MySQL - Operand should contain 1 column(s)
MysqlSqlMysql Error-1241Mysql Problem Overview
While working on a system I'm creating, I attempted to use the following query in my project:
SELECT
topics.id,
topics.name,
topics.post_count,
topics.view_count,
COUNT( posts.solved_post ) AS solved_post,
(SELECT users.username AS posted_by,
users.id AS posted_by_id
FROM users
WHERE users.id = posts.posted_by)
FROM topics
LEFT OUTER JOIN posts ON posts.topic_id = topics.id
WHERE topics.cat_id = :cat
GROUP BY topics.id
":cat" is bound by my PHP code as I'm using PDO. 2 is a valid value for ":cat".
That query though gives me an error: "#1241 - Operand should contain 1 column(s)"
What stumps me is that I would think that this query would work no problem. Selecting columns, then selecting two more from another table, and continuing on from there. I just can't figure out what the problem is.
Is there a simple fix to this, or another way to write my query?
Mysql Solutions
Solution 1 - Mysql
Your subquery is selecting two columns, while you are using it to project one column (as part of the outer SELECT
clause). You can only select one column from such a query in this context.
Consider joining to the users
table instead; this will give you more flexibility when selecting what columns you want from users
.
SELECT
topics.id,
topics.name,
topics.post_count,
topics.view_count,
COUNT( posts.solved_post ) AS solved_post,
users.username AS posted_by,
users.id AS posted_by_id
FROM topics
LEFT OUTER JOIN posts ON posts.topic_id = topics.id
LEFT OUTER JOIN users ON users.id = posts.posted_by
WHERE topics.cat_id = :cat
GROUP BY topics.id
Solution 2 - Mysql
This error can also occur if you accidentally use commas instead of AND
in the ON
clause of a JOIN
:
JOIN joined_table ON (joined_table.column = table.column, joined_table.column2 = table.column2)
^
should be AND, not a comma
Solution 3 - Mysql
In my case, the problem was that I sorrounded my columns selection with parenthesis by mistake:
SELECT (p.column1, p.column2, p.column3) FROM table1 p WHERE p.column1 = 1;
And has to be:
SELECT p.column1, p.column2, p.column3 FROM table1 p WHERE p.column1 = 1;
Sounds silly, but it was causing this error and it took some time to figure it out.
Solution 4 - Mysql
This error can also occur if you accidentally use =
instead of IN
in the WHERE
clause:
FOR EXAMPLE:
WHERE product_id = (1,2,3);
Solution 5 - Mysql
COUNT( posts.solved_post ) AS solved_post,
(SELECT users.username AS posted_by,
users.id AS posted_by_id
FROM users
WHERE users.id = posts.posted_by)
Well, you can’t get multiple columns from one subquery like that. Luckily, the second column is already posts.posted_by
! So:
SELECT
topics.id,
topics.name,
topics.post_count,
topics.view_count,
posts.posted_by
COUNT( posts.solved_post ) AS solved_post,
(SELECT users.username AS posted_by_username
FROM users
WHERE users.id = posts.posted_by)
...
Solution 6 - Mysql
I got this error while executing a MySQL script in an Intellij console, because of adding brackets in the wrong place:
WRONG:
SELECT user.id
FROM user
WHERE id IN (:ids); # Do not put brackets around list argument
RIGHT:
SELECT user.id
FROM user
WHERE id IN :ids; # No brackets is correct
Solution 7 - Mysql
This error can also occur if you accidentally miss if
function name.
for example:
set v_filter_value = 100;
select
f_id,
f_sale_value
from
t_seller
where
f_id = 5
and (v_filter_value <> 0, f_sale_value = v_filter_value, true);
Got this problem when I missed putting if in the if
function!
Solution 8 - Mysql
Another place this error can happen in is assigning a value that has a comma outside of a string. For example:
SET totalvalue = (IFNULL(i.subtotal,0) + IFNULL(i.tax,0),0)
Solution 9 - Mysql
(SELECT users.username AS posted_by,
users.id AS posted_by_id
FROM users
WHERE users.id = posts.posted_by)
Here you using sub-query but this sub-query must return only one column. Separate it otherwise it will shows error.