`hg clone http://your/repo -r branchname` should do the trick.

Benjamin&#39;s right. But is that really what you want to do? In particular, you&#39;ll only get the changesets needed to make up that branch, and nothing else - and that would, for example, prevent you from pulling changesets in from the trunk or other branches. You might well be better off just cloning the entire repository and then simply working in the branch you are interested in; this will let you keep your repository in sync with the one you&#39;re pulling from more easily. 

`hg clone &lt;URL&gt; -b BRANCHNAME` clone single branch, as requested

I know that this post is very old, but I had the same question. I found this trick:

    hg clone /path/to/your/repo -r 0
    hg pull -u -b branchname


I&#39;m using  Mercurial-4.0.2. In that we can specify the branch name by appending branch name with a **#** symbol in the clone url.
 
e.g.

    hg clone https://user@cloneurl/my_product#MY_BRANCH

    hg clone --verbose https://user@cloneurl/my_product#MY_BRANCH &quot;C:\myCode&quot;


mysql GROUP_CONCAT duplicates

I&#39;m developing a Web application and want to display a figure and its legend in different locations on the page. Which means I need to save the legend as a separate png file. Is this possible in Matplotlib in a more or less straightforward way? 

Get legend as a separate picture in Matplotlib

We have a repository with three named branches, I wanted to clone one of the branches. Is there a mercurial command to do that? If I provide the path (of branch) with hg clone I get 404 error.

Mercurial clone from a branch

<p>We have a repository with three named branches, I wanted to clone one of the branches. Is there a mercurial command to do that? If I provide the path (of branch) with hg clone I get 404 error.</p>


I have a number of changes that I committed to my local repository, but have not yet been pushed.  Since on a feature is taking longer than expected, I want to swap these changes onto a named branch before I push. How can I do this?

Mercurial move changes to a new branch

How can I undo my last accidentally commited (not pushed) change in Mercurial?

If possible, a way to do so with TortoiseHg would be prefered.

**Update**

In my concrete case I commited a changeset (not pushed). Then I pulled and updated from the server. With these new updates I decided, that my last commit is obsolete and I don&#39;t want to sync it. So it seems, that `hg rollback` is not exactly what I&#39;m searching for, because it would rollback the pull instead of my commit.

Mercurial undo last commit

Can anyone tell me what this Mercurial error means?

&gt; untracked file in working directory
&gt; differs from file in requested
&gt; revision

This occurred when doing an hg fetch: 

    C:\myapp&gt;hg fetch ssh://hg/myapp-v1
    pulling from ssh://hg/myapp-v1
    searching for changes
    adding changesets
    adding manifests
    adding file changes
    added 93 changesets with 693 changes to 78 files (+1 heads)
    updating to 797:0df7dbe7dc06
    196 files updated, 0 files merged, 196 files removed, 0 files unresolved
    merging with 704:edb7765768c6
    abort: untracked file in working directory differs from file in requested revision: &#39;a/b/c/d.java&#39;

From what I can tell this file (a/b/c/d.java) does not match any paths configured in .hgignore.  And this specific file is also identical in the two (myapp &amp; myapp-v1) repositories..   

I am not clear what this even means.  ??


Mercurial: &quot;untracked file in working directory differs from file in requested revision&quot;?

I have a Hg repo with 3 branches in it, but two of them are inactive (since I have already merged them into my default branch). *hg heads* shows 3 heads, one for each branch, even though *hg branches* shows 2 of those branches as &#39;inactive&#39;.

When I try to push my default branch (using *hg push --branch default http://...*) to another repo, the merge is aborted with the message &quot;abort: push creates new remote branches: &lt;branch name&gt;!&quot;

From the Hg push man pages, &quot;By default, push will not allow creation of new heads at the destination, since multiple heads would make it unclear which head to use. In this situation, it is recommended to pull and merge before pushing.&quot;

I&#39;ve already done that, but I still cant push --branch default without it getting aborted.

Any help is appreciated. Thanks!

How to only push to one branch in Hg?

I am working with Git repositories in the following way:

- I have the master repository and several remotes on the different production machines. 
- I am pushing the production code to the remotes and restart the services for the changes to take effect. 

I am about to switch from Git to Mercurial and I would like to know ahead how I can achieve something like that.

