimensional array by multiple columns

I can generate a few lines of code that will do this but I&#39;m wondering if there&#39;s a nice clean Rubyesque way of doing this. In case I haven&#39;t been clear, what I&#39;m looking for is an array method that will return true if given (say) `[3,3,3,3,3]` or `[&quot;rabbits&quot;,&quot;rabbits&quot;,&quot;rabbits&quot;]` but will return false with `[1,2,3,4,5]` or `[&quot;rabbits&quot;,&quot;rabbits&quot;,&quot;hares&quot;]`.

Thanks

How do I test if all items in an array are identical?

Since it seems like the first thing people do is convert `arguments` into a real array, I&#39;m interested in why the Javascript language authors and implementers decided, and continue to think, that `arguments` should *not* be a real `Array`. I don&#39;t mean this as flamebait, I&#39;m sincerely interested in the thinking behind it. Since the function is naturally being called when you&#39;re in its body, I don&#39;t think it&#39;s because the objects `arguments` are referencing can change, like with some of the DOM results...

Why isn&#39;t a function&#39;s arguments object an array in Javascript?

I have an array that I want to iterate over and delete some of the elements. This doesn&#39;t work:

    a = [1, 2, 3, 4, 5]
    a.each do |x|
      next if x &lt; 3
      a.delete x
      # do something with x
    end
    a #=&gt; [1, 2, 4]

I want `a` to be `[1, 2]`. How can I get around this?

How can I use Array#delete while iterating over the array?

I want to make some unit-tests for my app, and I need to compare two arrays. Since `array.__eq__` returns a new array (so `TestCase.assertEqual` fails), what is the best way to assert for equality?


Currently I&#39;m using

    self.assertTrue((arr1 == arr2).all())

but I don&#39;t really like it

Best way to assert for numpy.array equality?

I am using numpy. I have a matrix with 1 column and N rows and I want to get an array from with N elements.

For example, if i have `M = matrix([[1], [2], [3], [4]])`, I want to get `A = array([1,2,3,4])`.

To achieve it, I use `A = np.array(M.T)[0]`. Does anyone know a more elegant way to get the same result?

Thanks!

Numpy matrix to array

`numpy.vectorize` takes a function f:a-&gt;b and turns it into g:a[]-&gt;b[].

This works fine when `a` and `b` are scalars, but I can&#39;t think of a reason why it wouldn&#39;t work with b as an `ndarray` or list, i.e. f:a-&gt;b[] and g:a[]-&gt;b[][]

For example:

    import numpy as np
    def f(x):
        return x * np.array([1,1,1,1,1], dtype=np.float32)
    g = np.vectorize(f, otypes=[np.ndarray])
    a = np.arange(4)
    print(g(a))
This yields:
    
    array([[ 0.  0.  0.  0.  0.],
           [ 1.  1.  1.  1.  1.],
           [ 2.  2.  2.  2.  2.],
           [ 3.  3.  3.  3.  3.]], dtype=object)

Ok, so that gives the right values, but the wrong dtype.  And even worse:

    g(a).shape

yields:

    (4,)

So this array is pretty much useless.  I know I can convert it doing:

    np.array(map(list, a), dtype=np.float32)


to give me what I want:

    array([[ 0.,  0.,  0.,  0.,  0.],
           [ 1.,  1.,  1.,  1.,  1.],
           [ 2.,  2.,  2.,  2.,  2.],
           [ 3.,  3.,  3.,  3.,  3.]], dtype=float32)

but that is neither efficient nor pythonic.  Can any of you guys find a cleaner way to do this?  

Thanks in advance!

Using Numpy Vectorize on Functions that Return Vectors

is there a builtin function of Python that does on `python.array` what [`argsort()`][1] does on a `numpy.array`?


  [1]: http://www.scipy.org/Numpy_Example_List_With_Doc#head-82d26af744a08992cf3422d6df9dc9e276e78263

Equivalent of Numpy.argsort() in basic python?

I would like to create a two dimensional numpy array of arrays that has a different number of elements on each row.  

Trying

    cells = numpy.array([[0,1,2,3], [2,3,4]])

gives an error

    ValueError: setting an array element with a sequence.



How to make a multidimension numpy array with a varying row size?

If I have a Python dictionary, how do I get the key to the entry which contains the minimum value?

I was thinking about something to do with the `min()` function...

Given the input:

    {320:1, 321:0, 322:3}

It would return `321`.


Get the key corresponding to the minimum value within a dictionary

I need to find the minimum cut on a graph. I&#39;ve been reading about flow networks, but all I can find are maximum flow algorithms such as Ford-Fulkerson, push-relabel, etc. Given the max flow-min cut theorem, is it possible to use one of those algorithms to find the minimum cut on a graph using a maximum flow algorithm? How?

The best information I have found so far is that if I find &quot;saturated&quot; edges i.e. edges where flow equals capacity, those edges correspond to the minimum cut. Is that true? It doesn&#39;t sound 100% right to me. It is true that all edges on the minimum cut will be saturated, but I believe there might also be saturated edges which are out of the minimum cut &quot;path&quot;.

How can I find the minimum cut on a graph using a maximum flow algorithm?

So I am trying to figure out how to take a range of numbers and scale the values down to fit a range.  The reason for wanting to do this is that I am trying to draw ellipses in a java swing jpanel.  I want the height and width of each ellipse to be in a range of say 1-30.  I have methods that find the minimum and maximum values from my data set, but I won&#39;t have the min and max until runtime.  Is there an easy way to do this?

How to scale down a range of numbers with a known min and max value

How can I find the index of the minimum item in a Python list of floats? If they were integers, I would simply do:

    minIndex = myList.index(min(myList))

However, with a list of floats I get the following error, I assume because float equality comparison is rather iffy.

    ValueError: 0.13417985135 is not in list

Now, I know that I could simply scroll through the list and compare each item to see whether it is &lt; (min + 0.0000000000001) and &gt; (min - 0.0000000000001), but that is kinda messy. Is there a more elegant (preferably built-in) way to find the index of the smallest item in a list of floats?

Content Type	Original Author	Original Content on Stackoverflow
Question	yassin	View Question on Stackoverflow
Solution 1 - Python	Philipp	View Answer on Stackoverflow
Solution 2 - Python	Nikesh Bajaj	View Answer on Stackoverflow

Numpy minimum in (row, column) format

Python Problem Overview

Python Solutions

Solution 1 - Python

Solution 2 - Python

JavaScript: Global variables after Ajax requests

Are Java enums considered primitive or reference types?

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