Numeric for loop in Django templates

DjangoDjango Templates

Django Problem Overview


How do I write a numeric for loop in a Django template? I mean something like

for i = 1 to n

Django Solutions


Solution 1 - Django

I've used a simple technique that works nicely for small cases with no special tags and no additional context. Sometimes this comes in handy

{% for i in '0123456789'|make_list %}
    {{ forloop.counter }}
{% endfor %}

Solution 2 - Django

{% with ''|center:n as range %}
{% for _ in range %}
    {{ forloop.counter }}
{% endfor %}
{% endwith %}

Solution 3 - Django

Unfortunately, that's not supported in the Django template language. There are a couple of suggestions, but they seem a little complex. I would just put a variable in the context:

...
render_to_response('foo.html', {..., 'range': range(10), ...}, ...)
...

and in the template:

{% for i in range %}
     ...
{% endfor %}

Solution 4 - Django

My take on this issue, i think is the most pythonic. Create a my_filters.py in your apps templatetags directory.

@register.filter(name='times') 
def times(number):
    return range(number)

Usage in your template:

{% load my_filters %}
{% for i in 15|times %}
    <li>Item</li>
{% endfor %}

Solution 5 - Django

You can pass a binding of

{'n' : range(n) }

to the template, then do

{% for i in n %}
...
{% endfor %}

Note that you'll get 0-based behavior (0, 1, ... n-1).

(Updated for Python3 compatibility)

Solution 6 - Django

Maybe like this?

{% for i in "x"|rjust:"100" %}
...
{% endfor %}

Solution 7 - Django

I'm just taking the popular answer a bit further and making it more robust. This lets you specify any start point, so 0 or 1 for example. It also uses python's range feature where the end is one less so it can be used directly with list lengths for example.

@register.filter(name='range')
def filter_range(start, end):
    return range(start, end)

Then in your template just include the above template tag file and use the following:

{% load myapp_filters %}

{% for c in 1|range:6 %}
    {{ c }}
{% endfor %}

Now you can do 1-6 instead of just 0-6 or hard coding it. Adding a step would require a template tag, this should cover more uses cases so it's a step forward.

Solution 8 - Django

You can pass :

{ 'n' : range(n) }

To use template :

{% for i in n %} ... {% endfor %}

Solution 9 - Django

I tried very hard on this question, and I find the best answer here: (from https://stackoverflow.com/questions/5242866/how-to-loop-7-times-in-the-django-templates)

You can even access the idx!

views.py:

context['loop_times'] = range(1, 8)

html:

{% for i in loop_times %}
        <option value={{ i }}>{{ i }}</option>
{% endfor %}

Solution 10 - Django

You don't pass n itself, but rather range(n) [the list of integers from 0 to n-1 included], from your view to your template, and in the latter you do {% for i in therange %} (if you absolutely insist on 1-based rather than the normal 0-based index you can use forloop.counter in the loop's body;-).

Solution 11 - Django

Just incase anyone else comes across this question… I've created a template tag which lets you create a range(...): http://www.djangosnippets.org/snippets/1926/

Accepts the same arguments as the 'range' builtin and creates a list containing
the result of 'range'.

Syntax: {% mkrange [start,] stop[, step] as context_name %}

For example: {% mkrange 5 10 2 as some_range %} {% for i in some_range %} {{ i }}: Something I want to repeat\n {% endfor %}

Produces: 5: Something I want to repeat 7: Something I want to repeat 9: Something I want to repeat

Solution 12 - Django

This method supports all the functionality of the standard range([start,] stop[, step]) function

<app>/templatetags/range.py

from django import template

register = template.Library()


@register.filter(name='range')
def _range(_min, args=None):
    _max, _step = None, None
    if args:
        if not isinstance(args, int):
            _max, _step = map(int, args.split(','))
        else:
            _max = args
    args = filter(None, (_min, _max, _step))
    return range(*args)

Usage:

{% load range %}

<p>stop 5
{% for value in 5|range %}
{{ value }}
{% endfor %}
</p>

<p>start 5 stop 10
{% for value in 5|range:10 %}
{{ value }}
{% endfor %}
</p>

<p>start 5 stop 10 step 2
{% for value in 5|range:"10,2" %}
{{ value }}
{% endfor %}
</p>

Output

<p>stop 5
0 1 2 3 4
</p>

<p>start 5 stop 10
5 6 7 8 9
</p>

<p>start 5 stop 10 step 2
5 7 9
</p>

Solution 13 - Django

You should use "slice" in template, a example like this:

in views.py

contexts = {
    'ALL_STORES': Store.objects.all(),
}

return render_to_response('store_list.html', contexts, RequestContext(request, processors=[custom_processor]))

in store_list.html:

<ul>
{% for store in ALL_STORES|slice:":10" %}
    <li class="store_item">{{ store.name }}</li>
{% endfor %}
</ul>

Solution 14 - Django

This essentially requires a range function. A Django feature ticket was raised (https://code.djangoproject.com/ticket/13088) for this but closed as "won't fix" with the following comment.

> My impression of this idea is that it is trying to lead to programming in the template. If you have a list of options that need to be rendered, they should be computed in the view, not in the template. If that's as simple as a range of values, then so be it.

They have a good point - Templates are supposed to be very simple representations of the view. You should create the limited required data in the view and pass to the template in the context.

Solution 15 - Django

{% for _ in ''|center:13 %}
    {{ forloop.counter }}
{% endfor %}

Solution 16 - Django

If the number is coming from a model, I found this to be a nice patch to the model:

def iterableQuantity(self):
    return range(self.quantity)

Solution 17 - Django

You can use: {% with ''|center: i as range %}

Solution 18 - Django

For those who are looking to simple answer, just needing to display an amount of values, let say 3 from 100 posts for example just add {% for post in posts|slice:"3" %} and loop it normally and only 3 posts will be added.

Solution 19 - Django

This shows 1 to 20 numbers:

{% for i in "x"|rjust:"20"|make_list %}
 {{ forloop.counter }}
{% endfor %}

also this can help you: (count_all_slider_objects come from views)

{% for i in "x"|rjust:count_all_slider_objects %}
  {{ forloop.counter }}
{% endfor %}

or

  {% with counter=count_all_slider_objects %}
    {% if list_all_slider_objects %}
      {%  for slide in list_all_slider_objects %}
        {{forloop.counter|add:"-1"}}
        {% endfor%}
      {% endif %}
    {% endwith %}

Solution 20 - Django

You can pass range(n) instead of n in the context in views.py. This will give you an iterable list.

context['range']= range(n)

Then you can iterate in your template this way:

{% for i in range %}
   <!-- your code -->
{% endfor %}

Solution 21 - Django

{% for i in range(10) %}
   {{ i }}

{% endfor %}

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