How can I add remote repositories in Mercurial?

I have a local branch tracking the remote/master branch. After running `git-pull` and `git-log`, the log will show all commits in the remote tracking branch as well as the current branch. However, because there were so many changes made to the remote branch, I need to see just the commits made to the current local branch.

What would be the Git command to use to only show commits for a specific branch?

Notes:

Configuration information:

    [branch &quot;my-branch&quot;]
      remote = origin
      merge = refs/heads/master


How do I run git log to see changes only for a specific branch?

Can someone explain a &quot;tracking branch&quot; as it applies to git?

Here&#39;s the definition from [git-scm.com][1]:

&gt; A &#39;tracking branch&#39; in Git is a local
&gt; branch that is connected to a remote
&gt; branch. When you push and pull on that
&gt; branch, it automatically pushes and
&gt; pulls to the remote branch that it is
&gt; connected with.
&gt; 
&gt; Use this if you always pull from the
&gt; same upstream branch into the new
&gt; branch, and if you don&#39;t want to use
&gt; &quot;git pull&quot; explicitly.

Unfortunately, being new to git and coming from SVN, that definition makes absolutely no sense to me.

I&#39;m reading through &quot;[The Pragmatic Guide to Git][2]&quot; (great book, by the way), and they seem to suggest that tracking branches are a good thing and that after creating your first remote (origin, in this case), you should set up your master branch to be a tracking branch, but it unfortunately doesn&#39;t cover *why a tracking branch is a good thing* or *what benefits you get by setting up your master branch to be a tracking branch of your origin repository*.

Can someone please enlighten me (in English)?

  [1]: https://git-scm.com/book/en/v2/Git-Branching-Remote-Branches
  [2]: http://www.pragprog.com/titles/pg_git/pragmatic-guide-to-git

What is a tracking branch?

So I&#39;ve done some work in the repository and when I&#39;m about to commit I realize that I&#39;m not currently on any branch.

This happens a lot when working with submodules and I am able to solve it, but the process is tedious and I&#39;ve been thinking that there must be an easier way to do this. 

Is there an easy way to get back on a branch, while keeping the changes?

Git: &quot;Not currently on any branch.&quot; Is there an easy way to get back on a branch, while keeping the changes?

If there is a repository that I only have `git://` access to (and would usually just push+pull), is there a way to rename branches in that repository in the same way that I would do locally with `git branch -m`?


Renaming branches remotely in Git

I was looking to find the difference between these four on Google and I expected there to be a huge amount of information on this, but there really wasn&#39;t any solid comparison between the four calls. 

I set about trying to compile a kind of basic at-a-glance look at the differences between these system calls and here&#39;s what I got. Is all this information correct/am I missing anything important ?

`Fork` : The fork call basically makes a duplicate of the current process, identical in almost every way (not everything is copied over, for example, resource limits in some implementations but the idea is to create as close a copy as possible).

The new process (child) gets a different process ID (PID) and has the PID of the old process (parent) as its parent PID (PPID). Because the two processes are now running exactly the same code, they can tell which is which by the return code of fork - the child gets 0, the parent gets the PID of the child. This is all, of course, assuming the fork call works - if not, no child is created and the parent gets an error code.

`Vfork` : The basic difference between vfork and fork is that when a new process is created with vfork(), the parent process is temporarily suspended, and the child process might borrow the parent&#39;s address space. This strange state of affairs continues until the child process either exits, or calls execve(), at which point the parent 
process continues. 

This means that the child process of a vfork() must be careful to avoid unexpectedly modifying variables of the parent process. In particular, the child process must not return from the function containing the vfork() call, and it must not call exit() (if it needs to exit, it should use _exit(); actually, this is also true for the child of a normal fork()). 

`Exec :` The exec call is a way to basically replace the entire current process with a new program. It loads the program into the current process space and runs it from the entry point. exec() replaces the current process with a the executable pointed by the function. Control never returns to the original program unless there is an exec() error.

`Clone :` Clone, as fork, creates a new process. Unlike fork, these calls allow the child process to share parts of its execution context with the calling process, such as the memory space, the table of file descriptors, and the table of signal handlers.

When the child process is created with clone, it executes the function application fn(arg). (This differs from fork, where execution continues in the child from the point of the original fork call.) The fn argument is a pointer to a function that is called by the child process at the beginning of its execution. The arg argument is passed to the fn function. 

