MySQL Orderby a number, Nulls last
MysqlSql Order-ByMysql Problem Overview
Currently I am doing a very basic OrderBy in my statement.
SELECT * FROM tablename WHERE visible=1 ORDER BY position ASC, id DESC
The problem with this is that NULL entries for 'position' are treated as 0. Therefore all entries with position as NULL appear before those with 1,2,3,4. eg:
NULL, NULL, NULL, 1, 2, 3, 4
Is there a way to achieve the following ordering:
1, 2, 3, 4, NULL, NULL, NULL.
Mysql Solutions
Solution 1 - Mysql
MySQL has an undocumented syntax to sort nulls last. Place a minus sign (-) before the column name and switch the ASC to DESC:
SELECT * FROM tablename WHERE visible=1 ORDER BY -position DESC, id DESC
It is essentially the inverse of position DESC placing the NULL values last but otherwise the same as position ASC.
A good reference is here <http://troels.arvin.dk/db/rdbms#select-order_by>
Solution 2 - Mysql
I found this to be a good solution for the most part:
SELECT * FROM table ORDER BY ISNULL(field), field ASC;
Solution 3 - Mysql
NULL LAST
SELECT * FROM table_name ORDER BY id IS NULL, id ASC
Solution 4 - Mysql
Something like
SELECT * FROM tablename where visible=1 ORDER BY COALESCE(position, 999999999) ASC, id DESC
Replace 999999999 with what ever the max value for the field is
Solution 5 - Mysql
You can swap out instances of NULL with a different value to sort them first (like 0 or -1) or last (a large number or a letter)...
SELECT field1, IF(field2 IS NULL, 9999, field2) as ordered_field2
FROM tablename
WHERE visible = 1
ORDER BY ordered_field2 ASC, id DESC
Solution 6 - Mysql
Try using this query:
SELECT * FROM tablename
WHERE visible=1
ORDER BY
CASE WHEN position IS NULL THEN 1 ELSE 0 END ASC,id DESC
Solution 7 - Mysql
You can http://dev.mysql.com/doc/refman/5.0/en/comparison-operators.html#function_coalesce">coalesce</a> your NULLs in the ORDER BY statement:
select * from tablename
where <conditions>
order by
coalesce(position, 0) ASC,
id DESC
If you want the NULLs to sort on the bottom, try coalesce(position, 100000). (Make the second number bigger than all of the other position's in the db.)
Solution 8 - Mysql
For a DATE column you can use:
NULLS last:
ORDER BY IFNULL(`myDate`, '9999-12-31') ASC
Blanks last:
ORDER BY IF(`myDate` = '', '9999-12-31', `myDate`) ASC
Solution 9 - Mysql
SELECT * FROM tablename WHERE visible=1 ORDER BY CASE WHEN `position` = 0 THEN 'a' END , position ASC
Solution 10 - Mysql
To achieve following result :
1, 2, 3, 4, NULL, NULL, NULL.
USE syntax, place -(minus sign) before field name and use inverse order_type(Like: If you want order by ASC order then use DESC or if you want DESC order then use ASC)
SELECT * FROM tablename WHERE visible=1 ORDER BY -position DESC
Solution 11 - Mysql
This works well for me as well.
ORDER BY ISNULL(field), field = 0 ASC;
Returns 1 2 3 0 0 null null
Solution 12 - Mysql
This is working fine:
SELECT * FROM tablename ORDER BY position = 0, position ASC;
position
1
2
3
0
0
Solution 13 - Mysql
That's simple. You just need to order twice:
- first step, order NULLs
- second step, order your field.
SELECT * FROM table_name
ORDER BY ISNULL(field_name), field_name;
It works with any types, including JSON.
Solution 14 - Mysql
Why don't you order by NULLS LAST?
SELECT *
FROM tablename
WHERE visible = 1
ORDER BY position ASC NULLS LAST, id DESC