mysqli fetch_all() not a valid function?

PhpMysqli

Php Problem Overview


Thanks to the answers I have figured out that I am unable to use fetch_all() because i am using PHP 5.2.17 - fetch_assoc with while loop worked.


The function I am using fetch_all is coming back with this error:

> Fatal error: Call to undefined method mysqli_result::fetch_all() in

$mysqli = new mysqli($host, $username, $password, $database);
$query = "LONG QUERY that works, tested in phpmyadmin"
$result = $mysqli->query($query);
$result->fetch_all(); or  $mysqli->fetch_all() tried both
mysqli_fetch_all() was already tried.
$mysqli->close(); 

I am able to connect to the DB and I have pulled single rows. When I place the query in PHPMYADMIN I get 5 rows back.

Does this function even work? Is there a way I can place my data into an assoc array on my own?

Php Solutions


Solution 1 - Php

This function is available since PHP 5.3.0. Possibly your version is older. Use fetch_assoc() instead.

while ($row = $result->fetch_assoc()) {
    // do what you need.
}

Solution 2 - Php

mysqli::fetch_all() needs mysqlnd driver to be installed before you can use it.

Solution 3 - Php

The typical way to construct an associative array is in a while loop:

$results_array = array();
$result = $mysqli->query($query);
while ($row = $result->fetch_assoc()) {
  $results_array[] = $row;
}

Solution 4 - Php

Issue seems to be 'mysqli' and 'mysqlnd' are not working together. I had the same issue in cpanel

Steps:

  1. Go to CPanel dashboard

  2. Go to 'Select PHP Version', you should see a bunch of checkboxes

  3. Set PHP version (5.4 or above)

  4. Uncheck the 'mysqli' extension and check both 'mysqlind' and 'nd_mysqli'

Apparently 'nd_mysqli' is 'mysqli' but configured to work with 'mysqlind' and to make it work you have to uncheck 'mysqli' due to settings conflicts.

Following answer I found here helped me.

Solution 5 - Php

Please be careful about using fetch_all():

http://www.php.net/manual/en/mysqli-result.fetch-all.php#88031

Read the note about mysqldn requirement.

Solution 6 - Php

As an addition to Fabrizios answer, please consider building up your array with a loop:

$array = array();
while($row = $result->fetch_assoc())
    $array[] = $row;

Solution 7 - Php

If you don't want to iterate using Karolis' answer, use

     while($row = mysqli_fetch_array($result,MYSQLI_ASSOC))
    {
       $rows[] = $row;
    }

to achieve the same result as

$rows = mysqli_fetch_all($result, MYSQLI_ASSOC);

You may change constant to MYSQLI_NUM or MYSQLI_BOTH. This optional parameter are constants indicating what type of array should be produced from the current row data.

Notice that mysqli_fetch_array($result,MYSQLI_ASSOC ) behaves identically to the mysqli_fetch_assoc() function, while mysqli_fetch_array($result,MYSQLI_NUM) will behave identically to the mysqli_fetch_row() function. The final option MYSQLI_BOTH will create a single array with the attributes of both. http://php.net/manual/en/mysqli-result.fetch-array.php

Solution 8 - Php

I had 5.6 but didn't work for me anyway. By enabling the mysqlnd driver it worked for me. Just write apt-get install php5-mysqlnd then restart php and you're good to go!

Solution 9 - Php

PHP Fatal error: Call to undefined function mysqli_fetch_all()

$rows = mysqli_fetch_all($result, MYSQLI_ASSOC);//not work

change to:php 5.3 or

$query = "SELECT * FROM `user_counter` ORDER BY id DESC LIMIT 20";
$result =  mysqli_query($connection, $query) or die
("Error in Selecting " . mysqli_error($connection));
$rows = array();
while ($row = $result->fetch_assoc()) {
    $rows[] = $row;
}
echo json_encode($rows);

Solution 10 - Php

Just to add an additional note about the mysqlnd driver: It also has to have the mysqli API extension installed. Without the extension, fetch_all() still won't be available. I found this while troubleshooting why my code worked on one server but not another, both PHP > 5.3. Use phpinfo() to verify the installed extensions.

Solution 11 - Php

function runQuery($query) {
		$result = mysqli_query($this->conn,$query);
                $resultset  = array(); //you need to define array
                         while($row=$result->fetch_assoc()) {
                              $resultset[] = $row; //then insert result into the array
			}		
			if(!empty($resultset))
			{

			return $resultset;}
			else{return 'empty';};
	}

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionPhilView Question on Stackoverflow
Solution 1 - PhpKarolisView Answer on Stackoverflow
Solution 2 - PhpAmir Hassan AzimiView Answer on Stackoverflow
Solution 3 - PhpMichael BerkowskiView Answer on Stackoverflow
Solution 4 - PhpjavatarView Answer on Stackoverflow
Solution 5 - PhpFabrizio D'AmmassaView Answer on Stackoverflow
Solution 6 - PhpSascha GalleyView Answer on Stackoverflow
Solution 7 - PhpWilsonView Answer on Stackoverflow
Solution 8 - PhpCocoView Answer on Stackoverflow
Solution 9 - PhpsirmagidView Answer on Stackoverflow
Solution 10 - PhpChris LangtiwView Answer on Stackoverflow
Solution 11 - PhpRicky HarerriView Answer on Stackoverflow