When the fn(arg) function application returns, the child process terminates. The integer returned by fn is the exit code for the child process. The child process may also terminate explicitly by calling exit(2) or after receiving a fatal signal. 



Information gotten form : 

 - [https://stackoverflow.com/questions/1653340/exec-and-fork][1]
 - [http://www.allinterview.com/showanswers/59616.html][2]
 - [http://www.unixguide.net/unix/programming/1.1.2.shtml][3]
 - [http://linux.about.com/library/cmd/blcmdl2_clone.htm][4]


Thanks for taking the time to read this ! :)


  [1]: https://stackoverflow.com/questions/1653340/exec-and-fork
  [2]: http://www.allinterview.com/showanswers/59616.html
  [3]: http://www.unixguide.net/unix/programming/1.1.2.shtml
  [4]: http://linux.about.com/library/cmd/blcmdl2_clone.htm

The difference between fork(), vfork(), exec() and clone()

Consider this scenario:

```python
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import os

walk = os.walk(&#39;/home&#39;)

for root, dirs, files in walk:
    for pathname in dirs+files:
        print os.path.join(root, pathname)

for root, dirs, files in walk:
    for pathname in dirs+files:
        print os.path.join(root, pathname)
```

I know that this example is kinda redundant, but you should consider that we need to use the same `walk` data more than once. I&#39;ve a benchmark scenario and the use of same `walk` data is mandatory to get helpful results.

I&#39;ve tried `walk2 = walk` to clone and use in the second iteration, but it didn&#39;t work. The question is... How can I copy it? Is it ever possible?

Thank you in advance.

How to clone a Python generator object?

Question:

    package GoodQuestions;
    public class MyClass {	
    	MyClass() throws CloneNotSupportedException {
    		try {
    			throw new CloneNotSupportedException();
    		} catch(Exception e) {
    			e.printStackTrace();
    		}
    	}	
    
    	public static void main(String[] args) {	
    		try {
    			MyClass  obj = new MyClass();
    			MyClass obj3 = (MyClass)obj.clone();			
    		} catch (CloneNotSupportedException e) {
    			e.printStackTrace();
    		}
    	}
    }

Here class &#39;MyClass&#39; can able to clone its own object by calling the clone method in &#39;Object&#39; class.
When I try to clone the of this class(&#39;MyClass&#39;) in another class(&#39;TestSingleTon&#39;) in the same package &#39;GoodQuestions&#39; it is throwing the following compile time error.

***&#39;The method clone() from the type Object is not visible***&#39;

So here is the code it throwing the above error?

    package GoodQuestions;
    public class TestSingleTon {
    	public static void main(String[] args) {
    		MyClass  obj = new MyClass();
    		MyClass obj3 = obj.clone(); ---&gt; here is the compile error.
    	}
    }

The method clone() from object is not visible?

The below first logs `0`, and then logs `1`. How do I store a *copy* of the object, rather than a *reference* to it?

	debug.log(vi.details.segment);
	vi.nextSegment = vi.details;
	vi.nextSegment.segment++;
	debug.log(vi.details.segment);

Cloning an object in JavaScript

If I invoke `clone()` method on array of Objects of type A, how will it clone its elements? Will the copy be referencing to the same objects? Or will it call `(element of type A).clone()` for each of them?


Content Type	Original Author	Original Content on Stackoverflow
Question	Abidi	View Question on Stackoverflow
Solution 1 - Mercurial	Benjamin Pollack	View Answer on Stackoverflow
Solution 2 - Mercurial	Jay Maynard K5ZC	View Answer on Stackoverflow
Solution 3 - Mercurial	Lazy Badger	View Answer on Stackoverflow
Solution 4 - Mercurial	BlaX	View Answer on Stackoverflow
Solution 5 - Mercurial	apm	View Answer on Stackoverflow

Mercurial clone from a branch

Mercurial Problem Overview

Mercurial Solutions

Solution 1 - Mercurial

Solution 2 - Mercurial

Solution 3 - Mercurial

Solution 4 - Mercurial

Solution 5 - Mercurial

Get legend as a separate picture in Matplotlib

mysql GROUP_CONCAT duplicates

Attributions