MongoDB - The argument to $size must be an Array, but was of type: EOO / missing

MongodbMongodb QueryAggregation FrameworkIccube

Mongodb Problem Overview


Trying to create a MongoDB data source with icCube. The idea is to return the size of an array as a new field. Something like :

$project:
{ 
 "people": 1, 
 "Count myFieldArray" : {$size : "$myFieldArray" }
}

But I'm getting for some records the following error :

The argument to $size must be an Array, but was of type: EOO

Is there a way that size is 0 if the field is empty or not an array (getting rid of the error) ?

Mongodb Solutions


Solution 1 - Mongodb

You can use the $ifNull operator here. It seems the field is either not an array or not present by the given error:

{ "$project": {
    "people": 1,
    "Count": { 
        "$size": { "$ifNull": [ "$myFieldArray", [] ] }
    }
}}

Also you might want to check for the $type in your $match in case these do exist but are not an array.

Solution 2 - Mongodb

From MongoDB 3.2 and newer, you can use $isArray to check if your field is an array along with the $cond operator to return the field on evaluating with $isArray:

{ "$project": {
    "people": 1,
    "myFieldArrayCount": { 
        "$size": { 
            "$cond": [ 
                { "$isArray": "$myFieldArray" }, 
                "$myFieldArray", 
                []
            ]
        } 
    }
}}

Solution 3 - Mongodb

Alternative solution would be to eliminate the documents with nulls using

$match: {myFieldArray: { $elemMatch: { $exists: true } }}

Also, document fields which are used as arguments to $size by '$' reference (here: "$myFieldArray") must also be the part of projections.

$project:
{ 
 "people": 1,
 "myFieldArray":1,
 "Count myFieldArray" : {$size : "$myFieldArray" }
}

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionic3View Question on Stackoverflow
Solution 1 - MongodbNeil LunnView Answer on Stackoverflow
Solution 2 - MongodbchridamView Answer on Stackoverflow
Solution 3 - MongodbRohit Sai JangaView Answer on Stackoverflow