MySQL "WITH" clause

MysqlSqlCommon Table-Expression

Mysql Problem Overview


I'm trying to use MySQL to create a view with the "WITH" clause

WITH authorRating(aname, rating) AS
   SELECT aname, AVG(quantity)
   FROM book
   GROUP BY aname

But it doesn't seem like MySQL supports this.

I thought this was pretty standard and I'm sure Oracle supports this. Is there anyway to force MySQL to use the "WITH" clause? I've tried it with the MyISAM and innoDB engine. Both of these don't work.

Mysql Solutions


Solution 1 - Mysql

Update: MySQL 8.0 is finally getting the feature of common table expressions, including recursive CTEs.

Here's a blog announcing it: http://mysqlserverteam.com/mysql-8-0-labs-recursive-common-table-expressions-in-mysql-ctes/

Below is my earlier answer, which I originally wrote in 2008.


MySQL 5.x does not support queries using the WITH syntax defined in SQL-99, also called Common Table Expressions.

This has been a feature request for MySQL since January 2006: http://bugs.mysql.com/bug.php?id=16244

Other RDBMS products that support common table expressions:

Solution 2 - Mysql

You might be interested in something like this:

select * from (
    select * from table
) as Subquery

Solution 3 - Mysql

You've got the syntax right:

WITH AuthorRating(AuthorName, AuthorRating) AS
   SELECT aname         AS AuthorName,
          AVG(quantity) AS AuthorRating
   FROM Book
   GROUP By Book.aname

However, as others have mentioned, MySQL does not support this command. WITH was added in SQL:1999; the newest version of the SQL standard is SQL:2008. You can find some more information about databases that support SQL:1999's various features on Wikipedia.

MySQL has traditionally lagged a bit in support for the SQL standard, whereas commercial databases like Oracle, SQL Server (recently), and DB2 have followed them a bit more closely. PostgreSQL is typically pretty standards compliant as well.

You may want to look at MySQL's roadmap; I'm not completely sure when this feature might be supported, but it's great for creating readable roll-up queries.

Solution 4 - Mysql

Oracle does support WITH.

It would look like this.

WITH emps as (SELECT * FROM Employees)
SELECT * FROM emps WHERE ID < 20
UNION ALL
SELECT * FROM emps where Sex = 'F'

@ysth WITH is hard to google because it's a common word typically excluded from searches.

You'd want to look at the SELECT docs to see how subquery factoring works.

I know this doesn't answer the OP but I'm cleaning up any confusion ysth may have started.

Solution 5 - Mysql

Building on the answer from @Mosty Mostacho, here's how you might do something equivalent in MySQL,for a specific case of determining what entries don't exist in a table, and are not in any other database.

select col1 from (
   select 'value1' as col1 union
   select 'value2' as col1 union
   select 'value3' as col1
) as subquery
left join mytable as mytable.mycol = col1
where mytable.mycol is null
order by col1

You may want to use a text editor with macro capabilities to convert a list of values to the quoted select union clause.

Solution 6 - Mysql

MariaDB is now supporting WITH. MySQL for now is not. https://mariadb.com/kb/en/mariadb/with/

Solution 7 - Mysql

Have you ever tried Temporary Table? This solved my convern:

create temporary table abc (
column1 varchar(255)
column2 decimal
);
insert into abc
select ...
or otherwise
insert into abc
values ('text', 5.5), ('text2', 0815.8);

Then you can use this table in every select in this session:

select * from abc inner join users on ...;

Solution 8 - Mysql

   WITH authorRating as (select aname, rating from book)
   SELECT aname, AVG(quantity)
   FROM authorRating
   GROUP BY aname

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionBill CollinsView Question on Stackoverflow
Solution 1 - MysqlBill KarwinView Answer on Stackoverflow
Solution 2 - MysqlMosty MostachoView Answer on Stackoverflow
Solution 3 - MysqlEd AltorferView Answer on Stackoverflow
Solution 4 - MysqlMark BradyView Answer on Stackoverflow
Solution 5 - MysqlReubenView Answer on Stackoverflow
Solution 6 - MysqlMoshe LView Answer on Stackoverflow
Solution 7 - MysqlClausView Answer on Stackoverflow
Solution 8 - MysqlMantas DainysView Answer on Stackoverflow